Ampere’s Law Jessica Warfield Partner: Rachel Beckner TA: Joel Mazer March 15‚ 2012 Conclusion: This experiment clearly demonstrated how Ampere’s Law relates the magnetic field to the current using the relationships stated in the formula B= μ0I2πr. This relationship allowed to the experiment to calculate the value of permeability of free space in order to verify the relationship that is outlined in Ampere’s Law. This lab also allowed us to measure magnetic field strength as a function of
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SUGGESTED INVESTIGATORY PROJECTS CLASS XII 1 To study various factors on which the internal resistance/emf of a cell depends. 2. To study the variations‚ in current flowing‚ in a circuit containing a LDR‚ because of a variation. (a) in the power of the incandescent lamp‚ used to ‘illuminate’ the LDR. (Keeping all the lamps at a fixed distance). (b) in the distance of a incandescent lamp‚ (of fixed power)‚ used to ‘illuminate’ the LDR. 3. To find the refractive indices of (a) water (b) oil
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ESO210/ESO203A: Introduction to Electrical Engineering Assignment 4 Date of Submission: 20th March‚ 2013 1. The rotor shown in Fig.1 has two coils. The rotor is nonmagnetic and and is placed in a uniform magnetic field of magnitude B0 . The coil sides are of radius R and are uniformly spaced around the rotor surface. The first coil carrying a current I1 and second coil carrying a current I2 . Assuming that the rotor is 0.30 m long‚ R=0.13 m‚ and B0 = 0.85 T‚ find the Θ directed torque as a
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My research is to determine if electricity moves better through thick wires or through thin wires. For this experiment I used two size D batteries‚ two flashlight bulbs‚ one 6.5 inch thin steel wool piece‚ one 6.5 inch thick steel wool piece‚ two 2 inch pieces of straw‚ and some electrical tape. Steel wool is a material made from thin fibers of steel made into a pad. (http://www.wisegeek.com/l-what-is-steel-wool.htm) There are many uses for steel wool. It can be used for sanding furniture‚ removing
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KWEKWE POLYTECHNIC BACHELOR OF TECHNOLOGY DEPARTMENT BACHELOR OF TECHNOLOGY (HONOURS) IN ELECTRICAL ENGINEERING In Affiliation with NATIONAL U7NIVERSITY OF SCIENCE AND TECHNOLOGY (NUST) Course: Electromagnetic Fields 1 Paper Code: EPE 4102 Date: Time: REQUIREMENTS: 1. Answer book 2. Calculator INSTRUCTIONS
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Seat No.: _____ Enrolment No.______ GUJARAT TECHNOLOGICAL UNIVERSITY B.E. Sem- 1st Regular Examination January 2011 Subject code: 110005 Subject Name: Elements of Electrical Engineering Date: 07/ 01 /2011 Time: 10.30 am - 01.00 pm Total Marks: 70 Instructions: 1. Attempt all questions. 2. Make suitable assumptions wherever necessary. 3. Figures to the right indicate full marks. Q.1 Three resistances Rab‚ Rbc and Rca are connected in star. Obtain their equivalent for delta resistances
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The Five Competitive Forces Model In this section‚ the structure of our company will be explained using the five competitive forces model developed by Harvard professor Michael Porter. These forces include: rivalry among existing firms‚ threat of new entrants‚ bargaining power of buyers‚ threat of substitutes and bargaining power of suppliers. Each of these forces will have their own distinctive effect on determining industry profitability. Intensity of rivalry among competitors: Recently there
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Series and Parallel Circuits Name: Angelica Castro Directions: 1. Go to the following website: http://phet.colorado.edu/en/simulation/circuit-construction-kit-ac-virtual-lab 2. Click “Run now.” You now have the raw material to create a circuit. Take a moment to look over the site and find all the different materials. To build a circuit you will need several wires‚ a light bulb‚ a voltage source‚ a voltmeter‚ and a non – contact ammeter. Play with it to see how to grab and manipulate
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Week #7 Chapter 10 Static and Current Electricity Exercises (p.221) 6. Strictly speaking‚ will a penny be slightly more massive if it has a negative charge or a positive charge? Explain. A negative charge because when it is negatively charged electrons are added to the penny. 17. What is the voltage at the location of a 0.0001 C charge that has an electric potential energy of 0.5 J (both voltage and potential relative to the same reference point)? Potential = energy Charge = 0.5 J / 0.0001
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CHAPTER 2 CAPACITOR & DIELECTRIC Subtopics 2.1 2.2 2.3 2.4 Capacitance‚ Capacitor in series & parallel Charging & discharging of capacitors Capacitors with dielectric Energy stored in a charged capacitor 2.1 Capacitance‚ Capacitor in series & parallel Learning Outcomes: At the end of this topic‚ students should be able to: Define capacitance Use the capacitance formula Determine capacitance of parallel plate Deduce & calculate the effective capacitance of capacitors in series & parallel
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