Simple and Fractional Distillation Experiment II Stancy Saji‚ 18 September 2014 Purpose Experiment II involved two kinds of distillation techniques: simple and fractional. Simple distillation was done to separate ethyl acetate—which has a usual boiling point of 77º—from a less volatile component‚ while fractional distillation was done to distinguish an ethyl acetate/n-butyl acetate mixture‚ which has boiling points of 77º and 125 º‚ respectively. Results and Discussion As previously stated the
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of this lab was to compare the action of a catalyst (enzyme) under different environmental conditions. This was determined by performing a variety of different experiments. The first experiment was performed by adding hydrogen peroxide to sand. Due to the fact that the sand was not soluble in the hydrogen peroxide‚ no reaction thus no catalyst were present. Manganese dioxide was also added to the hydrogen peroxide creating a moderately fast reaction thus leading to believe that an enzyme was present
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was hypothesized that the growth and seed pod production in the standard plants would increase when less competitors were present and that growth would be more affected by competition than seed pod production would be. The data in Figure 1 and Figure 2 support this hypothesis; the standard plant grew the most when it was in a container alone and‚ on average‚ produced more seeds when no competitors were present (Figure 1). Though growth and seed pod production had similar trends‚ the difference in growth
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Adriana Gutierrez AP Biology Lab 9 Analysis 1. For this experiment‚ what were the independent variable and the dependent variable? What were the constants? The independent variable of this experiment are the environmental factors that you are testing on the rate of transpiration‚ so our independent variables would be bright light‚ fan‚ dark‚ and misted. The dependent variable is the rate of transportation because this depends on whatever environmental factor the plant is placed. The constants
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observed on the slide. D. Sketch of Thymus Slide: Describe the structures you observed on the slide. Exercise 2: Immunity and the Immune Respose A. Describe what happened to the red and green food coloring after 45 minutes. The food coloring spread throughout some of the dish. B. Which sera was an antigen in section 2 of the dish? Describe what you observed in section 2 of the dish. After 3 days‚ there was no visible line of precipitation evident and therefore the result is inconclusive
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(Justification-2 Enzyme Inhibition) By quantitative balance‚ the total amount of Enzyme is [E] 0= [E] + [EI] + [ES] + [ESI]. By using a=1+[I]/KI and a′=1+[I]/K′I‚ it is followed by [E]0=[E]a+[ES]a′ This equation can be written like this‚ [E]0=(Km[ES])/([S]0)a + [ES]a′=[ES]( aKm/[S}0+a’)‚ because of Km=[E][S]/[ES] and [S]≈[S]0. V=kb [ES] =kb [E] 0/ (aKm/[s] 0+a’). Kb [E] 0 is Vmax. This is why V=Vmax/(a^’+aKm/[S]0). This equation can be rearranged like this‚ 1/V= a’/Vmax+(aKm/Vmax)1/[S]0‚ which is
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The Effects on Enzymes By Bailey Rose The Effects on Enzymes Bailey Rose 10/31/2011 Abstract In this lab exercise‚ the study of enzyme catalase‚ we viewed the breakdown of hydrogen peroxide into water and oxygen. The purpose was to isolate catalase from starch and measure the rate of activity under different conditions. Changes in temperature and pH along with Substrate Concentration and Enzyme Concentration were the conditions tested in the experiment. Our class performed
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to increase in direct translation to the concentration increasing. The theory surrounding this lab was to see in practice how density could be determined with displacement and then to determine whether the density does in fact increase directly with the concentration. Summary of Key Data Figure 1: From Part 1 Mass of Brass 13.2200g Initial Volume 16.86mL Finial Volume 18.45mL Figure 2: From Part 2 Mass of the Empty 50-mL Flask 37.393g Weight of Flask Filled with 50-mL of Water 87.096g Weight Closest
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| AP Biology Lab #5: Cell Respiration | | | | | | Brian Suarez Completed with Yeonah Suk‚ Michelle Lee‚ and Agron 12/14/12 SBS21X (Period 1 & 2) Ms. Brady Brian Suarez Completed with Yeonah Suk‚ Michelle Lee‚ and Agron 12/14/12 SBS21X (Period 1 & 2) Ms. Brady Introduction To be able to carry on metabolic processes in the cell‚ cells need energy. The cells can obtain their energy in different ways but the most efficient way of harvesting stored food in the cell is through
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Computer Enzyme Action: Testing Catalase Activity 6A H2O2 is toxic to most living organisms. Many organisms are capable of enzymatically destroying the H2O2 before it can do much damage. H2O2 can be converted to oxygen and water‚ as follows: 2 H2O2 → 2 H2O + O2 Although this reaction occurs spontaneously‚ enzymes increase the rate considerably. At least two different enzymes are known to catalyze this reaction: catalase‚ found in animals and protists‚ and peroxidase‚ found in plants. A great
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