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    Chemical Basis of Life

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    ZOOL  1   Lecture  3   1   2   ¡    ¡  ¡  ¡  Chemical  substances  that  cannot  be  broken   down  to  simpler  forms  by  ordinary  chemical   reactions   Atom   Atomic  number   Atomic  mass   Compound   Molecule   Macromolecule   3     ¡  ¡  ¡  ELEMENT    Oxygen   Carbon   Hydrogen   Nitrogen   Calcium   Phosphorus   Potassium   Sulfur

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    1molecule = 2.8 x 1016 molecules 2.1 x 10-15 cm² 3. Moles of stearic acid in monolayer Average drops of stearic acid to make up the monolayer = 6 Average drops of stearic solution in 1 mL = 96 ml of stearic acid in monolayer = 6 / 96 = .0625 ml

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    Day 1: Buffer preparation First‚ the buffer was prepared by using the formula as follows: Figure 1: Calculation for prepare 0.5 M Tris buffer at pH 6.8 3.033 g of Tris was weighed and placed in 400 mL beaker. Then‚ 25 mL of distilled water was added into the beaker that contained Tris. The mixture was dissolved using the stirring rod‚ and then the magnetic stirring bar was placed in the beaker for further dissolve when measuring the pH. The pH meter was used to measure the solution‚ and the

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    Guinea Pig Ileum

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    (Legend) Figure 1. The concentration-response curve to ACh in the absence of a competitive antagonist. Each dose of ACh was added to an organ bath containing a section of Guinea Pig ileum and Tyrode’s solution at physiological temperature. The response to ACh was measured by the isotonic contractions of the ileum until the maximum response was reached for the dose‚ using an isotonic force transducer with metal counter-weight of approximately 0.5g. A wash

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    Potato Osmosis Lab

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    the 0.400M solution‚ the potato decreased in mass‚ this was due to the reason that the solution was hypertonic. There was a higher concentration of solute and lower concentration of water in the solution than there was in the potato cells. This led the water to travel down its concentration gradient‚ which was from a higher concentration (in the cell) to a lower concentration (in the solution)‚ which meant the potato cells lost water‚ therefore the potato lost mass. The 0.300M solution was also a

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    Using Sucrose Solutions to Determine Osmolarity of Potato Tubers Based on Weight By Thomas Pelikan Biology 200A Section 004 Kimberly Schmidt October 2‚ 2012 Abstract: In this experiment we were trying to determine the osmolarity of potato tubers by weighing them before and after incubating them in solutions of sucrose with varying molarities. To find the osmolarity we took a potato and used a cork borer to obtain seven samples of potato tubers. We then prepared seven beakers with concentrations

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    Potassium Iodide Lab

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    to measure the concentration of a specific chemical species in a solution. This was conducted in 2 stages. The first stage involved making a solution of potassium iodide. The potassium iodide was then diluted to several different concentrations that were ran in potentiometer to find the mV of each solution which would then be used to find the PH of the solution. After analyzing a sample of each concentration an unknown solution was compared. Along with the the unknown tap water and deionized water

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    water molecules around the sodium ions and chloride ions. STUDY GUIDE FOR CONTENT MASTERY CHAPTER 15 STUDY GUIDE FOR CONTENT MASTERY Solutions Section 15.1 What are solutions? In your textbook‚ read about the characteristics of solutions. Use each of the terms below just once to complete the passage. soluble solute solvent solution Because the sodium ion is positively charged‚ it attracts the negatively charged portion of the water molecule (the oxygen atom) and repels the

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    Potato Osmosis Lab Report

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    Osmosis and Scientific Method Lab Report Abstract The purpose of the lab is to see how different size potatoes have faster water movement depending on the concentration of sucrose it was placed in. We had two sized potatoes‚ 6g and 10g‚ and placed each in three different dilutions of sucrose at 0.5M‚ 0.1M‚ and 0.05M. We also placed a 6g and 10g potato piece in water to act as a control. Based on the weight percent change over 60 minutes‚ the 6g potato piece had faster water movement than the

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    Good Chemistry Questions

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    During the experiment‚ student dropped the flask containing 250 ml‚ 3 molar NaOH solution. Due to this 50 ml of solution out of 250 ml‚ had fallen on the floor. Thinking that teacher may punish him for this mistake‚ he replenished the left over solution with 50 ml of water. The new molarity of NaOH solution will be. (A) 2M (B) 3M (C) 2.5 M (D) 2.4 M 2.* Which of the following molarity values of ions in a aqueous solution of 5.85 % w/v NaCl‚ 5.55% w/v CaCl2 and 6% w/v NaOH are correct [Na = 23‚ Cl

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