Online Biology Lab Report Evolution Name______ A. Natural Selection 1. Record the number of beetles present in each of the three generations from the lab website. Generation|Orange Beetles|Green Beetles| 1st Generation|3|13| Later Generation|6|10| Last Generation|16|0| 2. Nature selected for the _______orange__________ beetles. 3. Nature selected against the______green________ beetles. B. Speciation 1. Why were wasp species A and B no longer able to mate with each
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1. By exhaling out carbon dioxide into the straw on top of the bromothymol blue indicator‚ the solution will turn the color blue into a yellowish-green color. When there is a presence of something that is acidic the BTB indicator changes its color into yellow/green. So in this case‚ the water with BTB and carbon dioxide exhaled into the flask creates a carbonic acid. As an aerobic activity increase than the carbon dioxide rate increases as well. 2. By exercising more‚ one’s body requires more
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Iodine is a test for starch while Benedict’s solution is a test for reducing sugars. When solution A is tested by benidicts test‚ the clear blue solution changed to a little reddish and brick red precipitate is formed.this result show that solution A is a reducing sugar. When carried out iodine test with solution A‚ the colourless solution remain unchanged . this tell us that starch is absent is solution A. When solution B is tested with Benedicts test‚ the clear blue solution remain unchanged‚ we
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Introduction: Living‚ microscopic‚ unicellular organisms can be identified as microorganisms. Fungi‚ Protista‚ Bacteria‚ and Archaeans are four kingdoms in the phylogenetic tree of life that consist of microorganisms. Amongst these microorganisms the prokaryotes were the first ones to arrive through evolution. The rest of the life forms as we see them evolved from these simple creatures‚ prokaryotes. The smaller prokaryotes were swallowed by bigger prokaryotes setting the stage for the origin of
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IB Biology Potato Lab Table 1: Trial Number | Concentration of Sucrose Solution (M) ±0.2 ml | Initial Mass of Potato Core Slice(g) ±0.1 | Final Mass of Potato Core Slices (g) ±0.1 | 1 | 0.0 | 7.7 | 9.3 | 2 | | 6.0 | 8.1 | 3 | | 6.2 | 7.4 | 4 | | 10.2 | 13.2 | 5 | | 8.7 | 10.3 | 6 | | 4.9 | 6.0 | 7 | | 9.2 | 10.4 | 1 | 0.2 | 5.8 | 6.0 | 2 | | 11.6 | 12.1 | 3 | | 2.5 | 3.1 | 1 | 0.4 | 14.4 | 13.9 | 2 | | 2.6 | 2.8 | 3 | | 8 | 6.5 | 1 | 0.6 | 7.3 | 5.3 | 2
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sure the executive management agrees. 5. What is the most important risk mitigation requirement you uncovered and want to communicate to executive management? What is the most important risk mitigation requirement to the executive management group? 6. Based on your IT mitigation plan‚ what is the difference between short-term and long term risk mitigation tasks and on-going duties? Short-term are risks that can be fixed rapidly and will (more than likely) not have long term effects on the long company
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11 ST Revision i) Multiply the following numbers and express in terms of a x 10k where 1 ≤a ≤ 10 and k ϵ Z: 3.2 x 104 5.6 x 10-2 ii) Add them and multiply by four. iii) Factorise x2 – 49 iv) Factorise 16x2 - 9 v) Factorise x2 – 7x + 12 vi) Solve x2 -7x + 12 = 0 vii) The first term of an arithmetic sequence is 8 and the common difference is 7. The nth term is 393. Find the value of n. viii) A geometric sequence has first term 2 and third term 32. Find the common Ratio. ix) Find
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SOCIAL DILEMMS CRISCYNTHIA MCWILLIAMS INTRODUCTION TO SOCIAL PSYCHOLOGY DORIE RICHARDS FEBRUARY 18‚ 2013 Our perception of ourselves can be one of many but the most important of our perception is determined by our behavior. What we think about ourselves is who we become. If we think we are inadequate‚ we will begin to act that way. If we feel positive‚ we will act that way. The trail forward towards
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BIOL 1364 LABORATORY EXERCISE 3 ________________________________________________________________________ INHERITANCE OF CHARACTERS Objectives of the Laboratory: i) Determination of the genetic control of seed colour‚ ie how many genes control seed colour‚ what sort of intra allelic (dominance relationship) and interallelic interactions (independent assortment vs epistasis) govern the inheritance of seed colour. ii) Understand the scientific process involved in studying character
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Dayanna Chiriboga 02/03/2015 Lab Report #1 Genetics 1 χ² Results : Phenotype Expected Expected Observed Ratio Counts Counts (Eͥ i) ͥ (Oi) Deviation (di) =(EiOi) di² = (EiOi)² di²/Ei Purple 75% 657 642 15 225 .34 Yellow 25% 219 234 15 225 1.03 Χ² = ∑ (di / Ei) = 1.37 According to the chi square chart values we are 80% confident that our hypothesis is correct
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