Cell Fractionation * Cell Fractionation: takes cells apart and separates the major organelles and other subcellular structures from one another. * Tissue cells are the first one to be homogenate or broken apart. * Plasma membranes are broken up so that there internal contents spill out and mix together and this is called homogenate. * Homogenate is in spun in a higher rate of speed in a process called centrifugation. And that speed can vary that why it’s called differential
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Cell Fractionation: Isolation of Mitochondria from Cauliflower and Determination of Specific Enzyme Kinetics Introduction Mitochondria is an organelle found in eukaryotic cells that play a role in biochemical processes such as respiration and energy production. Mitochondria even play an important role in apoptosis‚ or programmed cell death. This is achieved by disruption of electron transport‚ oxidative phosphorylation‚ and ATP production or even the release of proteins that trigger activation
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Cell Fractionation i) EQUIPMENT: Cold Liver‚ Blender‚ Gauze‚ Fridge‚ Isotonic Solution‚ Centrifuge‚ Tubes‚ Scalpel‚ HOMOGENIZATION • Take chilled liver tissue and cut into smaller pieces. • Place liver into blender with cold isotonic solution. • Blend until you have a thick soup like substance (homogenate). • Filter the mixture to remove large debris through gauze into a tube. DIFFERENTIAL CENTRIFUGATION • Attach tubes of homogenate to the refrigerated Centrifuge and turn on to spin
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STRUCTURE AND FUNCTION OF LIVING CELLS Name Answer the following questions as you work your way through the lab material typing in your answers. Then submit your completed lab report through the “Assignment” feature. This lab report is worth 50 points towards your final lab grade. Also‚ per the Honor Code‚ this work must be your own. CELLS Using your Biology Textbook answer the following questions. 1. What types of organisms are Prokaryotes? The Prokaryotes are organisms that are
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BioLab3 Cell Membranes Lab Report Student Name: I. Diffusion Define the following terms. Solvent Solute Solution. Diffusion Concentration gradient Dynamic equilibrium EXERCISE 1 – Factors influencing rate of diffusion Predict how molecule size and temperature will affect the outcome of this experiment. Record the data from the information in the lab. Potassium Permanganate R.T. Methylene Blue R.T. Time (min) Total Diameter
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a) Using a human cell of your choice‚ describe how organelles work together to make and secrete a protein (LO1. AC 1.1) An epithelial cell in the thyroid gland‚ called a thyrocyte forms spherical follicles that produce a protein called thyroglobulin. This is a globular protein that has a functional role in metabolism. The protein is used by the thyroid gland to produce thyroid hormones; thyroxine (T4) is an example of one of the hormones created. Thyroxine is formed by iodine binding to tyrosine
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Electrochemical Cells Lab Report AP Chemistry Block 1 Analysis: The purpose of Part 1 of this laboratory is to construct a table listing the reduction potentials of a series of metal ions in order of ease of reduction. The series of half-cells is constructed by placing a piece of metal into a 1.0 M solution of its ions for each metal in the series. The metals are Cu‚ Fe‚ Pb‚ Mg‚ Ag‚ and Zn. The half-cells are connected by a salt bridge constructed of a strip of filter paper soaked in a solution
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and centrifuged for 20 seconds. A polyacrylamide gel was assembled and the samples were loaded into it. The gel ran for approximately 45 minutes at 160 V. A western blot analysis was done in order to examine the Erk1/2 phosphorylation of the NIH3T3 cells. Three pieces of Whatman paper were wet in transfer buffer and placed on the anode plate. A wet PVDF membrane was placed on top of the Whatman paper. The gel was removed from holder and the stacking gel was removed. Forceps were used to place the gel
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TITLE AND AUTHOR Lab 7 Analysis of purified Concanavalin A via:Hemagglutination INTRODUCTION The purpose of this lab was to test the biological activity of ConA by performing a hemagglutination assay. If ConA is active then agglutination will occur due to ConA’s free receptors being able to bind to the glucose residues on the sheep’s red blood cells. If ConA is not active then no agglutination will occur. To test the hemagglutination reaction‚ two types of ConA solutions
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treatment of a pH shock and neutralization‚ by depicting a constant percentage of immobile cells. Prior to the lab series‚ it was expected that the positive control would present a decreasing percentage of immobile cells‚ and the negative control would present an increasing percentage of immobile cells. The experimental groups‚ testing the hypothesis‚ was inferred to show a constant number of immobile cells‚ after the 60-minute light treatment. Colchicine is a substance that reduces inflammation
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