MGT 623 Ocean Carriers Case Study 1) Do you expect daily spot hire rates to increase or decrease next year? According to the Case description‚ Exhibit 3 showed order booking and delivery schedule for bulk capsizes for coming years from 2001 to 2004. It was larger than the number of current fleet size in Exhibit 2. Thus‚ the spot hire rates would likely to decrease since capsizes are available. 2) What factors drive average daily hire rates? Daily hire rate were determined
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mass at sea level is 1 kg-force. 1-6C There is no acceleration‚ thus the net force is zero in both cases. 1-7 A plastic tank is filled with water. The weight of the combined system is to be determined. Assumptions The density of water is constant throughout. Properties The density of water is given to be ρ = 1000 kg/m3. Analysis The mass of the water in the tank and the total mass are V =0.2 m 3 mtank = 3 kg mw =ρV =(1000 kg/m )(0.2 m ) = 200 kg 3 3 mtotal = mw + mtank = 200 + 3 = 203
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THE OSMOREGULATORY ABILITY IN PHASCOLOSOMA LURCA AND UCA COARCTATA Abstract Phascolosoma lurca (P. lurca) and Uca coarctata (U. coarctata) species and their organs were examined and studied to determine their osmoregulatory ability using the density of extracellular fluid (ECF) as a measure of ionic and osmotic concentration. Body fluids are denser than water which has a specific gravity of 1‚ plus solutes. Through the examination of the two organisms‚ P. lurca is an osmoconformer and U. coactarta
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retaining walls‚ earth dams‚ and airport‚ require man-placed soils‚ or fills. These soils are loose (weak) and must be compacted to increase their strength characteristics. • Soil compaction is defined as the method of mechanically increasing the density of soil by reducing volume of air. 2 General Principles • The densification is accomplished by pressing the soil particles together into a close state of contact with air being expelled from the soil mass in the process‚ thereby increasing
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71°C 3. Determine the mass of the water by using the water’s density (specific to the initial temperature) and the volume of the water. Remember‚ density =mass/volume. You can look up the density of the water at your specific temperature at http://www.ncsu.edu/chemistry/resource/H2Odensity_vp.html. (5 points) Density =mass/volume. Density of water according to NCSU: 0.9972995 g/mL Volume of water: 75.0 g/mL Find mass: Mass = Density * Volume Mass = 0.9972995 g/mL * 75.0
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1. A Little About Buoyancy o In order to understand how a boat can float in water we must first go over one of the principles behind such a feat: buoyancy. This principle in physics was discovered by the mathematician Archimedes about 2‚000 years ago‚ so it has been taught and understood for some time now. The basics of buoyancy involve the relationship between the weight of the object in question‚ in this case a boat‚ and the weight of the water it displaces. If the object weighs more than the
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Newtons. English (now American) system Feet‚ pounds (mass)‚ seconds‚ pounds (force) cgs system Density The density of a substance is defined as its mass divided by a unit volume ρ=M/V where ρ=density M=mass V=volume In the SI system the base unit for density is kg/m^3‚ whereas in the American engineering system density is commonly expressed as (lb_M)/(ft^3 ) (lb_M=pounds(mass)). Density of water SI system: 1 x 103kg/m3 = 1 g/cm3 American engineering system: 62.4 lbM/ft3.
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In the pasted years population has been growing rapidly in MEDC’s and LEDC’s‚ by looking at the crude birth rate and crude death rate we are able to see how the population grows in certain countries. Looking at how high the rates are in a LEDC country and a MEDC country‚ you are able to conclude that you can relate specific factors to different areas of the world. When looking at the population growth of a LEDC there are common factors that appear when looking at the death and birth rates. For
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Heidi Duncan 11/24/13 Exothermic and Endothermic Reactions Lab The purpose of this lab is to observe how heat is released or absorbed with different chemicals. Data Table 1 – HCI and NaOH Trial 1 Trial 2 Avg Volume 1.0 M HCI(ml) 25 25 - Volume1.0 M NaOH (ml) 25 25 - Ti of HCI before mixing 20 20 - Ti of NaOH before mixing( 20 20 - Average Ti before mixing( 20 20 - Tf of mixture ) 26 26 - T ) 6 6 - Specific Heat (J/g) 4.184 4.184 - Heat‚ q (J) 1255.2
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2. The mass of the package would be 2 kilograms. 3. The mass of the package would stay the same. 4. The volume of this object would be 80cm3. 5. The volume of the object would be 22mL and 22cm3 6. Density relates to volume and mass. 7. The density of this object would be 5g/cm3 8. The density of a material will always be the same because it’s the same material just in a smaller ratio. 9a. This mystery substance must be water. 9b. The mystery substance must be granite. 9c. the volume of 10
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