also be cracked by thermal or steam cracking. ================================ Properties of Alkanes and Alkenes Alkenes have similar physical properties to the corresponding alkanes. They are both non-polar molecules with weak dispersion forces being the only intermolecular forces involved. Ethene‚ propene‚ and butenes are gases at room temp. as are the corresp alkanes. The higher alkenes‚ like the alkanes‚ are liquids. However‚ they are different chemically. ================================
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SYLLABUS FOR ENTRANCE TEST 2012 UNIVERSITY OF HEALTH SCIENCES LAHORE‚ PAKISTAN STRUCTURE OF ENTRANCE TEST PAPER 2012 Sr.# Subject No. of Questions 1. PHYSICS 44 2. CHEMISTRY 58 3. ENGLISH 30 4. BIOLOGY 88 TOTAL 220 CONTENTS PHYSICS Syllabus TOS Self Test Questions CHEMISTRY Syllabus TOS Self Test Questions ENGLISH Syllabus Self Test Questions BIOLOGY Syllabus TOS Self Test Questions PAGE# 1-5 6 7-9 10-21 22 23-28 29-34 35-36 37-44 45 46-51 PHYSICS
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Isolation of Eugenol from Cloves by Steam Distillation and its Identification by Infrared Spectroscopy Eim A. Chemist CHEM 303 June 16‚ 2005 INTRODUCTION “Essential oils” are the volatile components associated with the aromas of many plants.1 In this experiment‚ the essential oil eugenol (the main component of oil of cloves) will be isolated from ground cloves using the technique of steam distillation‚ which is often used to isolate liquid natural products from plants.2 The principle
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Jr.‚ 2013). This reaction is best used for making six membered rings with different functional groups. The reaction is called a 4+2 cycloaddition because a ring is formed by four pi electrons in the diene interacting with two pi electrons of the alkene or alkyne (Wade‚ Jr.‚ 2013). In this experiment anthracene was used as the diene and considered to be electron rich in the reaction. Maleic anhydride was the electron poor dienophile used in the reaction. The reaction converted two pi bonds into two
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positive result for the chloride test. Bromine Br2 (l or aq) A dark red liquid - orange-brown fumes‚ yellow-orange aqueous solution. The other common orange-brown gas is nitrogen dioxide (i) Shake with a liquid alkene. (ii) Mix with silver nitrate solution. (ii) Decolourised. See alkene test. (ii) Cream ppt. of silver bromide as in the test for bromide. (i) Forms a colourless organic dibromo-compound >C=C< + Br2 ==> >CBr-CBr< (ii) Ag+(aq) + Br-(aq) ==> AgBr(s) Any soluble bromide gives
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Subject Content Most of the objectives specified in this section relate to Knowledge with Understanding‚ although some indication has been given as to where the skills of Handling Information and Solving Problems may be developed. Teachers are reminded that‚ in the written papers‚ 40% of the marks are allocated to these higher ’thinking’ skills. In almost every section‚ students should therefore be given practice at dealing with unfamiliar situations so that these higher thinking skills can be developed
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IGCSE PRE-AICE CHEMISTRY 0620 OFFICIAL STUDY GUIDE Notes: To avoid any confusion concerning the symbol for litre‚ dm3 will be used in place of l or litre.Valence electrons are known as valency electrons for this test. Nature of Matter The states of matter are solid‚ liquid‚ and gas‚ in respective order of kinetic energy. State of Matter | Definite Volume | Definite Shape | Solid | Yes | Yes | Liquid | Yes | No | Gas | No | No | Diffusion:
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bond between two Carbon atoms‚ they are "unsaturated" hydrocarbons. Their names follow a similar pattern: ethene‚ propene‚ butene‚ pentene‚ etc..It is not possible to have "methene" because there have to be TWO atoms of Carbon in a molecule of an alkene. Think about it. Here is a general formula for the alkenes:By now you will have realised that the spelling of chemical names is very important. |
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Place asterisks at all of the asymmetric carbon atoms in the molecule shown below (prostacyclin). (b) Based on the number of asymmetric carbons‚ how many stereoisomers of prostacyclin are possible? 5. Hydrogenation of an alkene will yield an alkane. The alkane formed by hydrogenation of (S)-4-methyl-1-hexene (I) is optically active‚ while the one formed by hydrogenation of (S)-3-methyl-1-pentene (II) is not. Explain. I II 6. Draw and label a stereoisomer
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The E2 reaction performed began by dehydrohalogenating the 3-chloro-3‚ 7-dimethyloctane with potassium hydroxide in aqueous ethanol. The 3-chloro-3‚ 7-dimethyloctane will lose a hydrogen from three different carbons that cause the formation of three constitutional isomers. If the hydroxide ion attacks a hydrogen on the 3-methyl carbon‚ then 2-ethyl-6-methyl-1-heptene will be the product. If a hydrogen on the carbon-2 was attacked‚ then the product would be 3‚ 7-dimethyl-2-octene. If a hydrogen was
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