Macromolecules and Lipids Topic 1 Biological Molecules (Part 4) Lecture Presentation by Nicole Tunbridge and Kathleen Fitzpatrick © 2015 Pearson Education‚ Inc. Learning Outcome a) Describe structure and composition of nucleic acids‚ DNA and RNA. b) Discuss the importance of base pairing and hydrogen bonding. ©© 2015 Pearson Education Ltd 2011 Pearson Education‚ Inc. Concept 5.5: Nucleic acids store‚ transmit‚ and help express hereditary information a) The amino acid sequence of a polypeptide
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Experimen ChemiCal Basis of Chemical Basis of Life – Part I Carbohydrates H a n d s - o n l a b s ‚ i n c . Ve r s i o n 42-0144-00-01 LAB REPORT PHOTOS – Include two digital photos with your lab report‚ either as separate attachments to an e-mail or paste into your document. 1. Photo #1 – Take a photo of your finished experiment in exercise 2‚ testing for sugars. (The 3 test tubes after heating‚ but while still in the pan.) Be sure to take a view that shows the colors in all the tubes ^Picture
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Background: Lipid and protein composition varies in tissue types. Results: When comparing liver‚ muscle‚ and adipose tissue‚ adipose tissue had the highest percent lipid and liver tissue had the highest percent protein. Conclusion: Based on analysis of the gels‚ the liver appeared to have the most variety in proteins when comparing liver‚ muscle‚ and adipose tissue. Significance: In order to determine the composition of a tissue‚ specific macromolecules can be extracted‚ quantified‚ and analyzed
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boiled to find the boiling point and then identified using a chart of unknown identities and boiling points. The oxidation of the unknown alcohol was done through the mixing of the unknown alcohol‚ glacial acetic acid‚ and bleach. Through the procedure of oxidation over a period of two lab days‚
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Introduction: Proteins are necklaces of amino acids – long chains molecules. Proteins are the basis of how biology get this done. As enzymes‚ they are the driving force behind all the biochemical reactions which make biology work. As structural elements‚ they are main constituents of our bones‚ muscles‚ hair‚ skin‚ and blood vessels. As antibodies‚ they recognize invading elements and allow the immune system to get rid of the unwanted invaders. For these reasons‚ scientists have sequenced the
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Lab 7—Determination of Total Carbohydrates Using the Phenol-Sulfuric Acid Method This lab introduced the students to analyzing carbohydrate content using a spectrophotometer and phenol-sulfuric acid methods. Virginia Smith 983976633 Lab Partner: Jeff Martz Due Date: 3-22-11 Introduction The objective of this lab was to have students use a spectrophotometer to analyze the carbohydrate content in the sample. Phenol-sulfuric acid methods
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Acids and Bases Shane Purpose- To study the relationship between pH and metabolism. 10/21/13 Materials- see attached Per. D Biology Procedure- see attached Data and Results- see attached Theory- PH stands for the power of hydrogen. People refer to the pH scale as a tool for finding out if a substance is acidic‚ basic‚ or neutral. This scale goes from zero to fourteen. The number seven is neutral. Any number higher than seven on this scale is basic. Any number lower is acidic
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Daniel Bergey Lab 2: Proteins and Starches Purpose The purpose of lab 2 and both tests with proteins and starches is to determine which substance contains either protein or starch. Hypothesis Proteins: I predict that any substance I test that derives from a living organism is will test positive proteins. Any substance that isn’t from a living organism more than likely will test negative for proteins. Starches: I predict that any substance that contains any level of glucose will test positive
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Determining the Properties of Different Acids and Bases Yamin Liu November 16th‚ 2017 Chemistry 1021 Section: 427 Benton Smith Discussion of Results The goals of this experiment were to find the identities of four unknown compounds and to first determine the pH. We then were required to run a series of anion and cation tests to determine the composition of the unknown solutions. To get more knowledge about these solutions we ran a series of dilutions to see if
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CHM 3120L ANALYTICAL CHEMISTRY I LABORATORY REPORT EXPERIMENT: DETERMINATION OF ASCORBIC ACID BY REDOX TITRATION Name: Section: Date Experiment Completed: 2.0008 g KIO3 x (1 mol/214 g KIO3) = 0.0093495327 mol KIO3 0.0093495327 mol KIO3 / 0.500 L = 0.0186990654 M KIO3 6 Na2S2O3 + KIO3 + 6 H+ → I-+ 3 H2O + 3 S4O62- + K+ + 12 Na+ 0.0187 M KIO3 × 0.025 L = 4.675 x 10-4 mol KIO3 4.675 x 10-4 mol KIO3 x (6 mol Na2S2O3 / 1 mol KIO3) = 0.002805 mol Na2S2O3 0.002805 mol Na2S2O3
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