(energy change is negative because the reaction was exothermic): ΔH = -Q / number of moles = 2625 / 0.0125 = 210 kJmol-1 ‘Absolute Uncertainty’ = abs/unc ‘Percentage Uncertainty’ = %unc Uncertainty in mass = (%unc in density + %unc in volume) x mass = (0 + 0.5/25) x 25 = ±0.5 g Uncertainty in temperature change = abs/unc in Tmaximum + abs/unc in Tminimum = 0.5 + 0.5 = ±1 oC Uncertainty in number of moles = (%unc in concentration + %unc in volume) x number of moles = (0 + 0.5/25) x
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Ornopia ← Gequillana Steinbach ← 1. Blood typing/ RH typing ← Blood is often grouped according to the ABO blood typing system. This method breaks blood types down into four categories: ← Type A ← Type B ← Type AB ← Type O ← Blood typing is also done to tell whether or not you have a substance called Rh factor on the surface of your red blood cells. If you have this substance‚ you are considered Rh+ (positive). Those without it are considered Rh-
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have found this relationship between the sides of right triangles‚ since no texts written by him were found. In fact‚ we can’t even prove the guy lived. But the theorem a2 + b2= c2 got his name. Another Greek‚ Euclid‚ wrote about the theorem about 200 years later in his book called "Elements". There we also find the first known proof for the theorem. Now there are about 600 different proofs. Today the Pythagorean theorem plays an important part in many fields of mathematics. For example‚ it is the
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Term 1 - Summative Assessment Mathematics Question Paper Set - 1 Time: 3 to 3 ½ hours Max. Marks: 80 All questions are compulsory. The questions paper consists of 34 questions divided into four sections A‚ B‚ C and D. Section A comprises of 10 questions of 1 mark each‚ Section B comprises of 8 questions of 2 marks each‚ Section C comprises of 10 questions of 3 marks each and Section D comprises of 6 questions of 4 marks each. Question numbers 1 to 10 in section A are multiple choice questions
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FIITJEE Solutions to NTSE-2012 –Stage-I (Delhi State) (For Class X Students) Paper-2 SAT DATE OF EXAM : 18-11-2012 Time: 90 Minutes Max Marks: 90 INSTRUCTIONS TO CANDIDATES Read the following instructions carefully before you answer the question. Answers are to be given on a SEPARATE ANSWER SHEET. Use only HB Pencil. 1. Write you Roll No. very clearly (only one digit in one block) on this booklet and on the ANSWER SHEET. 2. This test consists of 90 questions of one mark
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The same thing as a primary key C. An attribute that serves as the primary key of another relation D. An attribute that serves no purpose Ans : c Data Structures; 1.The postfix equivalent of the prefix * + ab - cd is ? A. ab + cd - * B. abcd + - * C. ab + cd * - d. ab + - cd
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100% BIOGAS FOR URBAN TRANSPORT IN LINKÖPING‚ SWEDEN BIOGAS IN BUSES‚ CARS AND TRAINS BIOGAS IN THE SOCIETY Information from IEA BIOENERGY TASK 37 Energy from biogas and landfill gas SUMMARY The Linköping Biogas plant in Sweden was started in 1997 in order to treat organic waste from the agricultural sector in southeastern Sweden. Another main purpose was to produce biogas for the urban city buses in order to reduce the local‚ regional and global emissions from the urban transport system
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School of Communications Technology and Mathematical Sciences Digital Signal Processing Part 3 Discrete-Time Signals & Systems Case Studies S R Taghizadeh <srt@unl.ac.uk> January 2000 Introduction Matlab and its applications in analysis of continuous-time signals and systems has been discussed in part 1 and 2 of this series of practical manuals. The purpose of part 3 is to discuss the way Matlab is used in analysis of discrete-time signals and systems. Each section provides a series of worked
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STRUCTURAL ANALYSIS SUPPLEMENTARY MATERIAL Associate Professor Hong Guan and Professor Yew-Chaye Loo Griffith School of Engineering Griffith University Gold Coast Campus Queensland‚ Australia TENTH EDITION (Fourth Printing - 2013) Structural Analysis - Supplementary Material CONTENTS Part I 1 Supplementary Notes .................................................................. Fundamentals ...................................................................................
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the past 200 days‚ the owner has observed the following frequencies of demand QUANTITY DEMANDED NUMBER OF DAYS PROBABILITY 0 40 0.20 (= 40/200) 1 80 0.40 (= 80/200) The individual probabilities are all between 0 and 1 2 50 0.25 (= 50/200) 20 0.10 (= 20/200) Determining objective probability: • Relative frequency – Typically based on historical data P (event) = 0 ≤ P (event) ≤ 1 3 Types of Probability 4 10 Total 200 – Logically
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