alkyl halides useful chemical reagents. Nomenclature According to IUPAC‚ alkyl halides are treated as alkanes with a halogen substituent. The halogen prefixes are Fluoro-‚ Chloro-‚ Bromo- and Iodo-. Examples: H Cl CH3 H F CH2CH3 fluoroethane trans-1-chloro-3-methylcyclopentane Often compounds of CH2X2 type are called methylene halides. (CH2Cl2 is methylene chloride). CHX3 type compounds are called haloforms. (CHI3 is iodoform). CX4 type compounds are called carbon tetrahalides. (CF4 is carbon
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was then recrystallized from methanol‚ yielding 0.128g of pale yellow crystals with a melting point of 131-135 oC. This represents 0.33% of the original mass of the two yolks. The cholesterol was then dissolved in ether and further purified by bromination with a bromine/acetic acid reagent and debromination with zinc powder‚ a series of aqueous washes‚ and a final recrystallization from methanol. Here‚ a yield of 28% was recovered from an initial mass of 100 mg of recrystallized material. The melting
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1. Which of the following are the products of a homolytic cleavage of a C-C bond of ethane? A) 2 B) CH3 CH3 C) H D) 2 + + CH3 CH2H3 CH3 Ans: A Chapter 11 Topic: Radicals Section: 11.1 Difficulty Level: Easy 2. Which of the following is the most stable radical? A) B) C) D) E) Ans: B Chapter 11 Topic: Radicals Section: 11.1 Difficulty Level: Easy 3. In the molecule shown below‚ determine which of the labeled bonds is
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Introduction: For this lab‚ the main focused involved alkanes and hydrocarbons. Essentially‚ the free-radical chain of chlorination of 1-Chlorobutne. Free radical-chains occur because alkanes are chemically unreactive with most agents. However‚ the free-radical chain allows a pathway of certain functional groups like alkyl chloride or bromides. In addition‚ chlorine atoms can possibly be made from molecular chlorine under low to mild conditions with the usage of a catalytic amount of an initiator
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Comparative functional identification and analysis of Carica papaya promoter in the model system Arabidopsis thaliana revealed post-transcriptional regulation of gene expression INTRODUCTION a a CaMV35S Poly-A hptII b 5’ 3’ RB eGFP Promoter Construct b 1975 66 759 42 759 Cp29-eGFP 1796 36 759 75 759 759 Primer 3’ 5’ Transcribed mRNA chain 36 39 42 45 Cp45 WT 27 kDa 7 DAP 600bp 14 DAP 14
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good "perspective" drawing. CH3 CH3 trans-decalin: two chairs CH3 CH3 CH3 norbornane skeleton: CH3 H3C CH3 2. The molecule trans-cyclooctene is known to exist. (It is chiral‚ by the way). Why is the analagous molecule trans-cyclohexene unstable? Far too strained to have a trans-alkene in a six-membered ring. H H H = H H H trans-cyclooctene (planar representation) trans-cyclooctene (perspective representation) trans-cyclohexene???? 3. Draw each of the following
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B) is a deactivator and an o‚p-director. C) is an activator and a m-director. D) is an activator and an o‚p-director. E) none of the above Answer: B 32) Which of the following is an intermediate in the bromination of toluene? A) 13 B) C) D) Answer: B 33) Provide the major organic product of the following reaction. Answer: 14 34) Provide the major organic product which results when PhCHOHCH3 is treated with a chromate (PCC- strong oxidant). Answer:
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substituted benzenes towards bromination will be determined‚ where bromine is dissolved in acetic acid. Materials and apparatus Test solutions: 0.2 M solutions in ethyl acetate: Benzene‚ chlorobenzene‚ phenol‚ nitrophenol‚ aniline and acetanilide. Measuring pipettes (5 mL) micro test tubes 0.05 M Br2 in 90% CH3COOH Pasteur pipettes 0.05 M Br2 in cyclohexane II. Schematic Diagram of the Procedure Relative Rates of Bromination Add 2 drops of 0.05 M
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Crystallization and Melting Points Organic Chemistry 221 9/19/2012 Intro/Purpose: The purpose of this lab was to use crystallization to separate a compound from a solvent and be able to choose the best solvent to do so. Then identify an unknown and verify purity using melting points. Solubility contributes to crystallization; because a solute has lower solubility at lower temperatures‚ which makes the solvent separate from the solution as a solid. This process is important to understand because
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TWS Chemistry 1013-231 Organic Chemistry I Name___________________________________ 2011 Exam#2 - Version 2 MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) Energy is __________ when bonds are formed and is __________ when bonds are broken; therefore‚ bond dissociation energies are always __________. A) consumed / released / endothermic B) consumed / released / isothermic C) released / consumed / endothermic D) consumed / released / exothermic
Free Chemical reaction Chlorine Organic chemistry