01.07 Accuracy and Precision: Balance Lab Worksheet Calculations Show all of your work for each of the following calculations and be careful to follow significant figure rules in each calculation. 1. Part I: Density of Unknown Liquid 1. Calculate the mass of the liquid for each trial. (Subtract the mass of the empty graduated cylinder from the mass of the graduated cylinder with liquid.) Trial 1 36 - 25.5 = 10.5 Trial 2 36.5 - 25.5 = 11 Trial 3 36.9 - 25.5 = 11.4 2. Calculate the
Premium Accuracy and precision Density Volume
Ammonia and Hydrochloric Acid Lab Chemistry 1 Abstract The straw should be cut shorter to 8 cm in order to make the solid ring appear in the center of the straw. We achieved our goal‚ cutting the straw caused the gases to not have to go as far‚ and meet in the middle. Background The particles in a gas are very loose and tend to move around a lot very quickly. The particles in a solid are very compact and vibrate but don’t really move very much. The particles in a liquid however are more
Premium Gas Chemical reaction Chemistry
smaller than 0.85mm (Pass through 15 B.S. sieve) and bigger than 0.60mm (Retain at 25 B.S. sieve). A H M 531 Compressive and tensile strength of cement mortar By: Ahmed Essam Mansour The Civil Engineering Center 1 Visit www.AHM531.com for more lab reports and lecture notes! A H M 531 The Civil Engineering Center In the cement-sand mortar‚ the proportion between Cement and Sand is 1:3 and the W\C = 40%. The same mixture is used in the compressive test a nd in the tensile test. Apparatus
Premium Materials science Tensile strength Concrete
A. What is the name of the pigment that captures light? Chlorophyll B. Why does the pigment appear green? It absorbs other colors of light such as red and blue‚ so in a way the green light is reflected out since the pigment does not absorb it. 2. List two variables besides the wavelength (color) of light which might affect the rate of food production in plants. Light intensity and carbon dioxide 3. Why is chlorophyll important for all biological life? It is necessary for photosynthesis which
Free Photosynthesis Carbon dioxide Oxygen
peroxidase. The three conditions tested were the effect of peroxidase concentration on the rate of the experiment‚ the effect of pH of the rate of peroxidase activity‚ and the effect of temperature on the rate of peroxidase activity. During the lab‚ the lab group tested 7 test tubes‚ including 1 blank‚ with different amounts of pH 5 buffer‚ H2O2‚ Peroxidase‚ and Guaiacol. After the certain amount of mL per substance was mixed‚ the absorbance readings for the effect of peroxidase concentration were
Premium Enzyme Oxygen Chemical reaction
Through Dialysis Tubing (a Semi-Permeable Membrane) I. DESIGN A. PROBLEM/RESEARCH QUESTION 1. How does increasing molarity of sucrose affect osmosis through dialysis tubing? B. VARIABLES 1. The independent variable in this lab is the molarity of sucrose each dialysis bag is filled with. The time (30 minutes)‚ the temperature (23C) and the type of dialysis tubing used are all constants. 2. The dependent variable is the final mass of the dialysis bag. 3
Premium Semipermeable membrane Dialysis tubing
Question/Purpose: The Question or Purpose of our lab is to answer the question “How is the germination of a seed affected by sunlight?” Experimental Hypothesis: We believe these results will occur. 1. The seeds that are water deprived (1 mL of H2O a day) will not grow very well due to a lack of water which is important in photosynthesis and also lacks nutrients. The seeds may also die off due to a lack of water. 2. The seeds that are have a proper amount of water (10 mL of
Premium Plant Seed Plant morphology
The completed calculations can be found on lab notebook page 14. Using this data‚ graph 2 was generated showing the relationship between the intensity ratio and the concentration of chlorine. Relating to the Stern-Volmer equation of F0/F=1+KSV[Q] and the linear line equation of y = 124x + 1.08‚
Premium Spectroscopy Photon Atom
Physiology‚ Berry HOMEOSTASIS LAB ACTIVITY Introduction: Homeostasis means maintaining a relatively constant state of the body’s internal environment. The term used to describe a pattern of response to restore the body to normal stable level is termed negative feedback. When a stimulus (environment change) is met by a response that reverses (negates) the trend of the stimulus‚ it is negative feedback. As a result the internal environment is returned to normal. Pulse rate is constantly checked
Free Heart rate Physiology
This experiment was performed to demonstrate a cycle of chemical reactions involving copper. This lab will start with copper as a reactant in the first reaction through a series of five chemical forms of aqueous phase reactions and ending to calculate the percentage of recovered solid copper as a product in the last reaction of the experiment. The experiment resulted in a percent recovery from the cycle of copper reactions of an increase to 139%. . Introduction: The purpose of this experiment is
Premium Chemical reaction Chemistry Hydrogen