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    Specific Heat Summative

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    STAGE 1 PHYSICS ASSESSMENT TYPE 1: INVESTIGATIONS FOLIO PRACTICAL INVESTIGATION 2: SPECIFIC HEAT PURPOSE This assessment provides the student with the opportunity to demonstrate their ability to: formulate hypotheses and identify variables conduct an investigation collect‚ analyse and interpret data‚ and form conclusions evaluate results communicate your understanding of the physics concepts relating to the speed of sound in air DESCRIPTION OF ASSESSMENT Students will measure the

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    Heat of Fusion of Ice

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    Ailine Veiga Question: what is the heat of fusion of ice? Hypothesis: To get the heat of fusion of ice we need to determine the Energy it takes to melt the ice and also the mass of the ice and determine the heat of fusion. To determine the mass of the ice melted (m) we start by determine the volume of the water generated when the ice melted. This is the difference between the final volume (v2) and the initial volume (v1). Using the density of water (1.0g/mL)‚ this volume can be converted into mass

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    Candle Heat Lab

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    lab‚ we are now able to calculate the molar heat of combustion for paraffin‚ since we have the difference of the mass in candle before/after and the periodic table of elements (for converting g to moles of paraffin). Molar heat of combustion = (kJ of heat)/(mole of fuel) However‚ we do not know how much heat was released nor the mole of fuel (paraffin). In order to find the amount of heat released‚ we use the formula: g=mcΔT. Here‚ g represents the heat‚ m represents the mass of water‚ ΔT represents

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    Heat Pump Lab

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    MECHANICAL ENGINEERING 449 SENIOR LAB Test of a Heat Pump Submitted Submitted by: Submitted to: Executive Summary: The purpose of this experiment was to determine the performance values of a Hylton Air and Water Heat Pump System. The system uses refrigerant 134a and water as the working fluids. The power input of the system was measured. The rate of heat output and the coefficient of performance are to be determined

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    Heat Hydration of Cuso4

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    sulphate is dissolved in water is first determined. Secondly‚ the enthalpy of solution of copper(II) sulphate pentahydrate in water is determined. ‚ Thirdly‚ the enthalpy of hydration of copper(II) sulphate is evaluated by using Hess’s Law of Constant Heat (Enthalpy) Summation. ------------------------------------------------------------------------------------------------------------------------- Theory: 1. Define the terms ’enthalpy of solution’ and ’enthalpy of hydration’. 2. [pic] is the enthalpy

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    Name: ______________________________________ Date: ________________________ Student Exploration: Heat Transfer by Conduction Vocabulary: conduction‚ convection‚ insulate‚ radiation‚ thermal conductor‚ thermal energy‚ thermal insulator Prior Knowledge Questions (Do these BEFORE using the Gizmo.) Suppose two frying pans have been left on the stove with the burners on. One of the frying pans has a metal handle and the other has a wooden handle. 1. Which handle do you think you could

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    Conduction Heat Transfer

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    situation for thick pipes is‚ however‚ more complex. [pic] The figure shown above represents the condition in a thick walled pipe. The area for heat flow is proportional to the radius – as may be seen‚ the area at the outside wall of the pipe is much greater than the middle. As a result the temperature gradient is inversely proportional to the radius. The heat flow ‘per unit length of pipe’ at any radius r‚ is [pic] cf. [pic] Note: Area‚[pic] Note there is no length of pipe (l) in this equation

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    Rh Bill

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    Representatives as a result of re-introducing the bill under a different impression after overwhelming opposition in the country‚ especially from the Catholic Bishops’ Conference of the Philippines.[2][3] The law is highly divisive and controversial‚ with experts‚ academics‚ religious institutions‚ and major political figures supporting and opposing it‚ often criticizing the government and each other in the process. Debates and rallies proposing and opposing the bills‚ with tens of thousands of opposition particularly

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    Bill Gates

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    Bill Gates: Leader and Role Model William Cook COLL/148 August 14‚ 2011 Barbara Goldberg Bill Gates is an effective leader and leadership role model and he is my choice for a role a model. Bill Gates has demonstrated and employed good leadership skills to be a successful business man. He has also demonstrated why he is a good role model for those who want to become leaders themselves. I believe that I share many of the leadership traits with Bill Gates and that those traits will help me in

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    Steel and Heat Treatment

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    Steel and heat treatment MILD STEEL Mild steel is also called plain carbon steel. It is the most common type of steel and it price is pretty low. Its composition is around about 0.05%-0.29% carbon content. Mild steel has a relatively low tensile strength but the surface can be hardened through carburizing. It is mostly used where large amounts of steel needs to be formed eg structural steel MEDIUM CARBON STEEL Medium carbon steel has great wear resistance and is used for forged automotive

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