2. Use the passage below and your knowledge to answer the questions that follow. Methane reacts with bromine to give bromomethane and hydrogen bromide. The mechanism for the reaction is called free-radical substitution and involves hemolytic fission of chemical bonds. The reaction proceeds via initiation‚ propagation and termination steps. (a) By what mechanism does bromine react with methane? (b) Write a balanced symbol equation for this reaction. (c) Bonds break in this reaction
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compound Functional group(s) Alkanes CH3CH3 ethane C – C and C–H Alkenes CH2 = CH2 ethene C=C Chemical tests/Observations Add liquid bromine in ultraviolet light (or sunlight): White fumes of HBr liberated; decolourisation of bromine occurs slowly (a) Add Br2 in CCl4 at room temperature: Decolourisation of bromine occurs immediately CH2 = CH2 + Br2 → CH2BrCH2Br (b) Add acidified KMnO4 at room temperature: Decolourisation of KMnO4 occurs immediately CH2 = CH2 + [O]
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acid (cis isomer) to fumaric acid (trans isomers)‚ the differences in physical properties between this pair of cis-trans isomers and determine the stereochemistry of addition of bromine to butenedioic acid. Chemicals and Apparatus: 2 grams of maleic acid‚ 10 cm3 of concentrated hydrochloric acid‚ 10 cm3 of bromine water[1]‚ one 50 cm3 beaker‚ one 100 cm3 beaker‚ one 250 cm3 beaker‚ one 10 cm3 measuring cylinder‚ one piece of spatula‚ one piece of water glass‚ one glass rod‚ a few pieces
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through a cycle of 6 carbon atoms with 3 double bounds was proposed by Kekule in 1865: In some special conditions‚ benzene can be hydrogenated‚ the result being a cyclic hexane: | +3H2 | | Under the influence of light‚ chlorine or bromine addition at the benzene’s molecule giving hexachlorocyclohexane: C6H6 + 3Cl2 C6H6Cl6. With ozone‚ the benzene gives a trizonide‚ which by decomposing (with water)‚ passes in glycoxal. These addition reactions prove the following: benzene has a cycle
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iodine will be added to a test tube using a dropper in lieu of a graduated cylinder. Appearance of solution will be recorded. Then‚ 1mL of hexane will be added to the test tube mix. Observations of both layers will be recorded. Process repeated for bromine. For the third solubility test‚ 1mL of hexane will be added to a clean test tube. Then‚ 0.5mL of Clorox and 0.5M HCl (to make chlorine) are added. The color of each layer is noted. Part III: Electronegativity Testing This set of reactions
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Abstract 1‚2-dibromo-1‚2-diphenylethane was produced by the bromination of trans-stilbene through the addition of hydrobromic acid (HBr) and hydrogen peroxide (H2O2). This experiment was a greener bromination of stilbene because bromine was generated in situ and ethanol was used as the solvent. The melting point (243.30°C)‚ mass (.427g)‚ and percent yield (45.54) of the crystals were recorded. The FTIR was used to confirm that the product was produced. The peaks on the HNMR revealed
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BROMINATION OF ACETANILIDE OBJECTIVE Aim of the experiment was too brominate acetaldehyde to form p-bromoacetanilide. INTRODUCTION Acetanilide is a chemical compound with the chemical formula of C6H5NH(COCH3). It is a crystalline solid that is prepared by acetylation of analine and is widely used in the dye industry. This crystalline solid is an odourless solid chemical that has a flake or leaf like appearance. It is also known as N phenylacetamide‚ acetanil or acetanilide. Its former
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LAB REPORT! EXPERIMENT#5‚6! MANPREET KAUR KHAIRA! LAB PARTNER: VIAN RAIES! The purpose of this lab exercise was to perform the bromination of (E)-1‚2-diphenylethene (trans-stilbene) by addition reaction in which bromine was added across the double bond to yield a vicinal dibromide. The next step was to perform a double elimination reaction by product gained to synthesize an alkyne‚ that is‚ 1‚2-diphenylacetylene. The two major techniques used in this lab were TLC analysis and UV-vis spectroscopy
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(reduction of organic compounds). 2Na(s)+Cl2(g) → 2NaCl(s) Redox Reaction Experiments (Displacement Reactions) Halogens with Halides (Halogen Ions) Cl > Br > I (all ions added are in solution with other ions so that they are in ionic form don’t confuse bromine solution with sodium bromide). Silver nitrate can be used to test for halides (Cl- = white precipitate‚ Br- = pale cream precipitate‚ I- = pale yellow precipitate) Ammonia solution is added to the precipitates. Further testing involves adding dilute
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reaction that removed the pi bond from a molecule and adds covalent bonds with two new compounds. Halogenation or most commonly known as bromination is a reaction that breaks a pi bond and adds a halogen or in this case‚ a bromine to the molecule. This addition of the bromine can be very steroselective. Stereoselectivity can come from steric and electronic effects. Steric effect arise when two atoms ar brought close together‚ the resulting push of electrone clouds is what creates the significant
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