Acceleration vs. Time Graphing Name: Morgan Wilkins Go to http://phet.colorado.edu/en/simulation/moving-man and click on Run Now. Objectives: • To predict‚ sketch and test acceleration vs. time kinematics graphs • To review predicting and sketching distance vs. time and velocity vs. time kinematics graphs PROCEDURE: 1. Begin by making charts like the one below for each of the following a-d My Prediction / Actual Graph a. The man walks slowly to the house from the origin. Position –Time Graph
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brakes is 0.75 s. [Answer: 70 m] 3. An underground train on the Mass Transit Railway moves away from a station with an initial acceleration of 0.9 m/s2. The acceleration decreases uniformly with time until after half a minute it is 0.3 m/s2. Calculate the speed reached and the distance travelled during this time. [Answer: 18 m/s‚ 315 m] 4. The magnitude of the acceleration and deceleration of an express lift is limited to 0.4 ‘g’‚ and the maximum vertical speed is 400 m/min. Calculate the minimum
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Lab II‚ Problem 3: Projectile Motion and Velocity Oct. 06‚ 2013 Physics 1301W‚ Professor: Hanany‚ TA: Vladimir Abstract A ball is tossed obliquely. The vectors of position and velocity are measured. The acceleration is calculated. Introduction A toy company is now making an instructional videotape on how to predict the position. Therefore‚ in order to make the prediction accurate‚ how the horizontal and vertical components of a ball’s position as it flies through the air should
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constant‚ velocity is not. Centripetal Acceleration‚ – acceleration that maintains the object along a circular path directed towards the center. Also called as radial acceleration. In 1673‚ Christian Huygens‚ determined the following relationships. Velocity‚ Where‚ r = radius of curvature/path‚ t = time/period. Frequency (f) – number of revolutions of cycle completed per unit time. So‚ Expressing centripetal acceleration in terms of frequency‚ In
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a. Speed‚ velocity and acceleration Title: Linear Motion Main Concepts: force‚ velocity‚ speed‚ and acceleration Instructional Objective(s) UKDs: As a result of this lesson students will: Understand THAT… Forces affect the speed of an object Acceleration relates to speed Velocity and acceleration are not the same thing Know … The definition of speed‚ velocity and acceleration Velocity
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Understand and use the idea of a vector to represent displacements‚ velocities‚ accelerations and forces in a plane 5. Know the difference between speed (a scalar) and velocity (a vector) 6. Know the difference between “mass” and “weight” 7. Know the difference between “gravitational acceleration” and “gravitational force” 8. Be able to explain what a force is without using the word “force” 9. Be able to explain what time is without using the word “time” 10. Given a velocity or acceleration in terms of unit i and j vectors‚ understand how to find its
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object is moving with uniform accleration. Its velocity after 5 sec is 25m/s and after 8 sec‚it is 34 m/s. Find the distance travelled by this object in 12th second. Ans. 44.5 A particle starts with a velocity of 100 cm/s and moves with –2 cm/s2 acceleration. When its velocity be zero and how far will it have gone? Ans. 50s ‚ 25m m/s. After 7 a time interval ∆t‚ the velocity of the body is reduced by half‚ and after the same time interval‚ the velocity is again reduced by half. Determine the velocity
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CBSE TEST PAPER-02 CLASS - IX Science (Motion) 1. If a body starts from rest‚ what can be said about the acceleration of body? (a) Positively accelerated (c) Uniform accelerated (b) Negative accelerated (d) None of the above [1] 2. What does slope of position time graph give? (a) speed (b) acceleration (c) uniform speed [1] (d) Both (a) and (c) depending upon the type of graph. 3. When a body moves uniformly along the circle‚ then:(a) its velocity changes but speed remains the same (b) its
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determine the minimum speed required to clear 8m in 2.02 s just use D/T= 8/2.02= 3.96 m/s horizontally to clear 8 m from 20 m vertically. 5) Using acceleration = force * mass‚ we know the car had a force of 5000N‚ and a mass of 1500kg. 5000/1500 = -3.33 m/s deceleration. It took 5.6 seconds for the car to decelerate to 0‚ so multiply the deceleration/acceleration with the amount of time to obtain the initial speed of the vehicle. 3.33 * 5.6 = Initial speed of 18.65 m/s 6) Weight is equated as mass * gravity
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Instructor: (Name) Introduction We verified Newton’s Second Law for one-dimensional motion by timing an accelerated glider moving along a flat track. We varied both the accelerating force and the mass of the glider. We found that for a given force the acceleration of the glider was inversely proportional to the mass of the glider‚ in agreement with Newton’s Second Law. Experimental Procedure Description of the Apparatus: A sketch showing the essential elements of the apparatus is presented in Figure 1. below:
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