Chapter 13 Answers to Exercises 1. Identify three objects that might belong to each of the following classes: a. Automobile b. NovelAuthor c. CollegeCourse The students will have a variety of answers for these questions. Some examples might be: a. myRedChevroletCamaro‚ theBlackfordMustangWithTheDentThatBobDrives‚ thePorschee911ThatDonaldTrumpOwns b. Terry Brooks‚ Steven King‚ Ray Bradbury c. English Composition‚ Calculus‚ Physics 2. Identify three different classes that might contain
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Smbd – Assignment 4 Submitted to Prof. Ishwar Murthy 1 Introduction Mr. Debashish Chatterjee‚ owner of hotel Aria‚ is working on room booking policy to maximize the revenues. And specifically‚ he is working on the weekend operations in which the number of bookings are maximum. There are two types of bookings‚ Class I – One day bookings which start from SAT noon to SUN noon or SUN noon to MON noon and Class II – Two day bookings which start from SAT noon to SUN noon. The tariff of Class I booking
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UNIVERSITY OF TORONTO RSM 222 H1S MIDTERM EXAM‚ Winter 2011 Instructions: DURATION: AID ALLOWED: 1 hour 50 minutes Non-programmable calculator. Programmable calculators have to be reset before the exam. Total marks on the exam are 100 allocated as follows: Section I Marks Achieved 9 Multiple Choice Questions 3 marks each for a total of 27 marks II Short Answer Questions 18 marks III Problem 1: Job Costing 13 Marks Problem 2: Process Costing 12 marks Problem 3: CVP Problem 15 marks Problem
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Appendix I C1: Equity = Stock Price x Number of Shares Outstanding = $42.09 X 271.5 = $11‚427.435 million C2: Using Adjusted Beta formula: Adjusted Beta = 0.67* historical Beta + 0.33 = 0.67* 0.69 +0.33=0.79 C3: Using CAPM formula: KE = Krf + ß (Km-Krf) = 3.59%+0.79*6.7%=8.89% C4: Using rearranged DGM formula: KE =D1/P0 +g= 0.48(1+5.5%)/42.09 +5.5%=6.7% C5: Using redeemable bond formula: KD: 95.6= 100/ (1+KD/2)40 + 3.375(1-0.38)/(1+KD/2)n KD=4.52% C6: Using WACC formula: Rwacc =4.52*10.19% + 8
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quantity at the right time at the right place for the right price and to the right target customers (consumer) and it is the science of process having its presence in all sectors of the industry. The goal of logistics work is to manage the fruition of project life cycles‚ supply chains and resultant efficiencies. Logistics is concerned with getting (or transmitting) the products and services where they are needed or when they are desired. It is difficult to accomplish any marketing or manufacturing without
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1. Does Project 2007 function more like Microsoft Office Excel or Microsoft Office Access? Why? Complete Project Plan Schedule Creation & Integration with Resources along with Resource Allocation & Cost estimation is easier & unique to Project 2007. With knowledge of further VB Scripting or Macro creation – we can create these functions in all 3 application --Data is stored in Table Views; We have the capability for Charts; Time / Resource Allocation & Calculation; Database functionality (ODBC
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needs to followed to write a project proposal. The template given below follows the prescribed format. You can choose to study this template and download a copy of the same by clicking on the link given. Title of the Project: Name of the Organization: Location of the Project: Project Objectives Expected Outcome Priorities Market Analysis Implementation Techniques Budget for Project Team for Management Duration of Project: Read more at Buzzle: http://www
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Human Resource Management: Case Study | Nitish @ Solutions Unlimited Problem Definition: Nitish joined Solutions Unlimited on recommendation of his friend Arvind. He had a topsy-turvy journey in Solutions Unlimited with his compensation package being revised and severance pay first denied and then going through lots of negotiation. Also his role in the projects was not fixed. Also Nitish was been accused of being too demanding and he was accused for asking things which were not mentioned
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Hieu Nguyen – FIN 5309 Section 1 Assignment 1 2.3 Table 2.2 X=0 X=1 Total Y=0 0.15 0.07 0.22 Y=1 0.15 0.63 0.78 Total 0.30 0.70 1.00 With W = 3+6X and V = 20-7Y‚ we have: (W|X=0)=3 (W|X=1)=9 Total (V|Y=0)=20 0.15 0.07 0.22 (V|Y=1)=13 0.15 0.63 0.78 Total 0.30 0.70 1.00 a. E(W) = 3 x 0.3 + 9 x 0.7 = 7.2 E(V) = 20 x 0.22 + 13 x 0.78 = 14.54 b. = (3 – 7.2)2 x 0.3 + (9 - 7.2)2 x 0.7 = 7.56 = (20 – 14.54)2 x 0.22 + (13 – 14.54)2 x 0.78 = 8.4084 c. cov
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Q.1a) The following graph is EOQ model with planned shortages. Let the parameters from the basic EOQ model. d = constant demand rate K = setup cost for placing one order Q = order quantity h = inventory holding cost per unit of product per unit of time p = shortage cost per unit of product per unit of time S = inventory level just after an order of size Q arrives So‚ Q– S = Shortage in inventory just before an order of Q units is added Production or ordering cost per
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