Stoichiometry • Calculations involving quantities of consumed reactants and formed products based on a BALANCED chemical equation. Mass Molar Mass Mole Coeff Bal Eqn Mole Molar Mass Mass Example 2 • The Haber Process involves reacting gaseous nitrogen and gaseous hydrogen to form ammonia. Determine the mass in grams of hydrogen gas required to form 1.00 x 103 g ammonia. Your Turn 2 • If you react 52.9 g of potassium chlorate (KClO3) with excess phosphorus
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Chemistry 101 General Chemistry Fall 2013 –Syllabus S. Bakshandeh Office Hours: MW‚ 12:00–12:35 pm & T; 1:40-2:15 pm Room 92032 and/or Lab 92011. Email: sbakshandeh@yahoo.com – The best way to reach me is by email. Please indicate your full name and section number in the “Subject/Re” box. I will not open emails without proper identification. Blurb: Welcome to your first course in college chemistry. In this course‚ we will be exploring laws‚ theories‚ and principles of chemistry as related
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Q. 1. During the electrolysis of molten lead bromide‚ which of the following takes place : A : Bromine is released at the cathode. B: Lead is deposited at the anode. C : Bromine ions gain electrons. D: Lead is deposited at the cathode. Ans : - D. Q. 2. Here is an electrode reaction : Cu → Cu2+ + 2e-. [i.e. Cu- 2e- →Cu2+]. At which electrode(anode or cathode) would such a reaction take place. Is this an example of oxidation or reduction. Ans : - At anode. Oxidation. Q. 3. A solution contains
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Isotopes and average atomic mass Isotope: element variations with different atomic mass but same atomic number Isotopic Abundance: the relative amount in which each isotope of an element Calculating: given 2 isotopes of an element [B: 10.01u] [B: 11.01u] 1) Given average atomic mass: 10.81u If given percentages‚ you can find average atomic mass by adding each portion 2) Set variables for unknown values Let x represent % abundance for 10/5 B Let 1-x represent % abundance for 11/5 B Calculate:
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1. (a) The diagram below represents the industrial fractional distillation of crude oil. (i) Identify fraction A. (ii) What property of the fractions allows them to be separated in the column? (2) (b) A gas oil fraction from the distillation of crude oil contains hydrocarbons in the C15 to C19 range. These hydrocarbons can be cracked by strong heating. (i) Write the molecular formula for the alkane with 19 carbon atoms. (ii) Name the type of reaction involved in cracking. (iii) Write
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Scuba diving is a form of underwater diving in which a diver uses a scuba set to breathe underwater. According to the Professional Association of Diving Instructor (PADI)‚ a “DEEP DIVE” is considered to be anything from 18 meters (60 ft) to 30 meters (100 ft). A scuba diver moves around underwater by using swim-fins attached to the feet‚ however external propulsion can be provided by a diver propulsion vehicle. Scuba diving may be performed for a number of reasons; either for recreational purposes
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CELL STRUCTURE CELL THEORY: Structural and functional unit of all living things New cells arise from already existing cells Cells contain information that instructs growth. This information can be passed onto new cells. MICROSCOPES: There are two main types of microscopes: Light and Electron Electron Micrographs- shown in colour LIGHT ELECTRON Uses beam of light Magnification = x1500 Resolution = 200 nm Wide range of specimens can be used Samples are fairly quick + easy to prepare
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Term Final Exam Preparation (Note: This document includes practice examples from chapters covered only after the mid term. Your term final exam will be a comprehensive one and will include all chapters both before and after mid term exam.) FIN 300 Review: Basic Capital Budgeting Ch. 14: Calculating WACC Calculating the growth rate of dividends Ch. 15: Value of a right (including flotation) Dilution (three types) IPO underpricing (Winner’s Curse) Ch. 16: Indifference EBIT
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Module 4: 10. Strong Bases: NaOH‚ KOH‚ Na2CO3‚ NaHCO3‚ Na3PO4‚ NaHPO4‚ Strong Acids: Fe(NO3)3‚ HCL‚ HNO3‚ Al(NO3)3‚ NiCl2‚ H2SO4 11. Acidic Neutral Basic NaCl KNO3 NaOH HC2H3O2 Na2CO3 NaC2H3O2 NaHCO3 Fe(NO3)3 NaNO3 Na3PO4 HCl MgSO4 KOH HNO3 Na2SO4 NaHPO4 CuSO4 NaNO2 CoCl2 Al(NO3)3 NiCl2 H2SO4 KCl NH4Cl 12. CuSO4 CuCO3.Cu(OH)2(s) + 2 H2SO4(aq) ----> 2 CuSO4(aq) + CO2(g) + 3 H2O(l) Na3PO4 Na3PO4 (aq) + 3H2O (l) --> H3PO4 (aq) + 3NaOH
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Experiment 9 : The effect of substrate concentration on enzyme activity Objective To find out the relationship between the substrate concentration and the rate of reaction by determining the number of bubbles produce Hydrogen peroxide (H2O2) is a by-product of biochemical metabolism. An accumulation of hydrogen peroxide can be deadly‚ so it has to be decomposed. One of the decomposing factors is an enzyme called Catalase. Catalase breaks hydrogen peroxide into water and oxygen. The chemical
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