Engineering LABORATORY REPORT Ryan Bates 3675580 Group 13‚ Week 5 Date Performed: 26/03/12 Table of Contents 1. Direct Shear Test 1 1.1 Introduction 1 1.2 Test Procedure 1 1.3 Results and Discussion 2 1.4 Conclusion and Limitations 4 2. Triaxial Compression Test 5 2.1 Introduction 5 2.2 Test Procedure 5 2.3 Results and Discussion 5 2.4 Conclusion and Limitations 7 3. Consolidation Test 8 3.1 Introduction 8 3.2 Test Procedure 8 3.3 Results and Discussion
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HARWARD INTERNATIONAL COLLEGE BSBCUS402B – address customer needs Assessment 2 Student Name: GURDEEP SINGH Student ID: HIC-140705 Submitted to: SHAMIR TABLE OF CONTENT custmore service standards 3 Introduction 3 Defining custmore service standards 3 Policies and procedures of custmore service standards 4 Planning and implementation 6 Monitoring custmore service standards 7 Conclusion 8 Customer service standards Introduction We are used to such phrases
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Complete the first 2 parts and submit via schoology.comSerial: Episode 2Listening worksheet. Bring a printed copy to class along with your answers to the discussion questions (for an in-class discussion). Part I: Vocabulary: Look up each word below. Write a short definition‚ the part of speech‚ and then use each word in a sentence. 1. besmirch 2. humiliating 3. magnet school 4. prom 5. constraints 6. expectations 7. possessive 8. excerpts 9. pantheon 10. angst Part II: Listening Comprehension:
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Type 2 diabetes is the most common form of diabetes. In type 2 diabetes‚ either the pancreas does not make enough insulin (insulin is a hormone that helps glucose to enter cells) or muscle cells are unable to use insulin properly. As the result‚ a diabetic patient has very high blood sugar levels. When the sugar or glucose level is over 600 mg/dl‚ it’s dangerous to the diabetic’s health. Untreated diabetes affects the eyes‚ nerves‚ kidney‚ heart and blood vessels. Type 2 Diabetes is usually controlled
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be r so original area A= πr2 noe r is doubled and d is also doubled so new area A2=π(2r)2= 4A also new distance d2= 2d so new capacitance Cn=4A/ε(2d) = 2A/εd = 2C as only geometric changes are done but charges on plates will rtemain same so original energy stored in capacitor Uo= 0.5(Q2/C) new energy stored in capacitor Uf = 0.5(Q2/Cn) = 0.5[0.5(Q2/C)] = 0.5(Uo)= Uo/2 so new energy stored in capacitor Uf =Uo/2 final answer a charge of 2.00 uC flows into the plates of a capacitor when it is connected
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Case Analysis Unit 2 Assignment 2 Omar James Kaplan University The Case This case is an interesting one because it gets right into the core of the confliction between the proprieties of contractual agreement. This case is focused primarily on Osborne Development Corp. and the multiple defects customers are experiencing with their homes. These upset customers are suing this Corporation in attempts to collect reparations for the discrepancies faced. The homeowners who
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Multiple Choice 1) C 2) B 3) B‚ E 4) A‚ D 5) A 6) D 7) C 8) A 9) C‚ D‚ A 10) C‚ D 11) A 12) B‚ D 13) B 14) C 15) A‚ D 16) D 17) D 18) D 19) A 20) B Define the Key Terms Application: Generally‚ a function on any kind of computer or electronic device that is useful to the user‚ which can give the user a reason to want to own and use the device. More specifically‚ software that performs some useful function for a user. Computer network: A combination of many components
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1. Explain theory U in your own language. Provide example(s) from your own experience of knowledge Theory U is a leadership philosophy based on connecting to the source of our authentic self and that which wants to emerge through us. It is a new social field theory that equips us with a new consciousness and a new collective leadership capacity to meet challenges in a more conscious‚ intentional‚ and strategic way. The development of such a capacity will allow us to create a future of greater possibility
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FIN 502 – Personal Financial Planning Chapter 1 – Module 2 Time value of money * How to compare monetary amounts you pay or receive at different times * The arithmetic with which we convert money between periods‚ or calculate what rate of return is implied by a given set of cash flows Single Period – Rate of Return * N = amount of years * I% = x (what we’re trying to find) * PV = How much it’s worth today * FV = How much it’s worth at maturity date
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integer number of plants: 0‚ 1‚ 2‚.... Building Q plants costs each firm 3.5 × Q dollars. Each plant produces one unit of SOMA. If firm 1 builds Q1 plants and firm 2 builds Q2 plants‚ the market price p for one unit of SOMA will be 9 − (Q1 + Q2). For example‚ if firm 1 builds 2 plants and firm 2 builds 4 plants‚ the market price will be 9 − (2 + 4) = 3 per unit. At this price firm 1 will make a profit of 2 × 3 − 2 × 3.5 = −1 while firm 2 will make a profit of 4×3−4×3.5 = −2. Assume‚ no firm will build
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