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    Standardization of Solution and Titration Lab Report‚ Preparing a Dilute HCl Solution from a Concentrated One Titrating NAOH Solution with HCl Solution (of Known Concentration) Chemistry lab report(by abdazino abdalla) International College Objective preparing a dilute HCl solution from a concentrated one titrating NAOH solution with HCl solution (of known concentration) Procedure Section A: Preparation of 100.0cm3 0.480 mol/dm3 HCl solution a)Determine the volume of the concentrated acid needed

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    Chemical Equilibrium

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    Chemical Equilibrium: Le Chatelier Principle By Sarah Ramos and Kristina Todorovic Chemistry 203 DEN Dr. Mohamed El-Maazawi Part A. Acid-Base Indicators Purpose In this part of the experiment‚ we will find a reagent that will shift the acid-base equilibrium reaction described by Equation (2) in one direction and then a second reagent that will cause the equilibrium position to shift back in the opposite direction. Introduction An acid–base indicator

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    KATE FITZPATRICK YEAR TWELVE BIOLOGY TERM ONE _(www.happycow.net)_ "TO TEST THE EFFECTS OF ANTACIDS ON PEPSIN’S ABILITY TO DIGEST PROTEIN." _CONTENTS_ 1.0 Abstract Pg 2.0 Introduction · 2.1 Aim · 2.2 Background Information · 2.3 Hypothesis PG · Pg · Pg · pg 3.0 MATERIALS · 3.1 Equipment · 3.2 Chemicals PG · Pg · Pg 4.0 METHOD · 4.1 Variables · 4.2 Procedure PG · Pg · Pg 5.0 RESULTS · 5.1 Sample calculation · 5.2 Tables · 5.3 Graphs · 5.4 Photos PG · Pg · Pg · Pg

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    standard solutions are used in determining the concentrations of other solutions to an extremely high accuracy. They are typically used in titrations and other analysis techniques as standardization solutions. A secondary standard solution‚ such as HCl solution‚ is a solution which must be standardized first against a primary standard‚ but afterwards‚ it will be stable enough for titrimetric work (Titration). Titration involves the gradual addition of a solution of accurately known concentration (standard

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    amounts of gastric acids. One of the abundant acids is Hydrochloric Acid (HCl); this acid has a pH level of 1. When there is too much acid in our stomach‚ it rises up to the esophagus‚ which causes the burning sensation known as heartburn. You can treat this if you take antacids‚ antacids are mild bases that can help neutralize the stomach and ends heartburn. GENERAL NEUTRALIZATION EQUATION: Acid + Base = H2O + NaCl HCl + NaOH = water + salt Purpose The purpose of this experiment was to

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    EXPERIMENT 2: SOLUTION PREPARATION AND STANDARDIZATION Submitted by Iris Olaso ______________________________________________________________________________ INTRODUCTION Generally‚ there are two ways in preparing a solution‚ one is by dissolving a weighed amount of solid in a required solvent and the other is by dilution of a concentrated solution into the desired concentration. In diluting concentrated solution‚ the concentration of the diluted solution can be determined by standardization

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    of oxalic acid (g) 3.162g Concentration of 100.00ml .2510M Table 2: NaOH Mass of NaOH + weigh boat 11.336g Mass of weigh boat .500g Calculated mass of NaOH 10.836g Moles of NaOH .2709mol Concentration of 500.0ml NaOH .5418M Table 3: HCl Volume of Concentrated HCl 10.00mL Concentration diluted to 250.00ml .5475M Table 2: Volume of NaOH needed to neutralize 10.00 mL of oxalic acid Trial 1 Trial 2 Initial reading of buret (mL) 16.39mL 9.89mL Final reading of buret (mL) 25.98mL 19.50mL Volume of

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    Hess Law

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    for three reactions: Reaction 1 Reaction Equation NaOH(s) → Na+(aq) + OH-(aq) Solid NaOH is dissolved in water 2 Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) → Na+(aq) + Cl-(aq) + H2O(l) Solutions of NaOH and HCl are mixed 3 NaOH(s) + H+(aq) + Cl-(aq) → Na+(aq) + Cl-(aq) + H2O(l) Solid NaOH is dissolved in a HCl solution The third reaction is actually a combination of the first two reactions. Notice that the equation for Reaction 3 can be obtained by adding together reactions 1 & 2. By calculating the heats

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    to obtain 50 mL of 0.862M HCl. It was added to the empty coffee cup calorimeter‚ and its initial temperature was obtained by using the MeasureNet. Using a graduated cylinder‚ 50 mL of 0.901M NaOH was added into the cup‚ and the final temperature was obtained. The solution was disposed‚ and the coffee cup calorimeter was rinsed with distilled water. The next experiments were performed. The acid was always added before the base. Experiment 2 consisted of 100 mL of 0.862M HCl and 100 mL of 0.901M NaOH

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    the acid in the solution are equal to the moles of the base (Survey of Chemistry lab manual). Using a dilution equation of M1xV1=M2xV2‚ the concentration of the hydrochloric acid can be calculated. M1=NaOH(molarity)‚ V1=NaOH(volume)‚ M2=HCl(molarity)‚ V2=HCl(volume). Procedure: Instructions for laboratory were found on page 91 of Survey of Chemistry lab manual. All calculations were rounded off by 2 decimal places for accuracy. Preparation of the indicator required a combination of 50 grams

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