Name Naza Moore ID# 24120389 Lab# 2 Lab instructors Alecia Palmer and Donald Burke Course Instructor Maureen Wilson Lab Title Preparation of cyclohexene from cyclohexanol Aim Preparation of an Alkene by dehydration of an alcohol in the presence of a catalyst. Calculate the percentage recovery of products. Test for purity and identification of products. Abstract Cyclohexene and cyclohexanol are both colourless aromatic compounds. The major difference between the two is the presence
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Task 3: The chemical tests used in order to carry out and collect these results are useful for the simple identification of colourless organic liquids and ones that are often found at the scenes of crime. The first test carried out was the Lucas test which was used to identify a variety of alcohols following the contribution of a given solution‚ from carrying this out I could then identify that primary and secondary alcohols were present with one tertiary alcohol also being present however despite
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IntroductionA dehydration reaction of an alcohol results in an alkene. This type of reaction requires an alcohol‚ an acid catalyst and heat. Generally strong concentrated acids‚ like sulfuric acid and phosphoric acid‚ are used as the acid catalyst.The acid catalyst protonates the alcohol‚ to make a much better leaving group. Weakest bases make the best leaving groups‚ so once the alcohol is protonated the leaving group leaves and produces in a carbocation and water. In order to form the double bond
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Dehydration of Cyclohexanol Introduction In this experiment cyclohexene‚ an alkene‚ was prepared by the dehydration of cyclohexanol‚ an alcohol‚ using phosphoric acid‚ an acid catalyst. The reaction is as follows: [pic] The dehydration of cyclohexanol was performed in a simple distillation apparatus. As cyclohexene formed‚ it was distilled out of the mixture. Background Dehydration is an elimination reaction of an alcohol that takes place in the presence of an acid catalyst
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UNIVERSITY OF THE GAMBIA LECTURE NOTES COURSE: PRINCIPLES OF CHEMISTRY II (ORGANIC CHEMISTRY) CODE: CHM 161 2ND SEMESTER SESSION: 2012/2013 LECTURER: ANTHONY F. ADJIVON UNIT 1 INTRODUCTION Organic chemistry started as the chemistry of life‚ when that was thought to be different from the chemistry in the laboratory. Then it became the chemistry of carbon compounds‚ especially those found in coal. Now it is both. It is the chemistry of the compounds of carbon along with other elements
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N10/4/CHEMI/SP2/ENG/TZ0/XX 88106105 CHEMISTRY STANDARD LEVEL PAPER 2 Thursday 11 November 2010 (afternoon) Candidate session number 0 1 hour 15 minutes 0 INSTRUCTIONS TO CANDIDATES • • • • Write your session number in the boxes above. Do not open this examination paper until instructed to do so. Section A: answer all of Section A in the spaces provided. Section B: answer one question from Section B. Write your answers on answer sheets. Write your session number
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1. (a) The diagram below represents the industrial fractional distillation of crude oil. (i) Identify fraction A. (ii) What property of the fractions allows them to be separated in the column? (2) (b) A gas oil fraction from the distillation of crude oil contains hydrocarbons in the C15 to C19 range. These hydrocarbons can be cracked by strong heating. (i) Write the molecular formula for the alkane with 19 carbon atoms. (ii) Name the type of reaction involved in cracking. (iii) Write
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www.igcse.at.ua ORGANIC CHEMISTRY OIL and its many useful PRODUCTS The origin of oil Crude oil is formed from organic material of the remains of plant and animal organisms that lived millions of years ago. These remains form sediments eg at the bottom of seas‚ and become buried under layers of sedimentary rock. They decay‚ without air (oxygen)‚ under the action of heat and pressure to form crude oil over millions of years. It is a fossil fuel because it is formed from
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1691 Strong 4. The reaction of the unknown with bromine gave a negative result meaning the solution did not turn clear‚ but rather‚ maintained an orangish brown color. This is interpreted to mean that bromine in not adding to either side of an alkene bond‚ so there is no C=C bond in the unknown compound. The reaction of the dicarboxylic acid with bromine gave a positive result meaning that the solution turned clear as a result of bromine adding to both sided of the C=C bond. The dicarboxylic
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Carbon and Its Compounds Carbon: Introduction Atomic Number: 6 Electronic Configuration: 2‚ 4. Valence electrons: 4 Property: Non-metal Abundance:- Carbon is the 4th most abundant substance in universe and 15th most abundant substance in the earth’s crust. Compounds having carbon atoms among the components are known as carbon compounds. Previously‚ carbon compounds could only be obtained from a living source; hence they are also known as organic compounds. Bonding In Carbon:- The Covalent
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