slope of the equation to find the parallel lines by using the point slope formula. (4‚ 2) and m = ½ Use formula for equation of a line: m = mx + b Substitute the value of m into the equation y = 1/2 (x + b) Add the value for x into the equation y = (1/2)(4) + b Now put value of y in the equation 2 = (1/2)*(4) + b Now switch b so it can be on the opposite side of the equation (1/2) *(4) + b = 2 Multiply ½ by 4 to come up with 2 2 + b = 2 Reorder polynomials b + 2 = 2 Find be value: b
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1.Understand why effective communication is important in the work setting. 1.1 Identify the different reasons people communicate. There are many reasons why people have to communicate in work settings‚ here are a few :- Building relationships- When someone new joins the work setting e.g A child ‚ parent or colleague there will be some sort of communication either a smile‚ wave or a hello‚ this is the first part of communication and the beginning of building a relationship. Maintaining
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server based. 250 computers plus five servers will be attached to the network. A central switch/router is the easiest network device to reconfigure. A peer to peer topology will offer best access to the networks medians bandwidth. Case project 3.3 ENorm Inc.’s network will be server based with 105 computers attached to the network. With the given availability the best topology would be a physical star topology logical switch topology by means of physical star topology. For all three settings given
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Profit at this stocking quantity? 3 Ordering Level and Profits in Vertically Integrated
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Week 3 Homework Why study situational approaches to leadership? Researchers began to focus on what style of leadership was most effective in a particular situation with a particular manager. Contingency or situational theories look for the best fit between the leader and the situation and provide guidelines for a manger to achieve this fit. Managers adjust their decision making‚ orientation and motivational approach based upon a unique combination of factors in their situations for example
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Week 3 Homework Operant Conditioning molds behavior by the consequences of an individual through punishment‚ reinforcement and extinction. Observational Learning happens from observing the behavior of other individuals. Social Learning is a behavior learned from a social environment. Prejudice is developed and nurture through classical and operant conditioning from an early age when an individual acts prejudice towards something and is rewarded for acting in such a way or saying such things.
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Week 3 DQ 1: Due Day 2 Please post a 150-300-word response to the following discussion question by clicking on Reply. What is the difference between cash basis and accrual basis accounting? Why do accrual basis financial statements provide more useful information than cash basis financial statements? Describe when each method (cash basis and accrual basis accounting) would be appropriate to use. * Cash basis accounting recognizes revenues when cash is received and records expenses
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Checkpoint Week 4 XECO 212 Checkpoint Week 4 Axia College Material Appendix C Differentiating Between Market Structures Table and Questions Fill in the matrix and describe differences in public and private goods‚ common resources‚ and natural monopolies. Use your book and the Tomlinson video tutorials as a tool to help you answer questions about market structures. | Example | Is there a rival in consumption? | Is it excludable? | Private Good | Salad Bowl | Yes. I paid for it
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Team C Week 4 Summary David Ramirez‚ Kelvin Hemmingway‚ Chad Etzler ACC/291 August 26‚ 2013 Ins: James Covert Introduction As we advanced through week 4 of Principles of Accounting II‚ so far‚ we have absorbed ourselves with a litany of accountancy material. Week 4 continued with variety of content that contained: identifying kinds of shares issued by companies‚ computing shares‚ dividends‚ and stock splits‚ and documenting treasury stock deals. Also discussed in text and throughout discussion
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x2 – 2x = 13 2.) “Multiply each term in the equation by four times the coefficient of the x2 term.”: x2 – 2x = 13 4x2 – 8x = 52 3.) “Square the coefficient of the original x term and add it to both sides of the equation.”: 4x2 – 8x = 52 4x2 – 8x + 4 = 52 + 4 4x2 – 8x + 4 = 56 4.) “Take the square root of both sides.”: 4x2 – 8x + 4 = 56 2x – 2 = +/- √56 5.) “Set the left side of the equation equal to the positive square root of the number on the right side and solve
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