the computer system. Data and instruction must be entered to the computer before performing any competition. Data or instructions can be entered through input devices eg. Key board‚ or any other input devices. Input unit transferred this data into binary coded in short input unit performs the following function: It accepts data or instructions from external world. It converts these instructions and data in computer acceptable form. It supplies the converted instruction & data to the computer
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BCA SEM I / BCA 1040 / Unit 1 Logic Design Self Assessment Questions 1.2 1. Decimal means base __________. 2. The decimal value of the bit pattern 11111111 is _________. 3. The range of values represented by an 8-bit binary number is _____. 4. The binary equivalent of 228 is _________. 5. The result of 7 – 2 using 1’s complement notation is 6. The bit pattern 1011 in 1’s complement notation is 7. The result of 7 – 2 using 2’s complement notation is 8. The bit pattern 1110 in 2’s complement
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data processing B) base 10 C) application D) binary 6) ________ binary digits (or bits) combine to create one byte. 6) _______ A) Sixteen B) Ten C) Eight D) Two 7) The term "bit" is short for: 7) _______ A) binary language. B) megabyte. C) binary number. D) binary digit. 8) Computers process data into information by working
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2931 Exercise 1.1.2 22 21 20 4 2 1 1 1 0 4 +2 0 Decimal # 6 Binary # 1102 Exercise 1.1.3 21 20 2 1 1 1 2 +1 Binary # 112 Decimal # 3 Exercise 1.1.4 24 23 22 21 20 16 8 4 2 1 1 0 0 1 0 16 0 0 +2 0 Decimal # 18 Binary# 100102 Exercise 1.1.5 27 26 25 24 23 22 21 20 128 64 32 16 8 4 2 1 1 1 1 0 0 0 1 0 128 +64 +32 0 0 0 +2 0 Binary# 111000102 Decimal# 226 Exercise 1.1.6 156 28 12 4 27 26 25
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CS 11 Handout Outline I Basic computer concepts A Definition of a computer B Number systems and conversion C Types of programming languages Program Development Cycle A Problem Identification B Logic Formulation C Coding D Testing and Debugging E Storage and Maintenance Program Logic Formulation A Algorithms B Algorithm Representation 1 Flowchart 2 Pseudocode Programming Fundamentals A Data Types B Variables and Constants C Operators D Expressions Control Structures A Sequential B Conditional C
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Convert the decimal number 125 into binary. Use the division-by-two method shown in the following example. 125 /2 = 62 r=1 62 /2 = 31 r=0 31 /2 = 15 r=1 15 /2 = 7 r=1 7 /2 = 3 r=1 3 /2 = 1 r=1 1 /2 = 0 r=1 01111101 2.Convert your binary result back into decimal to prove your answer is correct. This is also shown in the following example. Weights = 128 64 32 16 8 4 2 1 Bits = 0 1 1 1 1 1 0 1 64 + 32 + 16 + 8 + 4 + 1 = 125 Task 2: Procedure 1.Convert the binary number 10101101 into decimal. Use
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Convert the binary number 1010110.1001 to decimal. 64 32 16 8 4 2 1 .5 .25 .125 .0625 1 + 0 + 1 + 0 + 1 + 1 + 0. 1 + 0 + 0 + 1 64 + 16 + 4 + 2 + .5 + .0625 = 86.5625 4. Convert the decimal number 1938.257 to hexadecimal. 1938 914 402 156 18 2 -1024 -512 -256 -128 64 32 -16 8 4 -2 1. 914 402 156 18 2 0 1 1 1 1 0 0 1 0 0 1 0 Binary 7
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each; 20 points total) 1. F 2. T 3. T 4. F 5. T 6. F 7. T 8. F 9. F 10. F Exercises #1 - #3‚ p.26 (10 pts. Each; 30 points total) #1. Convert the following decimal numbers to binary. 11 dec = 00001011 65 dec = 01000001 100 dec = 01100100 255 dec = 11111111 #2. Convert the following binary numbers to decimal. 1101 = 13 1000 = 8 101011 = 43 #3. What are the ASCII codes for each letter in your name? 83‚ 97‚ 109 Assignment #1 – Chapter #1 M/C Questions #
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Technological Institute of the Philippines Bachelor of Science in Electronics and Communications Engineering CS 100L2-ICDL / ES12FB2 Assignment # 3 Flores‚ Ian Peter Hanie D. Prof. Mon Arjay Fernandez Malbog Jan. 15 2013 Computer Number System Binary‚ hexadecimal‚ and octal refer to different number systems. The one that we typically use is called decimal. These number systems refer to the number of symbols used to represent numbers. In the decimal system‚ we use ten different symbols: 0‚ 1‚ 2
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(Task 1) Convert decimal number (125) into binary. 125 /2 = 62 remainder5 1(lsd) 62 /2 = 31 remainder0 o 31 /2 = 15 remainder5 1 15 /2 = 7 remainder5 1 7 /2 = 3 remainder5 1 3 /2 = 1 remainder 5 1 1 /2 = .5 remainder 0 1 .5 /2 = 0 remainder 0 0 Convert your answer back to decimal to prove your answer. 0 1 1 1 1 1 0 1 0+64+32+16+8+4+2+1=125 (task 2) Convert the binary number(10101101) into decimal.
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