Investigation 8.4- Titration Analysis of Vinegar Prediction: We predict that the amount concentration of acetic acid in a sample of vinegar is 0.83 mol/L. VCH3COOH (aq) = 10.00 mL VNaOH (aq) = ? CCH3COOH = 0.83 mol/L CNaOH (aq) = 0.145 mol/L Materials: Sodium hydroxide 100 mL Acetic acid 50 mL 250 mL beaker x 2 Distilled water x 1 bottle Erlenmeyer flask x 1 Burette x 1 Pipette x 1 Pipette bulb x 1 Volumetric pipette x 1 Phenolphalein Procedure: Step 1- Gather materials
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EXPERIMENT 3: INTRODUCTION TO TITRATION – DETERMINATION OF THE MOLARITY AND CONCENTRATION OF SULPHURIC ACID BY TITRATION WITH A STANDARD SOLUTION OF SODIUM HYDROXIDE INTRODUCTION Reaction of acid and base is one of the most common reaction in chemistry. This reaction is also widely known as neutralization. In this experiment‚ we used titration technique which involves accurately measuring the volume of a solution required to react with another reagent. An indicator must be used to determine the
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Acid/ Base Titration Lab Design III Materials: Goggles HCl NaOH Distilled Water Label Beaker Graduated Cylinder Pipet Stirring rod Buret with clamp Stopper Ring Stand Utility Clamp Computer Computer Program pH probe Procedure: 1) 2) Goggles were put on. 3) 0.1 M NaOH solution was made using 0.4 g NaOH and 100 mL distilled water. The ingredients were added together in a beaker and stirred. 4) The buret was standardized by adding 10 mL of distilled water‚ rolling
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Acid-base titration Aim To study the titration curve of a strong base-strong acid‚ strong base-weak acid and weak acid-strong base titrations Introduction Acid-base titrations are based on the neutralization reaction between the analyte and an acidic or basic titrant. When an acid and a base are present in a stoichiometric amount e.g. 1 mole HCl added to 1 mole NaOH‚ this means that the equivalent point has been reached in an acid-base system. The end point of an acid-base titration can be
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Acid-Base Titration and Volumetric Analysis The purpose of this experiment is to determine the [NaOH] of a solution by titrating it with standard HCl solution‚ to neutralize a known mass of an unknown acid using the NaOH solution as a standard‚ to determine the moles of NaOH required to neutralize the unknown acid‚ and to calculate the molecular mass of the unknown acid. Procedure: Part A: Standarized 0.10M HCl solution and unknown NaOH solution were poured into two beakers. The burets
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chemical that is made industrially is sodium thiosulfate. Sodium thiosulfate solution is sold in a range of concentrations. Dilute solutions of sodium thiosulfate can be used for cleaning contact lenses and used as a medicine for some cancer patients. Concentrated solutions are used to treat spillages of some chemicals. Sodium thiosulfate is safe to handle and store‚ but if it is mixed with an acid‚ a reaction happens. When dilute sodium thiosulfate is mixed with an acid‚ solid sulphur is made‚ which makes
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However‚ for Quick-eze‚ the number of moles is 0.00216 moles (1 tablet). This means the average volume of the NaOH have affected the number of moles as the concentration of the sodium hydroxide is 0.1M. This means that if less NaOH was required to neutralise the acid‚ the number of moles of HCl neutralized by the ant-acid would be greater. For example; by using mole ratio‚ the number of moles of HCl reacted with the NaOH is 0.00216 moles (1 tablet of Quick-eze). The number of moles of HCl that were
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tion Experiment 1 Titration curves of amino acids General structure of amino acids (amphoteric type): Zwitter ion C * : α- carbon : α- amino acid NH2 : α- amino group‚ basic (proton acceptor) COOH : α- carboxylic group‚ acidic (proton donor) R : side chain of amino acid Classification of amino acids depending on the nature
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Chamberlin Date: 29 April 2017 Experiment Title: Acid-Base Titration Abstract: Vinegar is a common household item containing acetic acid as well as some other chemicals. This experiment is designed to determine the molar concentration of acetic acid in a sample of vinegar by titrating it with a standard solution of NaOH. CH3COOH(aq) + NaOH(aq) -> CH3COONa(aq) + H2O(l) By adding the sodium hydroxide‚ which is a basic solution‚ to the acetic acid‚ which is an acidic solution‚ a neutralization
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Introduction Background Information To begin a discussion about acid-base titrations‚ we must first recall that there are several definitions of acids and bases. For the purpose of this exercise‚ we will consider the Arrhenius definition of acids and bases‚ in which an acid is a proton (H+) donor and a base produces hydroxide (OH-) in solution. When an acid reacts with a base‚ the products of this reaction are water and a salt. Note that salt here does not only mean table salt (NaCl)‚ but can refer
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