$6‚202.70. If the company is paying 9% interest per year‚ how many loan payments must the company make? A) 15 B) 13 C) 12 D) 19 6) ________ annuities involve depositing money at the end of the period and allowing it to grow. A) Discount B) Compound C) Annuity due D) Both B and C 7) When comparing annuity due to ordinary annuities‚ annuity due annuities will have higher: A) present values. B) annuity payments. C) future values. D) both A and C. E) all of the above. 8) Gina Dare‚ who
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Synthesis and IR Analysis of trans-[Bis(inosinato)palladium(II)] Abstract In this lab we synthesized trans-[Bis(inosinato) palladium(II)] for IR analysis. After completion of the reaction 84.4% of the product was collected. IR spectrum of the product and inosine was analyzed to determine how the inosine is bonded to the metal‚ palladium. From the IR analysis‚ it was determined that when inosine reacts with palladium‚ a shift of about 65 cm-1 in the carbonyl stretch was observed. Introduction:
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worth more than a dollar received a year from now. Thus if we are to logically compare projects and financial strategies‚ we must either move all dollar flows back to the present or out to some common future date. CHAPTER OUTLINE I. Compound interest results when the interest paid on the investment during the first period is added to the principal and during the second period the interest is earned on the original principal plus the interest earned during the first period. A
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Separation of a Mixture: Unknown # 12-Green Chemistry 221 with Professor Thomas Quale May 2012 Formal Lab Report Abstract An unknown sample‚ # 12-Green‚ was separated into its individual variable components‚ iron‚ ammonium chloride‚ silicon dioxide‚ and sodium chloride. The techniques used to separate the components of unknown # 12-Green‚ magnetism‚ sublimation‚ extraction‚ and filtration‚ were chosen based on the unique properties of each component. Using these separation techniques‚ each substance
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Chapter 4 15. For discrete compounding‚ to find the EAR‚ we use the equation: EAR = [1 + (APR / m)]m – 1 = .0719‚ or 7.19% EAR = [1 + (.07 / 4)]4 – 1 EAR = [1 + (.16 / 12)]12 – 1 = .1723‚ or 17.23% = .1163‚ or 11.63% EAR = [1 + (.11 / 365)]365 – 1 To find the EAR with continuous compounding‚ we use the equation: EAR = er – 1 EAR = e.12 – 1 = .1275‚ or 12.75% 23. Although the stock and bond accounts have different interest rates‚ we can draw one time line‚ but we need to remember to
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1. 2. Qualitative Density 3. 4. Potential energy chemical equation 5. 6. kinetic energy physical properties 7. 8. particulate submicroscopic 9. 10. hypothesis intensive properties 2. The ratio of the mass of an object to its volume 4. A written representation of a chemical reaction‚ showing the reactants and products‚ their physical states‚ and the direction in which the reaction proceeds 6. 1. Nonnumerical experimental
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be used to compute such useful information as car‚ mortgage and other loan payments. Another use of time value of money in accounting is reporting of certain long-term assets and liabilities. Time value of money is based on the principle of compound interest. Each time there is a compounding period the new principal is increased by the interest from the previous period. Converting Before Using the Tables When using the tables‚ you may need to convert if‚ for example‚ in a lump sum
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Mr. Keshav Singh Kansana 1. The product of 2 numbers is 60 and their arithmetic mean in 8‚ find the numbers. 2. The monthly salary of a persona was Rs. 320 for each of the first three years. He next got annul increment of Rs. 40 per month for each of the following successive 12 years. His salary remained stationary till retirement when he found that his average monthly salary during the service period was Rs. 698. Find the period of his service. 3. Divide 36 into 6 parts in A.P such that the sum
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Suppose Mr X deposits each year Rs 500‚ Rs 1000‚ Rs 1500‚ Rs 2000 and Rs 2500 in his saving bank account. The interest rate is 5% yearly. He wishes to find the future value of his deposits at the end of 5th year. End of Amount Number of years Compound Future year deposited compounded interest factor Value Col (1) Col(2) Col(3) Col(4) (2) X (4) 1 500 4 1.216 608 2 1000 3 1.158 1158 3 1500 2 1.103 1654 4 2000 1 1.05 2100 5 2500 0 1 2500 FV=500 X (1.05)5+1000 X (1
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The interest rate expressed in terms of the interest payment made each period is called the _____ rate. A. stated annual interest B. compound annual interest C. effective annual interest D. periodic interest E. daily interest 5. The interest rate expressed as if it were compounded once per year is called the _____ rate. A. stated interest B. compound interest C. effective annual D. periodic interest E. daily interest 6. The interest rate charged per period multiplied by the
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