work out the isotonic point of the potato cell sap. Prediction I have looked at my scientific knowledge from the background theory I carried out and I will base my prediction upon this information. In this experiment‚ I expect the different concentrations to show fairly noticeable effects on the lengths and masses of the potatoes‚ with the water diffusing into the potatoes at a high rate in the sucrose solution and therefore making their size bigger than at the start. As the distilled water solutions
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across a membrane because You correctly answered: d. they are lipid insoluble or they are too large. 2. Which of the following is true of facilitated diffusion? Your answer : b. Movement is active and against a concentration gradient. Correct answer: c. Movement is passive and down a concentration gradient. 3. Examples of solutes that might require facilitated diffusion include Your answer : a. glucose. Correct answer: d. all of the above. 4. Which of the following would not affect the rate of facilitated
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cells in distilled water should be 0‚ while at 1mol solution‚ all of the relevant cells should be plasmolysed. This is so‚ because plasmolisys occurs due to loss of water through osmosis‚ which depends on the concentration difference‚ and consists in the movement from a high to a low concentration gradient. This suggests that on a high molarity‚ the amount of water present outside the cell is lower than inside the cell‚ therefore it will move out of the cell‚ causing a loss of water. There are also other
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Diffusion is the passive movement of molecules from an area of higher concentration to areas of lower concentration (Martini & Nath‚ 89). Osmosis is a special kind of diffusion where water moves through a selectively permeable membrane (a membrane that only allows certain molecules to diffuse though) (Martini & Nath 90). Diffusion or osmosis takes place until a balance has been reached. This is the point where the concentrations in both areas are equal and no net movement will occur from one area
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Aim: To observe and describe an example of osmosis. Hypothesis: I predict that the water level will rise as the iodine stained water moves through the cellulose bag due to osmosis. The iodine is there so we can see this happening. Materials: * Dialysis(cellulose) tubing * Thistle funnel * Gas jar * Retort clamp and stand * Rubber bands * 50mL beaker * Iodine/potassium iodine solution * 5% starch solution Method: 1) Fill the gas jar to 3 quarters full with
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they would perish. Duckweeds are those types of plants that require fertilizers for the development of their roots‚ and Phosphorus fertilizers are the ones who have this ability. On the other hand‚ Nitrates or Nitrogen fertilizers in an excessive concentration would give an excessive amount of proteins to the duckweeds which would not be needed by them and hence concentrated nitrogen won ’t be that helpful for their growth. Tap Water would also be a good fertilizer for the duckweeds since it contains
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Lack of bioequivalence between disulfiram formulations Exemplified by a tablet/effervescent tablet study Andersen‚ M. P. Lack of bioequivalence between disulfiram formulations. Acta Psychiatr Scand 1992: 86: 31-35. M. P. Andersen Pharmacokinetic Laboratory AIS Dumex (Dumex Ltd.)‚ DK-2300 Copenhagen Abstract - A comparison of the bioavailability of disulfiram (DSF) after administration of non-effervescent Antabusea tablets (CP Pharmaceuticals‚ UK) and Antabuse@effervescent tablets Antabus@(A/S
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What amount of amylase is the best to produce a better reaction with starch? A 1% solution of amylase‚ made from 0.15g of amylase added to 15ml of water‚ a 2% solution of amylase made of 0.3g of amylase added to 15ml of water‚ and a 0.5% solution of amylase made of 0.75g of amylase to 15ml of water were created. A 0.25% starch solution was also created‚ and 3ml was added to each of the 4 test tubes. 1 drop of iodine was added to each test tube. 4ml of the 1% solution was added to the first test
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new egg volume. Finally the egg was submerged in water for 1-24hrs‚ again the volume was measured and recorded. I then compared the three volume measurements and provided observation. The next experiment was to determine the effects of salt concentration on bacterial growth. The tubes of broth were labeled as directed and
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the passage of materials into and out of the cell. Cell membranes are ‘semi-permeable’ which means that some substances can easily pass through them‚ whereas others cannot. Materials move by simple diffusion from high concentration on one side of the membrane to a lower concentration on the other side. Water is the most abundant and one of the most important substances in cells. The diffusion of water across a membrane is called osmosis. Water will diffuse
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