Complete Solutions Manual GENERAL CHEMISTRY NINTH EDITION Ebbing/Gammon David Bookin Mt. San Jacinto College Darrell D. Ebbing Wayne State University‚ Emeritus Steven D. Gammon Western Washington University HOUGHTON MIFFLIN COMPANY BOSTON NEW YORK Vice President and Executive Publisher: George Hoffman Vice President and Publisher: Charles Hartford Senior Marketing Manager: Laura McGinn Development Editor: Kate Heinle Assistant Editor: Amy Galvin Editorial Assistant: Chip
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SPM CHEMISTRY REVISION MODULE FOR THE MASTERY OF THE BASICS IN SPM CHEMISTRY Panel : 1. 2. 3. 4. June Ling S J Chen Soo Chien Felix Ngui Jong Kah Yin SMK St Joseph‚ Kuching Kolej DPAH Abdilah‚ Kuching SMK Tabuan Jaya‚ Kuching SM Sains Kuching REVISION MODULE FOR THE MASTERY OF THE BASICS IN SPM CHEMISTRY Page Compiled and edited by : Jong Kah Yin 1 SPM CHEMISTRY INDEX CONTENT 1 REVISION CHECK-LIST Form 4 Form 5 2 WRITING EQUATIONS 2.1 Charges of ions 2.2 Formulae of compounds
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the case in a Keq expression‚ regardless of which reaction (forward or reverse) predominates at a certain time. ********************************************************* The Keq Expressions for Solids and Liquids Consider the following reaction: CaCO3(s) CaO(s) + CO2(g)
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Descaling a coffee machine What is lime scale? Lime scale is a chalky white crust that is often built up on kettles and washing machines. The chemical name for lime scale is calcium carbonate‚ chemical formula CaCO3. It is usually caused by hard water (Water containing a higher than normal concentration of dissolved minerals such as calcium and magnesium). http://www.purewaterpeople.co.uk/blog/2013/06/what-is-limescale/ How is lime scale formed? Lime scale is built up over a long period of
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Calcination Studies of Limestone and Dolomite for CO2 Separation From Combustion Flue Gases”‚ International Gas Turbine Institute of ASME‚ 2008 [6] A [7] J.C Abandes‚ “The maximum capture efficiency of CO2 using a carbonation/calcinations cycle of CaO/CaCO3”‚ Department of Energy and Environment (CSIC)‚ 2002 [8] G.J Tzou‚ D.Y [10] Luis M. RomeoYolanda Lara‚ Pilar Lisbona and Jesús M. Escosa‚ “Optimizing make-up flow in a CO2 capture system using CaO ”‚ Universidad de Zaragoza‚ 2008 [11] M [12] B.M. Gopalasamy
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Imelda Galera De La Salle University-Dasmariñas Dasmariñas‚ Cavite Philippines ABSTRACT Chemical periodicity was demonstrated using different samples of elements from Group IA‚ IIA and IVA. These samples are: Li2CO3‚ Na2CO3‚ K2CO3‚ MgCO3‚ CaCO3‚ BaCO3‚ Carbon‚ Tin‚ Silicon and Lead. Each sample was placed in a test tube‚ (one sample and one test tube) and the physical color‚ appearance and state was defined. Water was used to test the solubility of the element. We use blue and red litmus
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mol Na2C03 x 106 g Na2C03 = 147 g CaCl2·2H2O 1 mol CaCl2·2H2O 1 mol Na2C03 Using 1 g of CaCl2·2H2O and .72 or .8 g (slight excess) Na2CO3 Should give a CaCO3 theoretical yield as follows: 1 g CaCl2·2H2O x 1 mole CaCl2·2H2O x 1 mol CaC03 x 100 g CaC03 = 147 g CaCl2·2H2O 1 mol CaCl2·2H2O 1 mol CaC03 To double-check‚ we can calculate CaCO3 theoretical yield by using Na2CO3 0.72 g Na2C03 x 1 mol Na2C03 x 1 mol CaC03 x 100 g CaC03 = 106 g Na2C03 1 mol Na2C03 1 mol CaC03 www.LabPaq.com 56 ©Hands-On
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becomes cloudy white as milk. Our breath contains carbon dioxide‚ and when it reacts with the limewater which contains Ca(OH)2 calcium hydroxide‚ it produces a new substance‚ CaCO3 calcium carbonate. 4. Write the equation(s) for the reaction that occur when the breath is blown through limewater. CO2(g) + Ca(OH)2(aq) CaCO3(s) + H2O(l) 5. Complete and balance the following (assume that complete oxidation occurs). a. CH4 +2O2 CO2 +2H2O b. C3H8 + 5O2 3CO2 +4H2O c. 2CH3OH + 3O2 2CO2 + 4H2O
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31.1% (actual yield/ theoretical yield). Overall‚ this lab has helped better the understanding of precipitation reactions and how it is applied to chemistry experiments. In addition‚ it provides fun facts such as the chemical formula for chalk is CaCo3 and that making chalk is not as complicated as one may
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yield)‚ divided by the mass of the precipitate that was hypothesized in the calculations (theoretical yield). This number was multiplied by a hundred to determine the percent yield (equation 4). Equation 1: Na2CO3 (aq) + Ca(NO3)2 (aq) CaCO3 (s) + 2NaNO3 (aq) Equation 2: n = OR mole = Equation 3: Percent Yield = × 100 Hypothesis: The law of conservation of mass states that the mass of the reactants must be equal to the mass of the products; no mass can be created
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