sucrose solutions of different concentrations and measuring the changes in mass of the apple cores. The changes in mass reflect the movement of water into or out of the tissue. After determining the concentration of sucrose solution at which there is no net gain or loss of water from the apple tissue‚ the osmotic potential can be calculated. This will then tell the water potential of the apple cells. Research Question and Hypothesis: How will changing the concentration of sucrose in solutions impact
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Equipment: Refer to Biology 12 Lab Manual – Investigation 13 Procedure: Refer to Biology 12 Lab Manual – Investigation 13 Data and Observations: The Potatoes change in mass after the process of Osmosis Test Tube # | Concentration of Sucrose Solution (mol/L) | Initial mass (g) | Final mass (g) | Change in mass (g) | Percentage change in mass (%) | 1 | 1.0 | 5.12 | 3.63 | -1.49 | 29.0% | 2 | 0.9 |
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Shanzhai case solutions sunny What are the environmental factors that help drive the Shanzhai phenomenon? * In china‚ peoples are fearless experimenter’s mindset. * Eye holes in regulations specified Shanzhai folks scope to grow. * protection law of IP is very poor. * Comparatively weak‚ inconsistent or non-transparent business policy. * Shanzhai performers are very flexible & efficient vendors. What characteristics are critical to the success of Shanzhai
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answered: c. It is a type of diffusion. 2. Which of the following occurs when a hypertonic solution is added to cells? You correctly answered: d. The cells shrink. 3. The variable that affects osmotic pressure is You correctly answered: a. the concentration of nondiffusing solutes. 4. The net movement of water would be into the cell in a Your answer : d. hypnotonic solution. Correct answer: b. hypotonic solution. 01/20/14 page 1 Experiment Results Predict Question: Predict Question 1:
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Simple Diffusion Activity 1: Simulating Simple diffusion 1.What is the molecular weight of Na+? 22.9 2. What is the molecular weight of Cl-? 35.45 3. Which MWCO dialysis membranes allowed both of these ions through? 50‚ 100‚ and 200 4. Which materials diffused from the left beaker to the right beaker? Urea‚ NaCl and glucose diffused 5. Which did not? Why? Albumin‚ because the molecular weight exceeded the highest MWCO membrane‚ thus being to large to pass through
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September 17th at the beginning of class. Show your work. 1. Match the differential equation in (a)-(c) to a family of solutions in (d)-(f). The point of this exercise is not to solve the differential equations in a) - c). (a) y = y 2 (b) y = 1 + y 2 (c) yy = 3x (d) y = tan(x + C) (e) 3x2 − y 2 = C (f) y = −1/(x + C) 2. Find the value of k so that y = e3t + ke2t is a solution of y − 2y − 3y = 3e2t . 3. Solve the following differential equations and IVP’s. You may solve these equations implicitly
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potato disks after they have been incubated in any sucrose solution. This means that the concentration of sucrose that the potatoes are in will no effect the movement of water in or out of the potato cells. However‚ the alternative hypothesis states that the mass of the potato disks will increase after they have been incubated in a hypertonic solution. The mass of the potato disks will decrease after they have been incubated in a hypertonic solution. After the results have been gathered‚ appropriate estimations
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for application in the dry state directly to the seed. DT Tablet for direct appli- Formulation in the form of tablets to be applied individually cation and directly in the field‚ and/or bodies of water‚ without preparation of a spraying solution or dispersion. EC Emulsifiable concentrate A liquid‚ homogeneous formulation to be applied as an emulsion after dilution in water. EG Emulsifiable granule A granular formulation‚ which may contain water-insoluble formulants‚ to
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Andrew Dickson Background When a plant cell is bathed in a solution of the same concentration (isotonic) as its intracellular environment‚ its mass and volume remain the same. This is because water enters and leaves the cells at the same rate. There is no net loss or gain of water by osmosis. Samples of cells can be placed in a range of solutions of different concentration. The cells will gain water by osmosis when placed in solutions which are more dilute (hypotonic) than the intracellular environment
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Experiment 1: Mixtures Aim: To develop an understanding of different types of mixtures including solutions and examine the different solubilities of some solutes and two solvents: water and ethanol Equipment Bunsen burner Tripod Gauze mat Beakers (2 x 100mL) Boiling chips Distilled water Sodium chloride Sodium chloride (solid) Glass rod Measuring cylinder (25mL) Ethanol Watch glass Thermometer 100% Orange Juice 100% Apple Juice 100% Prune Juice Solder Fruit Scone Charcoal Copper(II) Chloride Magnifying
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