Answers Chapter 1 c i No x-intercept‚ y = 4 iii y Pre-test 1 a 2x + 1 1 3 c x+ x= x 2 2 f 3x − 7 b 5(x − 1) 1 (x + 4) 3 -5ab -21x -4x + 4 3 ii 0 y=4 d 2x − 3 e a a a a 7x 8y 3x + 3 4m b b b b 6a 7 6 b 7 12 9 a 3 b -2 c 1 10 a y = 2x + 1 b y = -x + 5 c 4 7 d 19 72 Exercise 1A f 21 20 2 3 4 5 4 e 7 c c c c -5x 2 15a 2 -10x + 2x 2 a (0‚ 4) d g c 10 ii
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-n2 + 3n + 180 = 0 90 = n2 (n-3) n-15 = 0 n+ 12= 0 180 = n2 – 3n n = 15 n= -12 Answer: PENTADECAGON #19. Find the number of diagonals of a regular polygon whose interior angle measures 144°. Given: I.A = 144° Required: D =? For D I.A = 180(n-2)n 144n = 180n – 3 D = n2 (n-3) D = 702 144 = 180(n-2)n
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position‚ which is expressed by an angle. It is important to be able to relate the angular description of circular motion to the orbital or tangential description‚ that is‚ to relate the angular displacement to the arc length s. The arc length is the distance traveled along the circular path and the angle θ is said to subtend (define) the arc length. A unit that is very convenient for relating angle to the arc length is the radian (rad)‚ which is defined as the angle subtending an arc length (s) that
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ŸÊ◊Ê¢∑§ Roll No. No. of Questions — 24 No. of Printed Pages — 7 SS—15–1—Maths. I ©UìÊ ◊ÊäÿÁ◊∑§ ¬⁄UˡÊÊ‚ 2010 II SENIOR SECONDARY EXAMINATION‚ 2010 flÒ∑§ÁÀ¬∑§ flª¸ I ÃÕÊ ó ∑§‹Ê fl ÁflôÊÊŸ flª¸ ( OPTIONAL GROUPS I & II — HUMANITIES AND SCIENCE ) ªÁáÊÃ ó ¬˝Õ◊ ¬òÊ ( MATHEMATICS — First Paper ) ‚◊ÿ — 3 4 ÉÊá≈U ¬ÍáÊÊZ∑§ — 60 ¬⁄UˡÊÊÁÕ¸ÿÊ¥ ∑§ Á‹∞ •Êfl‡ÿ∑§ ÁŸŒ¸‡Ê — GENERAL INSTRUCTIONS FOR EXAMINEES : 1. 1 ¬⁄UˡÊÊÕ˸ ‚fl¸¬˝Õ◊ •¬Ÿ ¬˝‡Ÿ ¬òÊ ¬⁄U ŸÊ◊Ê¢∑§ •ÁŸflÊÿ¸Ã— Á‹π¥ – Candidate
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kinds of plane figures are. B.2 LESSON PROPER Shapes can be polygons → A closed plane figure made up of line segments. | A polygon with 3 sides | A 4-sided figure with 4 right angles and opposite sides parallel and the same length | A 4-sided figure that has 4 equal sides and 4 right angles | A 4-sided figure that has exactly one pair of parallel sides | A 4-sided figure with 2 pairs of parallel sides and all sides the same length | A circle is also a plane figure. A circle
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1. Use the values given in the above triangle and find the value of B‚ b‚ and c. A. A+B+C=180 B. A+C=48+97=145 C. B=180-145=35 2. Two sides and an angle (SSA) of a triangle are given. Determine if the given measurements produce one triangle‚ two triangles‚ or no triangle at all. Sin B)/5=sin70/7 Sin B/5=0.9397/7 Sin B=0.6712 then B=42 or 138〗 B = 138 is impossible since 138 + 70 = 208 and exceeds 180 B=42 since 42+70 = 112 and less than 180 C = 180 – 112
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may use a soft pencil for any diagrams or graphs. Do not use staples‚ paper clips‚ highlighters‚ glue or correction fluid. Answer all the questions. Give non-exact numerical answers correct to 3 significant figures‚ or 1 decimal place in the case of angles in degrees‚ unless a different level of accuracy is specified in the question. At the end of the examination‚ fasten all your work securely together. The number of marks is given in brackets [ ] at the end of each question or part question. The total
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1 A pictorial view of an object is shown in fig.1. Draw to full size‚ its following views using ‘First Angle projection method’. (1) Front View – looking from direction ‘X’ (2) Top View (3) Side View Show dimensions using Aligned dimensioning system. Fig.2 shows two views of an object. Draw its isometric view. Draw the following views of fig.3. (1) Rear view (2) Bottom view OR Draw a right angle only with the help of compass & trisect the same with the compass only. Construct a curve‚ when the distance
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In ‚ is a right angle. Find the remaining sides and angles. Round your answers to the nearest tenth. 2. a = 3‚ c = 19 a. = 9.1°‚ = 80.9°‚ b = 18.8 c. = 14.5°‚ = 75.5°‚ b = 18.8 b. = 80.9°‚ = 9.1°‚ b = 18.8 d. = 75.5°‚ = 14.5°‚ b = 18.8 Answer A 3. What is the simplified form of sin(x + p)? a. cos x b. sin x c. –sin x d. –cos x Answer C Rewrite the expression as a trigonometric function of a single angle measure. 4. a. b
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washers are on the protractor and mark down on a piece of paper would angle it was at. These steps were repeated until three sub trials were conducted. A new trial would be conducted‚ adding 25 milliliters and would follow steps 1-8. Until three trials were conducted with 9 sub trials in total. Once all the trials were completed‚ I subracted the observed angles from 90 degrees. After that was done I found the tangents of all the new angles and multiplied them by the distance‚ 5.969 meters. The solutions
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