xxx1 xxxxxx Ms. xxxx Biology 20 November 2013 Osmosis Lab Problem: What’s the order of the concentration for each solution and how does it affect the movement of water? Hypothesis: Experimenter thinks the order of the solutions according to their concentration is D‚A‚E‚C‚B‚ from smallest. And the water will pass through semipermeable tubing bag from low to high concentration to thin the concentration inside the bag. Osmosis is a diffusion of water particles and is one of the passive transport
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background information 1.1 Diffusion is the process which molecules dissipate into a solution evenly over a period of time. An example is putting sugar in your coffee‚ after a while if you don ’t mix the solution‚ the sucrose will over time‚ go through the process of diffusion and be distributed throughout the coffee. Osmosis is movement of H2O molecules passing through a permeable cell membrane to the less concentrated solution‚ eventually to reach an equivalent number of molecules on both sides of the cell
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Sucrose solution concentrations of 0M‚ .2M‚ .4M‚ .6M‚ .8M‚ 1.0M String Balance 6 beakers or plastic cups
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Egg How does the solution a cell is in effect the movement of substances into and out of the cell? Eggs were soaked in vinegar for twenty-four hours before the lab to dissolve the shell‚ then placed them into the distilled water. Then the eggs were taken out and dried by the paper towel to measure their weight on the electronic scale. First egg weighted 78.92g‚ most of the parts of it’s skin was white translucent‚ and was spongy. After the egg was submerged into the salt solution‚ it floated on
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information‚ Sales and Marketing must clearly define the exact requirements of the customer to ensure they are incorporated into the specification. There is no easy way of solving the design problem and transforming the specification into a design solution. Whatever the system whereby the initial specification is produced‚ the method used to translate it into the final design always follows a basic pattern and can be summarised in the following five steps. 1. Identification of the problem.
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concentration of the solution. Dependent variable: percentage changed in weight of the potato strips. Controlled variable: size of the potato strips‚ it can be controlled by cutting the length of the strips. Procedure: Table 1. Concentration of sucrose solution table Concentration/ M | Sucrose Solution/ ml | Distilled Water/ ml | 0 (Water) | 0 | 10 | 0.2 | 2 | 8 | 0.4 | 4 | 6 | 0.6 | 6 | 4 | 0.8 | 8 | 2 | 1 | 10 | 0 | 1. Prepared 6 solutions. 0.2M‚ 0.4M
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Mg2+ Determination using EDTA Linh Nguyen Chem 1212L – 165 Feb 08 ‚ 2014 Purpose and Procedure: The purpose of this experiment is using Compleximetric titration and EDTA to determine the concentration of Mg2+ in solution; and also calculating the percent by mass of MgO in the unknown sample. This procedure results no significant deviations. The procedure for the experiment is from the lab manual referenced below Laboratory Experiments for Chem 1211L & 1212L (6e)
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Project on Saturated Solutions: Measuring Solubility iC BS E.c om Index 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. Certificate Acknowledgement Objective Introduction Basic concepts Materials and Equipment Experimental Procedure Observation Conclusion Result Precautions Bibliography iC BS E .co m CERTIFICATE This is to certify that the Project titled ’Saturated solutions: Measuring Solubility ’ was completed under my guidance and supervision by Roll No. ________
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measuring the absorbance‚ the concentration of a chemical substance can be determined. For the calibration of the colorimeter‚ different concentrations of a standard solution and a control (distilled water) are prepared in cuvettes. These cuvettes are put into the colorimeter one by one to calibrate it. After the colorimeter is calibrated‚ solutions of the substances which their concentrations are wanted to be determined‚ are put into cuvettes and their concentrations can be determined by this process (Dubey
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CHEM 3411‚ Fall 2010 Solution Set 5 In this solution set‚ an underline is used to show the last significant digit of numbers. For instance in x = 2.51693 the 2‚5‚1‚ and 6 are all significant. Digits to the right of the underlined digit‚ the 9 & 3 in the example‚ are not significant and would be rounded off at the end of calculations. Carrying these extra digits for intermediate values in calculations reduces rounding errors and ensures we get the same answer regardless of the order of arithmetic
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