the difference in heart rates before and during intense exercise. Aim: The aim of the investigation was to discover how the heart rate varied with the intensity of exercise. The heart rate is a term describing the regularity of the cardiac cycle. The heart rate is the amount of times it contracts (beats) in a unit of time‚ nearly always per minute. At rest the adult female’s heart rate regulates 75 bpm (beats per minute) but this varies between people. If the heart rate is measured before‚ during
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metabolic rate are investigated. Hypothesis: With the information given‚ we tested the effects of given hormones on the body by using virtual rats. We expect to see a greater metabolic rate for the normal rat as opposed to the thyroidectomized rat. The hypox rat is expected to have the lowest metabolic rate. Metabolic rate will increase once thyroxine is injected. TSH will increase the metabolic rate of all the rats with
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Coursework Rates of Reaction Research The rate of reaction tells us how quickly a chemical reaction takes place. It is important for people in industry to know how fast a reaction goes. They have to know exactly how much of their product they can make each hour‚ day or week. In a shampoo factory‚ the rate might be 100 bottles per minute. We can’t work out the rate of a reaction from its chemical equation. Equations can only tells us how much product we can get. They don’t say how quickly
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........................................................... 53 III. Immunoassays ........................................................................ 70 1. Radio immunoassays ............................................................. 70 2. Enzyme linked immunoassays ................................................ 89 IV. Metabolism ............................................................................. 94 1. Carbohydrate metabolism....................................................
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factors that can influence the rate of diffusion through a membrane. Chemical kinetics plays a large part in diffusion. In order for a solute to passively diffuse through a membrane‚ it must line up with a pore in the membrane and pass through it (textbook 101). The concentration gradient is also important for diffusion because solutes diffuse from areas of high concentration to areas of low concentration (textbook page 101). There are different factors that can affect the rate of this diffusion. Our intent
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Chemical reactions are a part of everyday lives. Whether it is the burning of propane at a kitchen stove‚ or washing detergent reacting with dirt stains‚ chemical reactions are useful tools that have widespread applications. With so many reactions assisting our everyday activities‚ it is important that ways to optimise reaction rates are investigated. “Reaction rate‚ the speed at which a chemical reaction proceeds… may be defined in terms of the amounts of the reactants consumed or products formed
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would affect the growth rate. Also‚ we tested if fertilizer was even an impact in the growth rate of algae. Increasing the amount of the dependent variable (fertilizer) would affect the independent variable (growth of algae) negatively due to too much chemicals that are being applied to the independent variable. Which would kill the algae cells or at last damage them and either the algae would die or become weaker and won’t be able to grow as quickly as its normal rate. Stuti and I used 5 beakers
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Chong Molecular Biology CTW: Enzyme Kinetic Dr. Cruz 07/22/2010 Enzyme kinetics Introduction Enzymes are biological catalysts or assistants‚ without enzyme many of important processes of life could not happen. Most of enzymes are proteins that help speed up chemical reactions by lowering amount of activation energy needed for the reaction1. Enzymes are usually highly selective‚ only bind to specific substrate and convert it to product at a particular rate1. The rate of the reaction affects by substrate
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Link reaction The link reaction takes place in the mitochondrial matrix and its main function is to turn the pyruvate into acetate for the kerb cycle. During the link reaction the pyruvate molecule undergoes decarboxylation and dehydrogenation‚ the enzymes pyruvate decarboxylase and pyruvate dehydrogenase remove the carboxyl group (which becomes a carbon dioxide molecule) and removes the hydrogen atoms from the pyruvate molecule. The coenzyme NAD accepts the two hydrogen atoms and becomes reduced
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volume). 3. [10 points] The following reaction is found to be first order in A: A −→ B + C If half of the starting quantity of A is used up after 56 seconds‚ calculate the fraction that will be used up after 6.0 minutes. 4. [15 points] The rate law for the decomposition of ozone to molecular oxygen 3 O3 (g) −→ 3 O2 (g) is rate = k [O3 ]2 . [O2 ] The mechanism for this process is k1 O3 O + O2 k−1 k 2 O + O3 −→ 2 O2 Derive a rate law from these elementary steps. Clearly
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