b)posterior auricular c)auriculotemporal d)facial 8)Adductor pollicis is supplied by a)Superficial branch of ulnar nerve b)deep branch of ulnar nerve c)radial nerve d)median nerve 9)Ring Scotoma is seen in a)Retinitis Pigmentosa b) c) d) 10) In a patient‚ highest visual morbidity is seen in a)Nuclear cataract b)Intumescent cataract c)Posterior subcapsular d) 11)Klumpke paralysis is a)C5‚C6 B)C6‚C7 C)C8‚T1 D)T1‚T2 12)For the treatment of a patient with after cataract which
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CCE helps in reducing stress of students by - Identifying learning progress of students at regular time intervals on small portions of content. Employing a variety of remedial measures of teaching based on learning needs and potential of different students. Desisting from using negative comments on the learner’s performance. Encouraging learning through employment of a variety of teaching aids and techniques. Involving learners actively in the learning process. Recognizing and encouraging specific
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Samantha Meyer MATH 334 Reflection 4 Date of Observation: Monday‚ April 20‚ 2015 Grade Level Observed: 4th grade Math concept covered: Measuring capacity Mentor teacher’s name: Jessica Ross Intern (your) name: Samantha Meyer Reflection 4: Equity At Hawthorne Elementary on Monday‚ April 20th the students learned measurement capacity. The lesson started as a full class lesson at the carpet. Ms. Ross started the lesson reviewing previous topics of capacity because the students struggled with
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you reset the mean jar fill so that only 0.4% are underfilled? Question 2 (i) If random variables Y1 ‚ Y2 ‚ · · · ‚ Yn are independent with a common mean µ but 2 2 2 have variances σ1 ‚ σ2 ‚ · · · ‚ σn (which need not be the same) show that the sample mean ¯ Y is an unbiased estimator of µ with standard deviation 1 n 1 2 n 2 σi . i=1 (ii) A student takes independent measurements of an instrument but‚ owing to fatigue‚ 2 the variance of his measurements increases linearly
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Building Standards in Educational and Professional Testing Sample Paper State Bank of Pakistan Sample Paper SBP 1 Building Standards in Educational and Professional Testing VERBAL Question (1) following the passage refers to the numbered sentences in the passage. Answer the question by choosing the best alternative using logic and organization. 1 When television is good‚ nothing-not the theater‚ not the magazines or 2 newspapers-nothing is inferior. But when television
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It can create a remarkable contrast to the way women dress. The Hindu : Magazine / Columns : The colours of India www.hindu.com/mag/2005/04/10/stories/2005041000220300.htm Apr 10‚ 2005 - The colours of India. RAMACHANDRA GUHA. IN an essay of 1993 entitled "India as a Nation-State"‚ the historian Dharma Kumar took issue ... Colors of India - Term Paper - Aml116 - StudyMode.com www.studymode.com › Essays › Chemistry The Colors of India “Taste is colored not just by the gustatory properties
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MATHEMATICS SL INTERNAL ASSESSMENT TYPE 1 LACSAP’S FRACTIONS 10/11/2012 Tracy Braganza IB2T In mathematics‚ Lacsap’s fractions are based upon Pascal’s triangle. In this portfolio‚ the aim that was given was to consider a set of numbers that are presented in a symmetrical pattern‚ deduce a general statement and also to determine the limitations of the general statement that have been found. The answers in this portfolio will be attained with the help of a GDC calculator (GDC – TI84 Plus
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Solution to CBSE Question Paper 2013 Set 1 (Outside Delhi) Ans 1. In case of fixed capital‚ interest charged on drawings will be recorded on the debit side of Current Account of the Partners. Ans 2. Accumulated Profits are shared in the old ratio‚ in case of change in profit sharing ratio amongst existing partners. Ans 3. Interest is payable @ 6% p.a is charged on the amount remaining unpaid to the executor of deceased partner. Ans 4. Date Journal entry Particulars Workmen Compensation
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1)=1.25 v(1‚2)=1.25 ; v(2‚1) = 1/1.25 = 0.8 v(2‚3)=1+1=2 ; v(3‚2)=1/(1+1)=0.5 v(3‚4)=1+1=2 ; v(4‚3)=1/(1+1)=0.5 The smallest payment at time 1 = 2v(0‚1) + (-3) v(2‚1) + 5v(3‚2)v(2‚1) + 10v(4‚3)v(3‚2)v(2‚1) = 2(1.25) + (-3)(0.8) + 5 (0.5)(0.8) + 10(0.5)(0.5)(0.8) = 2.5-2.4+2+2 = 4.1 The smallest payment you would accept is 4.1. 2. Let K be the initial payment. a)9980.89 b)10117.4 3
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∴-4x = 1 1 ∴-4x = 1 -4 -4 ∴ x = - 1 (5) (3) [23] (3) (4) - = 53x + 2. 5x - 3. 5 52(2x – 1) 1 = 53x + 2. 5x - 3. 5 54x – 2 1 =5 3x + 2 + x – 3 + 1 – 4x + 2 = 52 1 = 25 1 1.1.2 3x + 3x + 2 3x + 1 = 3x + 3x .32 3x .3 1 = 3x(1 + 32) 3x.3 1 = 10 of/or 3 1 3 __ ___ ___ 1.1.3 4√ 8 + 3√ 18 – √ 32 ____ ____ _____ = 4√4 x 2 + 3√9 x 2 – √16 x 2 1 1_ 1_ 1_ = 8√2 + 9√2 – 4√2 _ = 13√2 Copyright reserved Please turn over Functional Mathematics/SG/P1 3 SCE – Memorandum DBE/2011
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