HPMC S. No. Wavelength cm -1 Interpretation 1 3600-3500 cm -1 O-H phenols group 2 2950-2850 cm -1 C-H Alkenes group 3 1400-1300 cm -1 Methyl bonding FTIR analysis of Pantoprazole + HPMC Table 9.12: FTIR interpretation analysis of Pantoprazole + HPMC S. No. Wavelength cm -1 Interpretation 1 3530-3400 cm -1 O-H phenols group 2 3300-3200 cm -1 N-H amides group 3 3000-2910 cm -1 C=C-H alkenes 4 1450-1350 cm -1 Methyl bonding 5 1100-1000 cm -1 C-O alcohol‚ ether group FTIR analysis of Pantoprazole
Premium
UNIT 1 REVISION CHECKLIST Topic 1.1 Can you a) define atomic number‚ mass number‚ isotopes‚ relative atomic mass‚ relative molecular mass b) remember the four stages in mass spectrometry and explain how each one works c) calculate relative atomic mass from isotopic composition data‚ or from a mass spectrum of an atom d) deduce relative molecular mass from the mass spectrum of a molecule e) Give the electronic configuration of atoms with atomic number 1-36 and of the common ions
Free Atom Chemical bond Covalent bond
Developing Fuels * All gases take up the same volume under the same conditions. AT room temperature and room pressure this volume is 24 dm3. * Number of moles= volume in dm3 24 * Balanced equations can also be used to work out gas volumes. In the equations: 2Na + 2H2O 2NaOH + H2‚ where 15g of sodium is reacted‚ you can work out the volume of gas from working out the number of moles in 15g Na = 0.65 mol. Then you see that 2 mol of Na 1mol of H2‚ Thus 0.65 mol Na 0.325 mol H2. 0.325
Premium
on the other hand‚2-pentene will react with sulphuric acid to form penta-2‚3-diol.The purple color of KmnO4 will change to brown CH3CH=CHCH2CH3 + KMnO4 (cold) ---> CH3CH2(OH)CH2(OH)CH2CH3 For the experiment between alkane and alkene that react with sulphuric acid‚alkene which is 2-pentene have react and change to ethyl hydrogen sulphate.The alkane‚heptanes doesn’t react as the as the sulphuric acid will act as electrophile. C5H10 + H2SO4 ==> C5H11.HSO4 For the aromatic hydrocarbon‚toluene doesn’t
Premium Benzene Hydrogen Carbon
Bromination Solo Experiment 3 – Individual Lab Report (Save as pdf and submit‚ due by 12:00 NOON one week after experiment) Last Name: First Name: TA Name: Date Lab Performed: Date Lab Submitted: Group A‚ B‚ or C: Comments for Grading TA: (Please indicate if you performed the lab on a day other than your regularly scheduled day and/or with a TA other than your regular TA). Page Limit: report must not exceed FIVE pages (including this page) LIMIT DOES NOT INCLUDE ANY GRAPHS‚ SPECTRA
Premium Carbon Oxygen Chemical reaction
Lab #2 (Part A‚B) Due date: Oct 5‚ 2010 1 - Theory and mechanism Epoxidation is a reaction of an alkene with a peroxycarboxylic acid (also called peracid) to produce an epoxide product‚ generally performed in inert solvents‚ such as dichloromethane. The epoxide product is a cyclic ether in which the ring contains three atoms. The alkene gains an oxygen from the peracid in a syn fashion. In this experiment‚ R-(－)-carvone is reacting with MCPBA‚ a peracid‚ to produce the epoxide product.
Premium Oxygen Hydrogen Hydrogen peroxide
Lesson 08.01: Half-life and Radioactive Decay · Distinguish between nuclear and chemical reactions. · Compare and contrast different types of nuclear decay and the properties of the three types of radiation (alpha‚ beta‚ and gamma) discussed in the lesson. · Be able to predict the isotope or radiation produced by a nuclear decay reaction when the other product is given. · Describe and make predictions regarding half-life‚ including using a graph or set of data to determine the half-life of
Premium Functional group Carbon Alcohol
using line-angle structural formulas. (Ex. The five constitutional isomers of C6H14) -Cycloalkanes are alkanes that contain a ring of three or more carbons -General Formula of Cycloalkane: CnH2n‚ n = number of carbon atoms Alkenes and Cycloalkenes -An alkene is an acyclic unsaturated hydrocarbon that contains one or more carbon –
Premium Functional group Alcohol Amino acid
eliminated the reaction yields an alkene in which the un-protonated alcohol serves as the reaction solvent. This experiment then called for the distillation of this mixture‚ using a distillation apparatus. As this distillation took place the products‚ alkenes and water continuously distilled from the reaction mixture into a Hickman still as they were formed. The removal of these elements shifted the equilibrium to the right‚ ultimately increasing the yield of alkene‚ this is also known as Le Chatelier’s
Premium Water Oxygen Alcohol
107 oC 1.18 g/ml Sodium bicarbonate NaHCO3 84.007 g/mol Decomposes at melting point unknown 2.159 g/ml Diethyl ether C2H5OC2H5 74.12 g/mol 34.6 °C −116.3 °C 0.7134 g/ml In this lab we use electrophilic addition of a hydrogen halide to an alkene to make 2-bromo-2-methylbutane. Electrophilic addition
Premium Chemistry Chemical reaction Hydrogen