a) Distance covered by the man b) Displacement of the man c) Time taken by the man in reaching from A to B. 2. A car starting from rest moves with a uniform acceleration of 0.1 m/s2 for 2 minutes. Find the speed acquired by the car. 3. A ship is moving at a speed of 56 km/h. One second later it is moving at 58 km/h. What is its acceleration? 4. A child completes a circular track of 200 m length in 10 seconds. Calculate a) speed‚ b) velocity. 5. A car travels 10 m in 5 seconds‚ 20 m in next 10 seconds
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measured for various initial angles‚ and also calculated by applying the theory for motion with constant acceleration. For further background information‚ refer to the sections in your textbook on projectile motion and motion with constant acceleration. THEORY For a given initial velocity‚ v0 ‚ and initial position‚ s0 ‚the position of a particle‚ s‚ as a function of time‚ undergoing constant acceleration‚ a is given by sr = sr 0 + vr 0 t + 12 ar t 2 ( 1 ) This is a vector equation and can be broken up
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masses of the pulleys and the effect of friction in the pulleys‚ determine: (a) the acceleration of each block‚ (b) the tension in each cable. -3- Problem (3) The motion of an oscillating flywheel is defined by the relation: 0 e7 t / 6 sin 4 t‚ where θ is expressed in radians and t in seconds. Knowing that θo= 0.4 rad‚ determine‚ the angular coordinate‚ the angular velocity‚ and the angular acceleration of the flywheel when; (a) t = 0.125 s‚ (b) t = ∞. -4- Problem (4) When the power
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the position vector is a function of time. Velocity & Acceleration • Velocity is defined as the change in position over a change in time; thus the average velocity is and the instantaneous velocity is • For motion in one dimension the velocity is the slope of the position line plotted versus time. • The same logic is used in deriving the average and instantaneous acceleration resulting in: • Jerk is defined as the rate of change of acceleration: Example 1 • A body starts from rest at x=0. ax(t)=2t-4
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of this lab is to show how to calculate the average speed and acceleration in six different races. In order to find average speed you will need to use the formula s=d/t (s= speed‚ d=distance‚ t=time). On the other hand‚ for accelaration you will use the formula a= vf-vi/t (a=acceleration‚ vf=final velocity‚ vi= initial velocity‚ t=time). Average speed is how fast something is moving; the path distanced moved per time. Acceleration is the rate of which velocity is changing‚ the change may be
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IMU Inertial Measurement Unit Help you measure tilt angle and angular velocity… Topics We’ll cover today… • • • • • • • • What is an IMU... ? Few Examples and Videos Accelerometer Gyrometer Magnetometer Filters Euler Angles Demos By:- Vivek Kumar Vipul Gupta (viveks@) (vipgupta@) Abhishek sharma (abhishr@) So... Lets Start... • What is an IMU...? • • • • • • • Few Examples and Videos Accelerometer Gyrometer Magnetometer Filters Euler Angles Demos Why do we need IMU
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| We found the average by using the formula (Trial 1 +Trial 2 + Trial 3)/3‚ and example would be (0.4663+0.454+0.4664)/3 = (1.3867)/3 = 0.4622 seconds. Graphs - The graphs (stapled on the back) all display that the ball moves at a constant acceleration. 4 book x-t graph: P= 32.38cm/s2 (t) + 6.012cm 7 book v-t graph: V= 52.19cm/s2 (t) + 54.74s 7 book x-t graph: P= 55.09cm/s2 (t) + 4.948cm 4 book v-t graph: The position vs. time graphs’ (x-t) slopes represent velocity. Obviously‚ 7 books
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object moving with a constant acceleration can certainly slowdown‚ But can an object ever come to a permanent halt if its acceleration truly remains constant? Explain. -An object can never come to a complete stop if its acceleration remains constant because even if the velocity reaches zero‚ it will just continue‚ probably in the opposite direction #2 An airliner reaches its take off speed of 334 m/s from rest in 35.2 s. What is the magnitude of its average acceleration? -D=vt D=334m/s(35.2s)
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Unit 1 HW 16.2: Acceleration 2 Name: Date: Period: UNIT I Acceleration 2 The problem v vs t graph Solution 1. A poorly tuned Yugo can accelerate from rest to a speed of 28 m/s in 20 s. a) What is the average acceleration of the car? b) What distance does it travel in this time? a = (28-0m/s)/20s = 1.4 m/s/s x = 1/2at2 = ½(1.4)(20)2= 280m 2. At t = 0 a car has a speed of 30 m/s. After 6 s‚ its speed is 15 m/s. What is its average acceleration during this time interval
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Constant Acceleration‚ Velocity and Displacement On A Downward Ramp 3/3/2014 Purpose: To determine the velocity and acceleration of an object at different positions going down a ramp at four different angles. Hypothesis: If an object is accelerating at different angles then the larger angles will always have the largest acceleration. Materials: Ramp Miniature car Ticker Machine Masking tape Ticker tape Carbon paper Power supply Ruler Procedure: 1. A ramp
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