Acids and Bases Q1.This question is about several Brønsted–Lowry acids and bases. (a) Define the term Brønsted–Lowry acid. ........................................................................................................................ ........................................................................................................................ (1) (b) Three equilibria are shown below. For each reaction‚ indicate whether the substance immediately above the box is acting
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THE CHEMISTRY OF ORGANIC MOLECULES I. MACROMOLECULES-large molecules that are composed of smaller molecules and atoms that are bonded together. These are among the largest of all chemical molecules. A. Polymers-the largest of the macromolecules. These are composed of numerous‚ small identical subunits known as Monomers. There are 4 major polymers that are important for living organisms. These polymers are; carbohydrates‚ lipids‚ proteins and nucleic acids. B. Polymers
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and is a strong acid. Where comparing to the conductivity of distilled water to HCL would be evidently HCL. This is because distilled water doesn’t contain ions‚ hence no movement of electrons‚ furthermore no conductivity. However since we added sodium chloride‚ distilled water will have some conductivity but no where near the amount of HCL. Comparing to the conductivity of vinegar to HCL mostly relays on how acidic each other are. Since HCL is a strong acid and vinegar is a weak acid‚ this will impact
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Properties of Acids and Bases Diagram: A B C D E F Bromothymol Blue Universal Indicator Phenolphthalein Litmus Paper Analyze: 1) F‚ C‚ D‚ B‚ A‚ E 2) D is neutral because it turned to the colour of green when it came in contact with the indicator Bromothymol Blue. The acid or base is green between 6.0-7.6 pH. 3) Solution E is more alkaline (more basic) than solution A because when E came into contact with the indicator Bromothymol Blue it turned
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|Chapter 5: | |Structure and Preparation of Alkenes. | |Elimination Reactions | Summary Alkenes contain the C=C functional group which can be prepared by 1‚2-elimination reactions such as: • dehydration of alcohols (- H2O) or • dehydrohalogenation of alkyl halides (- HX). Zaitsev’s rule indicates that the preferred product is the more highly substituted
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18.1.4 – 18.1.6 CALCULATIONS INVOLVING ACIDS AND BASES Review of Important formulas pH = ‐ log10[H+] [H+] = 10‐pH pKa = ‐ log10 Ka Ka = 10‐pKa pOH = ‐ log10[OH‐] [OH‐] = 10‐pOH pKb = ‐ log10 Kb Kb = 10‐pKb The ionic product of water = Kw = [H+] x [OH‐] = 1.0 x 10‐14 mol2 dm‐6 at 298 K The expression varies with temperature
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Kong Acid rain on plant -Background information Unpolluted rain is normally slightly acidic‚ with a pH of 5.6. Carbon dioxide (CO2) from the atmosphere dissolves to form carbonic acid. Acid rain is rain that has been made acidic by certain pollutants in the air. Acid rain is a type of acid deposition‚ which can appear in many forms. Wet deposition is rain‚ sleet‚ snow‚ or fog that has become more acidic than normal. Dry deposition is another form of acid deposition‚ and this is
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(Fe3+ ) form. Ferric form is not usually absorbed in the body. In the stomach‚ there is low pH of 2 due to presence of gastric acids such as Hydrochloric and Ascorbic acids. These acids provide an acidic environment for reduction of ferric iron to ferrous (Fe2+). Ferrous iron can be absorbed in the body system. As in following equation of iron (iii) reaction with Ascorbic acid ‚ the product is iron (ii) chloride which is soluble 2 Fe3+ (s) + C6 H8 O6 (aq) → 2 Fe2+ (aq) + C6 H6 O6 (aq) + 2 H (aq)+
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ACID/BASE You might need to know the following K values: CH3COOH Ka = 1.8 x 10–5 Benzoic Acid Ka = 6.5 x 10–5 HNO2 Ka = 4.5 x 10–4 NH3 Kb = 1.8 x 10–5 HF Ka = 7.2 x 10–4 H2S Ka = 5.7 x 10–8 HSO4– Ka = 1.2 x 10–2 HS– Ka = 1.2 x 10–13 HCOOH Ka = 1.8 x 10–4 HOCl Ka = 3.0 x 10–8 SIMPLE ACIDS AND BASES 1. According to the Brønsted–Lowry definition‚ which species can function both as an acid and as a base? (A) Cl– (B) SO42– (C) NH4+ (D) HCO3– (E) H3O+ 2. Which of the following
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Objectives 1. To separate a mixture of an acid and a neutral compound into its component by extraction. 2. To determine the melting point and the yield of the benzoic acid and the unknown sample. 3. To determine the unknown sample whether is is Trimethylmethanol or 1‚2‚4‚5-Tetrachlorobenzene. Introduction Extraction is a process of transferring a solute from one solvent to another. It is usually used to separate one or more components from a mixture. Diethyl ether‚ dichloromethane
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