Chemistry 121 Colligative Properties Lab Demonstration of Selected Calculations from Choice I Determination of Kf for Naphthalene To determine the Kf for naphthalene‚ we need to find the difference in the freezing point of pure naphthalene and the solution of 1‚4-dichlorobenzene in naphthalene. Let’s say that we did this experiment‚ used 1.00 g 1‚4-dichlorobenzene in 10.00 g naphthalene‚ and found that the freezing temperature of pure naphthalene was 78.2°C‚ while that of the solution was 75
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Discussion Based on the results of the lab it can be seen that the metal in the lab can be identified as lead. The identity of the metal was determined by the heat energy calculations. The heat capacity that was found matched closely to that of the lead. There were several possible sources of error that could be found throughout the lab. Some of the main errors as seen in question 7 that could have affected the results of the lab were the amount of water transferred with the hot metal‚ the
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Physical and Chemical Change Objective: Recognize and distinguish between chemical and physical changes. Materials: - lab balance - microspatula - lab burner - dropper pipet - 5 test tubes - mortar and pestle - test tube rack - magnet - test tube holder - insulating pad - watch glass - safety goggles - glass square - lab apron or coat - copper sulfate pentahydrate - iron fillings - sodium chloride - magnesium ribbon - hydrochloric acid - paper
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Ten Minutes of Specific Heat Remi Adams East Rowan High School AP Environmental Science Abstract Specific heat and climate were the primary focus of this lab. Specific heat is defined as “the measure of the ability of a substance to change temperature”. The purpose for carrying out this lab was to determine the specific heat/rates of both soil and water‚ and then comparing them. Students also were to relate specific heat to climate. Students were to determine which substance expressed
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In this lab‚ we will measure the heat of combustion‚ or calorimetry‚ of a candle and compare the found quantity with known values for other hydrocarbons. The calorific value is the total thermal energy released when a substance goes through complete combustion with oxygen. In order to achieve the purpose of this lab‚ we must first determine the mass of the tea candle. Then‚ we will determine our room temperature‚ measure about 100 mL of chilled water‚ and then pour the water into the given empty
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Jashandeep Gill Gammellos Chemistry Density is one of the fundamental principles of physics. Density is the reason why a plank of wood floats on water while a piece of metal several times smaller will sink. Density of an object is measured in g/cm³ or g/cc. The equation is D=M/V‚ D being the density of the object‚ M being the mass of the object‚ and V being the volume of the object. Mass is the space an object takes up. It is the amount of matter present in an object. Mass is measured using
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MECHANICAL ENGINEERING 449 SENIOR LAB Test of a Heat Pump Submitted Submitted by: Submitted to: Executive Summary: The purpose of this experiment was to determine the performance values of a Hylton Air and Water Heat Pump System. The system uses refrigerant 134a and water as the working fluids. The power input of the system was measured. The rate of heat output and the coefficient of performance are
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Specific heat is the property of the material that an object is made of. The greater the material’s specific heat and the mass‚ the more energy must be added to change its temperature. The goals of this lab were to calculate the specific heat of water and compare to the known value of 4.19J/°Cg. Another goal was to calculate the efficiency of the hot pot used for the experiment and to estimate the cost to heat water for a cup of tea and to bath in a bathtub. The thermal energy E= cm Δ T‚ required
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Chemistry 3373F Lab Manual 2008 Modified 11/07 Table of Contents Chem 3373 Laboratory Schedule for Fall 2008.............................................................................2 The Benzoin Condensation of Benzaldehyde ..............................................................................3 Synthesis of Dilantin and Related Compounds (two weeks).........................................................6 Synthesis of an Alkaloid: Pseudopelletierine (two weeks) .............
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Calculations/Analysis Through this lab‚ we are now able to calculate the molar heat of combustion for paraffin‚ since we have the difference of the mass in candle before/after and the periodic table of elements (for converting g to moles of paraffin). Molar heat of combustion = (kJ of heat)/(mole of fuel) However‚ we do not know how much heat was released nor the mole of fuel (paraffin). In order to find the amount of heat released‚ we use the formula: g=mcΔT. Here‚ g represents the heat‚ m represents the mass
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