opens‚ click on ‘Show Both’ for Velocity and Acceleration at the top of the page. Now click and drag the red ball around the screen. Make 3 observations about the blue and green arrows (also called vectors) as you drag the ball around. When the ball is stopped there isn’t any changes in the placement of the ball. This means that there is zero velocity at that time. 2) Which color vector (arrow) represents velocity and which one represents acceleration? How can you tell? The green arrow represents
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| Vectors cannot be added‚ subtracted and multiplied following simple arithmetic laws. Arithmetic division of vectors is not possible at all. | Example: mass‚ volume‚ time‚ distance‚ speed‚ work‚ temperature | Example: displacement‚ velocity‚ acceleration‚ force | Distance and displacement Distance is defined as the ground covered by a moving object during its motion. Its SI unit is metre (m). It has only magnitude‚ but no direction. Distance can never be negative. The minimum value of distance
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Sample Paper – 2011 Class – XI Subject – Physics Time: 3 Hrs. MM : 70 General Instructions: i) All questions are compulsory. ii) There are 30 questions in total. Questions 1 to 8 carry one mark each‚ questions 9 to 18 carry two marks each‚ questions 19 to 27 carry three marks each and questions 28 to 30 carry five marks each. iii) There is no overall choice. However‚ an internal choice has been provided in one question of two marks‚ one question of three
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Kinematics is one of the topics under dynamics. Kinematics describes motion without regard to its causes. In this experiment‚ kinematics focuses in one dimension: a motion along a straight line. This kind of motion‚ involves velocity‚ displacement‚ and acceleration with regards to time. The objectives of the experiment are to draw the displacement versus time graphs and velocity versus time graphs for uniform motion and uniformly accelerated motion‚ and to determine one’s normal reaction time and his reaction
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CHECK ACTIVITY ON MOTION 1. A car speeds up from 40 km/h to 55 km/h to overtake a truck. If this requires 15 s‚ what is the (a) acceleration and (b) distance traveled by the car? 2. Albert is riding his scooter at a velocity of 80 km/h when he sees an old woman crossing the road 45 m away. He immediately steps hard on the brakes to get the maximum acceleration of 7.5 m/square second. how far will he go before stopping? Will he hit the old woman? 3. the time a male bungee jumper if freely
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this is because it has more time to accelerate. We hope to find out from our results that the golf balls acceleration is the same as gravity which is 9.81 ms². We intent on showing this through the Suvat equation which is V²=U²+2as where ‘a’ is acceleration. Suvat equations were made by Gottfried Leibniz‚ Suvat stands for displacement (S)‚ Initial velocity (U)‚ Final velocity (V)‚ Acceleration (A) and Time (T). As I said we are using the equation V²=U²+2as‚ but we have to re-arrange this equation
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distance of 110 m. Determine the acceleration of the car. ------------------------------------------------- Solutions Given: d = 110 m | t = 5.21 s | vi = 0 m/s | | Find:a =?? | d = VI*t + 0.5*a*t2 110 m = (0 m/s)*(5.21 s) + 0.5*(a)*(5.21 s)2 110 m = (13.57 s2)*a a = (110 m)/ (13.57 s2) a = 8.10 m/ s2 ------------------------------------------------- Equations and Problem-Solving * Rocket-powered sleds are used to test the human response to acceleration. If a rocket-powered sled is accelerated
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Remedial Physics------------------------------------Review Questions -------------------------------------Chapter 2 Quantitative Problems 1) An object moves 15.0 m north and then 11.0 m south. Find both the distance traveled and the magnitude of the displacement vector. A) 6.0 m‚ 26.0 m B) 26.0 m‚ 4.0 m C) 26.0 m‚ 26.0 m D) 4.0 m‚ 4.0 m 2) A boat can move at 30 km/h in still water. How long will it take to move 12 km upstream in a river flowing
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B) 1.3 s C) 5.3 s D) 7.3 s E) 9.3 s 0=16-9t2 t2=16/9 t=1.33 s 4. Over a short interval near time t = 0 the coordinate of an automobile in meters is given by x(t) = 27t – 4.0t3‚ where t is in seconds. At the end of 1.0 s the acceleration of the auto is: A) 27 m/s2 B) 4.0 m/s2 C) –4.0 m/s2 D) –12 m/s2 E) –24 m/s2 at= -24t 5. Each of four particles move along an x axis. Their coordinates (in meters) as functions of time (in seconds) are given by | particle 1:
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the board. If it enters with a speed of 450 m/s and emerges with a speed of 220 m/s‚ what is the bullet’s acceleration as it passes through the board? Answer: –550 km/s2 5. A particle confined to motion along the x axis moves with constant acceleration from x = 2.0 m to x = 8.0 m during a 2.5s time interval. The velocity of the particle at x = 8.0 m is 2.8 m/s. What is the acceleration during this time interval? Answer: 0.32 m/s2 6. A package is dropped from a helicopter moving upward
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