"Chemistry current event" Essays and Research Papers

Sort By:
Satisfactory Essays
Good Essays
Better Essays
Powerful Essays
Best Essays
Page 19 of 50 - About 500 Essays
  • Good Essays

    chemistry

    • 1127 Words
    • 5 Pages

    12U Equilibrium Unit Test Multiple Choice K/U Identify the letter of the choice that best completes the statement or answers the question. ____ 1. When solid lead(II) phosphate is in equilibrium with its ions‚ the ratio of lead(II) ions to phosphate ions is which of the following? a. 1:1 d. 2:3 b. 1:2 e. 3:2 c. 2:1 ____ 2. In a saturated solution of silver phosphate‚ the concentration of silver ion is 4.5  10-4 mol/L. The Ksp of silver phosphate would be which of the following

    Premium PH Ammonia Acid dissociation constant

    • 1127 Words
    • 5 Pages
    Good Essays
  • Good Essays

    Chemistry

    • 637 Words
    • 3 Pages

    Explain the effects of the Purges? Introduction The Great Purge was a campaign of political repression in the Soviet Union orchestrated by Joseph Stalin from 1934 to 1939. It involved a large-scale purge of the Communist Party and government officials‚ repression of peasants and the Red Army leadership‚ and widespread police surveillance‚ suspicion of "saboteurs"‚ imprisonment‚ and arbitrary executions. 1st Para Scientists‚ Doctors and Engineers‚ were heavily targeted‚ imprisoned and killed.

    Premium Soviet Union Great Purge Joseph Stalin

    • 637 Words
    • 3 Pages
    Good Essays
  • Good Essays

    chemistry

    • 670 Words
    • 3 Pages

    Abstract By adding HCl to 2-methyl-2-butanol‚ through the Sn1 mechanism‚ 2-chloro-2-methylbutane is formed. Water‚ sodium bicarbonate and NaCl(aq) were then added to the 2-chloro-2-methylbutane to remove any of the excess water from the reaction. To confirm‚ a successful reaction‚ AgNO3 was added to the 2-chloro-2-methylbutane. A white precipitate formation confirmed a successful Sn1 reaction. Introduction Nucleophilic substitution reactions such as Sn1 and Sn2 allow us to convert one functional

    Premium Alcohol Functional group Chemical reaction

    • 670 Words
    • 3 Pages
    Good Essays
  • Good Essays

    Chemistry

    • 1812 Words
    • 8 Pages

    Absorbance of Light vs. Concentration of Colored Solution Introduction: Performing this lab showed the importance of light in virtual drug screening because light can be used in a variety of ways to obtain different kinds of information in research. Light can be used to determine the concentration of DNA or protein in solution‚ tag different objects such as cells‚ protein structures‚ or bacteria in order to determine whether there is a large amount of a certain substance‚ and to determine the size

    Premium Concentration Chemistry Light

    • 1812 Words
    • 8 Pages
    Good Essays
  • Good Essays

    Chemistry

    • 3313 Words
    • 14 Pages

    Data-based questions Study the photos below and answer the following questions. Photo A Photo B Photo C (a) What are industries shown in photos A‚ B and C respectively? (3 marks) (b) Draw a diagram to illustrate the manufacturing system of the industry shown in photo A. (4 marks) (c) Describe and explain the characteristics of these three industries. (i) Photo A (3 marks) (ii) Photo B (3 marks) (iii) Photo C (in tradition) (3 marks) (d) How do personal factors affect

    Premium Iron Steel Iron ore

    • 3313 Words
    • 14 Pages
    Good Essays
  • Satisfactory Essays

    Chemistry

    • 337 Words
    • 2 Pages

    Reactions of some Hydrocarbons Equipment Required: -4 Test tubes -Dropper - Cyclohexane (C6H12) (3ml) - Cyclohexene (C6H10) (3ml) - Toluene (CH3C6H5) (3ml) - Potassium Permanganate solution (KMnO4) .01 mol L-1 (4ml) - Sulfuric Acid (H2SO4) 2mol L-1 (2ml) - Bromine Water (Br2) (5ml) Procedure: Reaction of hydrocarbons with acidified permanganate: 1) Into three separate‚ labeled test tubes place 1 ml of cyclohexane‚ cyclohexene and toluene respectively. 2) In a separate test

    Premium Potassium permanganate Acid Bromine

    • 337 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    Chemistry

    • 356 Words
    • 2 Pages

    Separation of a Mixture of Solids PURPOSE: The purpose of this lab is to familiarize ourselves with the techniques associated with separating a mixture of different solids. We will learn how the unique properties of substances can aid in this process and help us distinguish each pure substance from one another. DATA OBSERVATIONS CALCULATIONS CONCLUSION/DISCUSSION QUESTIONS A. How did your proposed Procedures or flow charts at the beginning of this experiment compare to the actual Procedures

    Free Mixture Separation process Chemistry

    • 356 Words
    • 2 Pages
    Good Essays
  • Powerful Essays

    Chemistry

    • 1354 Words
    • 6 Pages

    Calculations 1. Rounding Examples *0.1356 (4 significant figures) -> Round answer to 2 significant figures *0.1356 -> 0.14 *314.705 (6 significant figures) -> Round number to 4 significant figures. *314.705 -> 314.7 *0.0035771 (5 significant figures) -> Round to 3 significant figures. *0.0035771 -> 0.00358 *500‚000 (1 significant figure) -> Write this number to have 3 significant figures. *500‚000 - 5.00 x 10^5 *39.501 -> Round to 2 significant figures. *39‚501

    Premium

    • 1354 Words
    • 6 Pages
    Powerful Essays
  • Good Essays

    chemistry

    • 344 Words
    • 2 Pages

    of the Upper Nepean Catchment. The following is a summary of factors that affect water quality. Water may contain several ions‚ namely anions and cations which are toxic to humans. Hardness is the scum on water surface from significant concentrations of calcium and magnesium ions. Total dissolved solids is the measure of dissolved solids that are ionic in water. Turbidity is the presence of suspended solids in water which reduces penetration of light‚ resulting in a decrease concentration of

    Premium Water Water pollution Ammonia

    • 344 Words
    • 2 Pages
    Good Essays
  • Satisfactory Essays

    chemistry

    • 604 Words
    • 3 Pages

    CHE 242 Tutorial 3: Problems & Answers Week 4: Feb 2- 6‚ 2009 1. Consider a gas that occupies 1.00 dm3 at a pressure of 2.00 bar. If the gas is compressed isothermally at constant external pressure‚ Pext‚ so that the final volume is 0.500 dm3‚ what is the smallest value Pext can have? Calculate the work involved using this value of Pext. Solution For compression to occur‚ the value of Pext must be at least as large as the final pressure of the gas. P1 = 2.00 bar‚ V1 = 1.00 dm3‚ V2 = 0.500

    Premium Ideal gas law Gas

    • 604 Words
    • 3 Pages
    Satisfactory Essays
Page 1 16 17 18 19 20 21 22 23 50