Hertfordshire Business School Guide to Harvard Referencing This guide has been produced by the ASU in response to questions from Hertfordshire Business School (HBS) students about the important subject of accurate referencing. It is essential for you to reference your work thoroughly because what you write for HBS must be ’evidenced ’ - your discussion and arguments should consist mainly of academic theory and ’expert ’ practitioner experience. These two main sources (theory and practice) MUST
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CHM 2046 L Scheme of Analysis for Unknown 9A/9B “Fair Game” Unknowns * Cations: Na+‚ K+‚ NH4+‚ Ca2+‚ Mg(H2O)62+‚ Al(H2O)63+‚ Zn(H2O)62+‚ Cu(H2O)2+‚ Ag(H2O)+ * Anions: Cl-‚ NO3-‚ SO4-2‚ HSO4-‚ OH-‚ CO3-2‚ HCO3-‚ S-2 * Insoluble Salts: Ca(OH)2‚ CaCO3‚ CaSO4‚ Mg(OH)2‚ MgCO3‚ Ag2O‚ AgCl‚ Ag2S‚ CuO‚ CuCO3‚ CuS‚ Zn(OH)2‚ ZnCO3‚ ZnS * Alums: [Al(OH2)6]2(SO4)3∙6H2O‚ Na[Al(OH2)6](SO4)2∙6H2O‚ K[Al(OH2)6](SO4)2∙6H2O‚ NH4[Al(OH2)6]2(SO4)2∙6H2O * Hydrated Ions: Na2CO3∙10H2O‚ Na2SO4∙10H2O
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Mrs. S. is an 83 year old woman with multiple medical problems‚ including chronic obstructive pulmonary disease (for which she sees a pulmonologist)‚ atrial fibrillation and systolic heart failure (for which she sees a cardiologist)‚ hypertension‚ diabetes‚ depression‚ and mild dementia. She comes to your provider’s office today with a new list of medications. Her pulmonologist changed her inhaler from one brand/strength to another brand/strength‚ but she is not sure why. Her cardiologist took her
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Thebian play of Antigone has excited many debates over the years. The most prevalent being who exactly could be characterized as the tragic hero in the story. The argument that Antigone is the hero is deffinatly a strong one. There are many critics who believe that Creon‚ however‚ is the true protagonist of the play. In order to determine whether or not Creon is the tragic hero one must first examine what a tragic hero is. Aristotle states that a hero is neither purely innocent nor purely malevolent
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1) The similarities between visual and nonverbal communication are slightly varied but overall the same. They both operate on the interpreted meaning of the action of the picture. They both rely on the emotional or inferred response from the action or media. 2) I believe it to be completely ethical to make a website more engaging to increase sales or traffic. If a competitive edge can be found by adding more facets to the experience on the web site then the advantage lies with them. Implying that
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Week8 Ch 20: 5‚11‚15 5. Turn back to figure 20.1‚ which lists prices of various IBM options. Use the data in the figure to calculate the payoff and the profits for investments in each of the following February expiration options‚ assuming that the stock price on the expiration date is $195. a. Call option‚ X = $190. b. Put option‚ X =$190. c. Call option‚ X = $195. d. Put option‚ X =$195. e. Call option‚ X = $200. f. Put option‚ X =$200. St =$195 COST PAYOFF PROFIT CALL 6.75 195-190=5 -1
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GEOG 1106 Lab 11 Biomes Directions: Listed below are the lab questions to answer. 1. Use the Whittaker biome figure to determine the biome of the places listed below. Place Average Temperature oC Annual Precipitation (cm) Whittaker’s Biome La Selva‚ Costa Rica 22.1 403 Tropical Rain Forest Marietta‚ Ohio 12 105 Temperate Deciduous Forest Pasadena‚ CA 18.2 51.8 Woodland/Shrub land Temperate Ferron‚ UT 8.8 20.9 Grassland and Desert Tucson‚ AZ 21.1 21.9 Subtropical Desert Santa Rosa National Park
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spots were present for a compound‚ give Rf value for each component and state if the component was major or minor. | 100% hexane | 25% EtOAc in hexane | 10% EtOAc in hexane | Fluorene | 0.34 cm | 0.94 cm | 0.67 cm | 9 - fluorenol | 0.00 cm | 0.49 cm | 0.05 cm | 9 - fluorenone | 0.00 cm | 0.69 cm | 0.21 cm | 2. Explain how Rf values were generally affected by polarity of the solvent/eluent systems. As part of your answer‚ rank the solvent/eluent systems in order of decreasing polarity
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9 Sinusoidal Steady State Analysis Assessment Problems AP 9.1 [a] V = 170/−40◦ V [b] 10 sin(1000t + 20◦ ) = 10 cos(1000t − 70◦ ) . ·. I = 10/−70◦ A [c] I = 5/36.87◦ + 10/−53.13◦ = 4 + j3 + 6 − j8 = 10 − j5 = 11.18/−26.57◦ A [d] sin(20‚000πt + 30◦ ) = cos(20‚000πt − 60◦ ) Thus‚ V = 300/45◦ − 100/−60◦ = 212.13 + j212.13 − (50 − j86.60) = 162.13 + j298.73 = 339.90/61.51◦ mV AP 9.2 [a] v = 18.6 cos(ωt − 54◦ ) V [b] I = 20/45◦ − 50/ − 30◦ = 14.14 + j14.14 − 43.3 + j25 = −29.16 + j39.14 = 48.81/126
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Conflict of professional interest frequently arise in the working environment of an engineer. Discussion the statement and propose the appropriate solutions for overcoming the problems. Conflict is so common in today’s world that is full with sophistication and complexity. All of us are facing with some kind of conflicts in our life. We are frequently encountering conflict with our family members‚ friends‚ colleagues or even our bosses. Everybody‚ individuals‚ societies or countries are looking into
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