Chem 3418 Organic Chemistry Laboratory I Acid Base Review Definition In general‚ an acid is a substance that can donate a proton (H+) and a base is a substance that can accept a proton. Any proton in an organic molecule can potentially be donated. The most acidic proton in a molecule would be donated first. Any lone pair in an organic molecule can act as the proton acceptor. An acid (HA) reacts with a base (in this case H2O) to form the conjugate base of the acid (A-) and the conjugate acid of the
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early atmosphere - earth roughly 4 billion yrs old - created by volcanoes erupting + releasing gases - contained mostly co2 + water vapour - earth cooled + water vapour condensed to form oceans - co2 dissolved into oceans + used to form marine organism shells which were compacted to form sedimentary rock - plants evolved to photosynthesise‚ takingin co2 + releasing oxygen - scientists don’t kno where all nitrogen came from bc they weren’t there to record evidence but most theories suggest
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each of the following molecules: O C NH2 H N O C OH H C CH2 (a) (b) O (c) Solutions: a. b. c. d. Amide‚ double bond Amine‚ carboxylic acid Double bond‚ ketone‚ ester O OCH3 (d) CH2OH Aromatic ring‚ double bond‚ alcohol (a) Alcohol (d) Amine (b) Aromatic ring (e) both ketone and amine (c) Carboxylic acid (f) two double bonds 3.2 Propose structures for simple molecules that contain the following functional groups: Solutions: (a). H 3C CH3 OH (b). O (c)
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Chemistry Unit 1 – Revision Questions Chemistry 1A 1) Define an element. How many are there in the Periodic Table? 2) Write a table with the charges and masses of protons‚ neutrons and electrons. 3) Define atomic number and mass number. 4) Draw electron (energy level) diagrams for Be‚ S‚ Al‚ Cl and K. Also‚ write down the number of protons and neutrons for each. Finally‚ write the symbols (with mass no. and atomic no.) 5) Why have all Group 7 elements (halogens) got similar chemical properties
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Lab #24- Preparation 4-Methylcyclohexene Introduction: The goals in this lab were to have a reaction occur with 4-methylcyclohexanol and an acid catalyst to form our product of 4-methylcyclohexene via an E1 reaction. This reaction is accomplished by removing the –OH group on 4-methylcyclohexanol via dehydration and to have a double bond form via a loss of a hydrogen on a β-Carbon. Many techniques and skills were developed in this lab. Among them were dehydration‚ isolation‚ drying
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cat cracker. Catalysts used for cracking alkanes are inorganic compounds called zeolites crystalline compounds of Al‚ Si‚ and O with some metal ions. Zeolites are effective as catalysts because they have a very large surface area per unit mass. Mixtures of alkanes can also be cracked by thermal or steam cracking. ================================ Properties of Alkanes and Alkenes Alkenes have similar physical properties to the corresponding alkanes. They are both non-polar molecules with weak
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The Earth’s atmosphere has changed over billions of years‚ but for the past 200 million years it has been much as it is today. We are‚ however‚ causing our atmosphere to change by human activity. Burning fossil fuels and deforestation are two examples of human effect on the environment. Composition of the Earth’s atmosphere The composition of air You need to know the proportions of the main gases in the atmosphere. The Earth’s atmosphere has remained much the same for the past 200 million years
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polyhalogen compounds. Haloalkanes and Haloarenes Haloarenes Halogenated compounds persist in the environment due to their resistance to breakdown by soil bacteria. 10 Unit The replacement of hydrogen atom(s) in a hydrocarbon‚ aliphatic or aromatic‚ by halogen atom(s) results in the formation of alkyl halide (haloalkane) and aryl halide (haloarene)‚ respectively. Haloalkanes contain halogen atom(s) attached to the sp3 hybridised carbon atom of an alkyl group whereas haloarenes contain halogen
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2950 cm-1 sp2 C-H stretch 3100 cm-1 C=O - ketone 1715 cm-1 C=C alkene 1680 cm-1 O O d. e. f. OH sp3 C-H stretch 2950 sp C-H stretch 3310 cm-1 CC alkyne stretch 2220 cm-1 cm-1 sp2 C-H stretch 3100 cm-1 sp3 C-H stretch 2950 cm-1 C=C alkene 1680 cm-1
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all of the asymmetric carbon atoms in the molecule shown below (prostacyclin). (b) Based on the number of asymmetric carbons‚ how many stereoisomers of prostacyclin are possible? 5. Hydrogenation of an alkene will yield an alkane. The alkane formed by hydrogenation of (S)-4-methyl-1-hexene (I) is optically active‚ while the one formed by hydrogenation of (S)-3-methyl-1-pentene (II) is not. Explain. I II 6. Draw and label a stereoisomer of this compound
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