FIGURE Figure 1 Determining the Pace Factor V. FIELD MEASUREMENT DATA Trial(n) Line No. of Paces(x) Taped Distance (TP) Average No. of Paces (AP) Pace Factor (PF) 1 AB 75 55 m 72.7 paces approx. 73paces 0.75m/pace 2 BA 77 3 AB 74 4 BA 72 5 AB 70 6 BA 71 7 AB 70 Total 509 VI. CALCULATION Given: *Tabulated Data To compute for the Average Pace: AP = (x1+ x2+ x3+ x4+ x5+ x6+ x7)/n = (75+77+74+72+70+71+70)/7
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is a point lying on BC such that DE and AE are perpendicular to BC‚ then the angle between the plane ABC and the horizontal ground is A. ABD. B. ABE. C. ACD. D. AED. 4. In the figure‚ ABCDEFGH is a cube. If M and N are the mid-points of AB and EH respectively‚ then cos = A. . B. . C. . D. . 2009-CE-MATH 2 Q16 5. The angle of elevation of P from Q is 40‚ then the angle of depression of Q from Q is A. 40. B. 50. C. 130. D. 140. 2009-CE-MATH 2 Q47 6. In the figure
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half-adder is described by block diagram‚ truth table and logic equation for Sum and Carry. Fig. 7.5 Half Adder block diagram a 0 0 1 1 b 0 1 0 1 Cout 0 0 0 1 Sum 0 1 1 0 Cout = ab a→ b→ H.A. → Sum → Cout From the minterms in the truth table we get the following Boolean equations for the circuit. Sum = a’b + ab’ or a ⊕ b Circuit Diagram for half adder which produces a Sum and Cout p. 1 of 5 Functions of Combinational Circuits Full Adder The full-adder is described by block diagram
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points B‚ C‚ and E: ____________ 28. a plane containing lines p and q: ______________________ In the figure below‚ CD bisects AB at D. For each of the following‚ find the value of ‘x’ and the measure of the segment indicated. 29. x = __________ AB = ______ AD = 2x + 11 DB = 4x – 5 30. x = __________ AD = _______ AB = 5x – 4 DB = x + 1 The numbers given are the coordinates of two points on a number line. Find the distance between the
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Experiment 1: Quantitative assessment of Some Cellular Constituents Summary: Euglena gracilis are unicellular organisms in the Protist Kingdom. They are known to have both plant and animal characteristics. Although‚ Euglena cells contain a variety of cellular constituents‚ their cellular constituents should be presented in equal ratio. The objective of this experiment is to determine Euglena’s cellular components in cells and then to establish their cellular constituents by comparing the experimental
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Name Chantell Johnson BioScience 100A Online Virtual Lab Report: Part I Points: 120 (30/each) Due by: 12:00 PM PST on the second Saturday of class Directions 1. Type your answers‚ observations‚ and results in bold. 2. Save your report often as you fill it out‚ so as not to lose information. 3. Use the report form as a single document‚ do not turn in separate reports for each lab 4. Use the ‘Save As’ option to save your file as a Word file 5. Save your lab report with this name: Last name
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ACC 400 Week 2 Team Assignment-Text Assignments Exercise E7-2 & Problem Set B P7-2B.doc To Purchase this Tutorial Copy And Paste Below Link In Your Browser http://www.homework-bank.com/downloads/abs-497-complete-course-material/ For Any Information or Any Class Which you Did not find on Our Website ‚ Just Hit US Email On below address Email Address: hworkbank@gmail.com Visit Our Website : http://www.homework-bank.com/ ACC 400 Week 2 Team Assignment-Text Assignments Exercise E7-2 & Problem
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I. PROBLEM DEFINITION Policy Question: Given California’s current climate change regulations‚ which policy alternatives can California utilize to satisfy the rising demand for energy as well as meet 2030 emissions reduction goals? Problem Details and Background: With a population steadily growing at about 0.9% per year‚ California has the challenge of meeting energy demands while bringing greenhouse gas (GHG) emissions down (PPIC 2013). California emits 359 metric tons of energy related carbon dioxide
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Consider a typical member AB loaded as shown below: Tangent at B Mab A Tangent at A P1 a Elastic Curve L P2 b Mba B A GENERAL BEAM ELEMENT UNDER END MOMENTS AND LOADS General Slope deflection equations are. 2EI Mab = MFab + ( − 2θa − θb ) L 2EI Mba = MFba + ( − θa −2θb ) L equation (1) can be re-written as Mab = MFab + 2 M′ab + M′ba and → (1) → (2) → (3) where MFab = fixed end moment at A due to applied loads. EI M′ab = rotation contribution of near end A of member AB = − (2θa) L =− → (4) where
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type of discrepancy. Some of the common causes in this group are: • Subgroups may be present • Weak expression of A or B antigens in cases of leukemias or occasionally Hodgkin’s disease • Acquired B antigen; this is suspected when the group appears AB but the serum contains anti-B. A1 cells are notorious for such type of expression. This phenomenon is frequently encountered in patients of carcinoma colon and rectum. Group III Discrepancy This discrepancy between forward and reverse groupingusually
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