MAT 222 week 2 Assignment Essay Example
Two- Variable Inequalities
Lynwood Wright
MAT 222 Week 2 Assignment
Instructor: Dr. Stacie Williams
December 14, 2013
In Elementary Algebra we have learned how to solve systems of equations. The solution to a system of linear equations is the point where the graphs of the lines intersect. The solution to a system of linear inequalities is every point in a region of the graph where the inequalities overlap, rather than the point of intersection of the lines (Slavin, 2001).
This week assignment required to solve problem 68 on page 539 (Dugopolski, 2012). I will be giving a detailed presentation on math required for the solution to this problem; the accompanying graph shows all of the possibilities for the number of refrigerators and the number of TVs that will fit into an 18-wheeler. The point-slope form of a linear equation to write the equation itself can now be used. These are the steps we take to solve our linear inequality. I will start with the point-slope form. Substitute slope form with (300, 0) for the x and y. Next we are going to use the distributive property and then add 330 to both sides and divided both sides by -3 and cancel out like terms.
The graph has a solid line rather than a dashed line indicating that points on the line itself are part of the solution set. This will be true anytime the inequality symbol has the equal to bar.
a) Write an inequality to describe this region.
p = y1-y2 /x1-x2 =
330 – 0 / 0-110 = -3/1 the slope is -3/1 or -3 y – y1 = p(x – x1) y– 330 = - 3 / 1(x-0) y= - 3x/1 + 330
-3x/1 +330 = y expression switch by place the y on the right hand side
-3x/-3 = y/-3 – 330/ -3 divide each equation by -3 and cancel out like terms
-3y = 1x + 110
-3y + 1x < 110
b) Will the truck hold 71 refrigerators and 118 TVs? In this problem I will be substituting 71 where the y is for refrigerators and 118 where the x is for TVs to determine if the truck
Lynwood Wright
MAT 222 Week 2 Assignment
Instructor: Dr. Stacie Williams
December 14, 2013
In Elementary Algebra we have learned how to solve systems of equations. The solution to a system of linear equations is the point where the graphs of the lines intersect. The solution to a system of linear inequalities is every point in a region of the graph where the inequalities overlap, rather than the point of intersection of the lines (Slavin, 2001).
This week assignment required to solve problem 68 on page 539 (Dugopolski, 2012). I will be giving a detailed presentation on math required for the solution to this problem; the accompanying graph shows all of the possibilities for the number of refrigerators and the number of TVs that will fit into an 18-wheeler. The point-slope form of a linear equation to write the equation itself can now be used. These are the steps we take to solve our linear inequality. I will start with the point-slope form. Substitute slope form with (300, 0) for the x and y. Next we are going to use the distributive property and then add 330 to both sides and divided both sides by -3 and cancel out like terms.
The graph has a solid line rather than a dashed line indicating that points on the line itself are part of the solution set. This will be true anytime the inequality symbol has the equal to bar.
a) Write an inequality to describe this region.
p = y1-y2 /x1-x2 =
330 – 0 / 0-110 = -3/1 the slope is -3/1 or -3 y – y1 = p(x – x1) y– 330 = - 3 / 1(x-0) y= - 3x/1 + 330
-3x/1 +330 = y expression switch by place the y on the right hand side
-3x/-3 = y/-3 – 330/ -3 divide each equation by -3 and cancel out like terms
-3y = 1x + 110
-3y + 1x < 110
b) Will the truck hold 71 refrigerators and 118 TVs? In this problem I will be substituting 71 where the y is for refrigerators and 118 where the x is for TVs to determine if the truck