1. Solve a. e^.05t = 1600 0.05t = ln(1600) 0.05t = 7.378 t = 7.378/.05 t = 147.56 b. ln(4x)=3 4x = e^3 x = e^3/4 x = 5.02 c. log2(8 – 6x) = 5 8-6x = 2^5 8-6x = 32 6x = 8-32 x = -24/6 x = -4 d. 4 + 5e-x = 0 5e^(-x) = -4 e^(-x) = -4/5 no solution‚ e cannot have a negative answer 2. Describe the transformations on the following graph of f (x) log( x) . State the placement of the vertical asymptote and x-intercept after the transformation. For example‚ vertical shift
Premium Mathematics Analytic geometry Number
Centre Number For Examiner’s Use Candidate Number Surname Other Names Examiner’s Initials Candidate Signature Pages General Certificate of Secondary Education Higher Tier June 2014 Mark 3 4–5 6–7 Mathematics (Linear) 4365/1H H Paper 1 Monday 9 June 2014 9.00 am to 10.30 am For this paper you must have: 8–9 10 – 11 12 – 13 14 – 15 16 – 17 mathematical instruments. 18 – 19 You must not use a calculator 20 – 21 Time allowed 1 hour 30 minutes 22 – 23 TOTAL Instructions Use black
Premium Volume Triangle Quadratic equation
Treasure Hunt: Finding the Values of Right Angle Triangles This final weeks course asks us to find a treasure with two pieces of a map. Now this may not be a common use of the Pythagorean Theorem to solve the distances for a right angled triangle but it is a fun exercise to find the values of the right angle triangle. Buried treasure: Ahmed has half of a treasure map‚which indicates that the treasure is buried in the desert 2x + 6 paces from Castle Rock. Vanessa has the other half of the map
Premium Pythagorean theorem Triangle Law of cosines
They allow the employees to make decission for themselves. They also focus on supporting their employees in their personal and professional growth. They offer a wellness program for all employees. They look at it as we take care of you and you take care of our guests. It has improved how they do their jobs‚ how they treat the guests‚ how their attitude is at work‚ and how they can have fun. If they were to open in Asia‚ I really don’t see it being a problem for the fact is I’m sure they will get
Premium Corporation
Module 8 Business Decisions Capital Gains Page 705‚ question 30 30A- How much tax will you have saved by waiting? $1‚250 $25‚000 X .10 = $2‚500 $25‚000 X .15 = $3‚750 $3‚750 - $2‚500 = $1‚250 30B- How much would you save in 36% bracket? Between $2‚000 to $4‚400 $25‚000 X .20 = $5‚000 $25‚000 X .28 = $7‚000 to $9‚900 $7‚000 - $5‚000 = $2‚000 $9‚900 - $5‚000 = $4‚400 Interpreting the numbers Page 743‚ Question 20 2‚300 2‚430‚ 2‚018‚ 2‚540‚ 2‚675‚ 4‚800
Premium Depreciation
Centre Number For Examiner’s Use Candidate Number Surname Other Names Examiner’s Initials Candidate Signature Pages General Certificate of Secondary Education Foundation Tier November 2013 Mark 2–3 4–5 6–7 Mathematics 43601F Unit 1 Wednesday 6 November 2013 9.00 am to 10.00 am For this paper you must have: l mathematical instruments. 10 – 11 12 – 13 14 – 15 16 – 17 a calculator l F 8–9 TOTAL Time allowed l 1 hour Instructions
Premium Question Chart
Understanding What You Read – Week 3 Week 3- Chapter 5- Understanding Your Customer 1. Identify demographic trends that are occurring in the United States‚ related to (a) number of single-person households‚ (b) median age for marriage‚ (c) birthrate‚ (d) U.S. population growth‚ and (e) number of male homemakers. Single person households are showing the greatest increase in numbers and that trend is projected to continue. Birthrate has remained relatively stable in the United States since
Premium Product life cycle management Data warehouse Department store
1998 9 14 1. 1.1 Markov Property 1.2 Wiener Process 1.3 2. 2.1 2.2 2.3 2.4 2.5 2.6 Taylor Expansion 2.7 3. Stochastic 3.1 3.2 SDE(Stochastic Differential Equation) 4. Stochastic 4.1 Stochastic integration 4.2 Ito Integral 4.3 Ito Integral 4.4 5. Ito’s Lemma 5.1 Stochastic 5.1.1 5.1.2 5.1.3 First Order Term Second Order Term Cross Product Terms “ ” – Ito Integral Riemann (Ordinary Differential Equation) (Chain rule) 5.2 Ito’s Lemma 6. 6.1 6.1.1 6.1.2 Closed-Form Solution Numerical Solution
Premium
let f(x) be a quadratic polynomial such that that f(2)= -3 and f(-2)=21‚ then the co-efficient of x in f(x) is a. -3 b. 0 c. -6 d. 2 1. if f(x) =x3 +ax+b is divisible by (x-1) 2 ‚then the remainder obtained when f(x) is divided by (x+2) is ; a. 1 b . 0 c. 3 d. -10 3. the remainder when x1999 is divided
Premium Integer Division Remainder
2008 H I G H E R S C H O O L C E R T I F I C AT E E X A M I N AT I O N Mathematics General Instructions • Reading time – 5 minutes • Working time – 3 hours • Write using black or blue pen • Board-approved calculators may be used • A table of standard integrals is provided at the back of this paper • All necessary working should be shown in every question Total marks – 120 • Attempt Questions 1–10 • All questions are of equal value 212 BLANK PAGE – 2 – Total marks – 120
Premium Series Summation Mobile phone