to $2‚500. How large a sample should they take? The margin of error for this confidence interval for the mean is 100=Z*SD/sqrt(n). To solve for N: sqrt N=Z*SD/1.645‚ now square both sides: N=[Z*SD/100]^2 The Z score for a 90% confidence interval is 1.645. The SD standard deviation is 2500-600=1900 1900/4 N=[1.645*(1900/4)/100]^2=62 A sample of 62 is needed. Your sample data has mean 3.1948 and standard deviation 0.0889‚ with a sample size of 25. X (bar) = 3.948‚ s =0.0889‚ n = 25 Use
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Human Body Recognition and Tracking: How the Kinect Works Kinect RGB-D Camera • Microsoft Kinect (Nov. 2010) – Color video camera + laser-projected IR dot pattern + IR camera • $120 (April 2012) • Kinect 1.5 due 5/2012 IR laser projector color camera T2 IR camera Many slides by D. Hoiem 640 x 480‚ 30 fps What the Kinect Does How Kinect Works: Overview Get Depth Image IR Projector IR Sensor Projected Light Pattern Stereo Algorithm Segmentation‚ Part Prediction
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Variance Variable Mean First Quartile Q1 Median Q2 Third Quartile Q3 Range Standart Deviation Opening Gross Sales 9.37 0.06375 0.39 12.43025 108.43 18.87470211 Total Gross Sales 33.04 0.40275 5.85 47.43475 380.15 63.16469269 Number of Theaters 1‚277.94 45.75 410 2626.5 3905 1378.689444 Weeks in Top 60 8.68 3 7 13 26 6.389511608 Opening Gross Sales represent how anticipated and well received the movie is. Of the 100 movies the mean opening sale is $9.38 million
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ASSIGNMENT (2015-16) 1. During a socio-economic survey conducted in a rural area‚ the concerned authorities came to the conclusion that mean level of income in the area was Rs 150 per month with a standard deviation of Rs 20 and that income is approximately normally distributed. The total population of the area was 4000. Compute the number of people who fell into the following categories: (i) monthly income less than Rs 50 (ii) monthly income greater than Rs 100 but less than or equal to
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PROGRAMMING Programming assignment #1 Mean and Standard Deviation INTRODUCTION In this programming assignment you are required to understand the problem definition given below‚ solve the problem‚ program your solution in the C++ programming language‚ and document your solution. PROBLEM The mean (average) and standard deviation calculator allows the user to enter the name of a class and 10 scores. The calculator then displays a message as follows: SummerCS115test1: mean = 75.7 and standard deviation
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look? Did anyone judge you? How would you feel getting judge? To me I never did judge people by their cover‚ I rather meet them in their inside than their outside because their inside is what tells you who they really are whether their nice‚ sweet‚ mean or shy. But people this day tend to judge a book by its cover. They judge the way they look not knowing what’s inside of them. In “Lamb to Slaughter” by Roald Dahl‚ police officers did judge Mary Maloney because the way she look and acted-like an innocence
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to 6th September‚ 2012. The study surveyed 120 Airtel customers to determine the key factors that significantly influence on their perceptions. In the study‚ data have been collected by questionnaires. They are analysed by statistical tools namely mean‚ standard deviation (SD) and coefficient of correlation. This paper reports the findings from a survey on Airtel customers on these issues and tests a number of hypotheses pertaining to them. The result confirms that customer value is the most important
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contributes around 40% of its manufacturing output. The prospects of RMG sector‚ however‚ in Bangladesh not only depends on availability of cheap labor and government’s liberal policy but also depends on compliance with codes of conduct. Compliance means to comply with something or 1 Senior Lecturer in Management‚ Department of Business Administration‚
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QUEUING THEORY INTRODUCTION Waiting lines are the most frequently encountered problems in everyday life. For example‚ queue at a cafeteria‚ library‚ bank‚ etc. Common to all of these cases are the arrivals of objects requiring service and the attendant delays when the service mechanism is busy. Waiting lines cannot be eliminated completely‚ but suitable techniques can be used to reduce the waiting time of an object in the system. A long waiting line may result in loss of customers to an organization
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1.972 175 180 22 / 200 3.21‚ p-value = .0015. There is enough evidence to infer that the population mean is not equal to 180. b t x s/ n 175 180 45 / 200 1.57‚ p-value = .1177. There is not enough evidence to infer that the population mean is not equal to 180. c t x s/ n 175 180 60 / 200 1.18‚ p-value = .2400. There is not enough evidence to infer that the population mean is not equal to 180. 269 d. As the s increases‚ the test statistic increases and the p-value increases
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