prepare a Beer’s law plot. Molarity of these samples was also calculated to determine concentration and percent error rate. Students also analyzed the concentration of blue dye #1 to determine the concentration of blue dye #1 in a commercial blue dye drink. Procedure Exercise #1 Step #1: Convert %T (Table 1) to absorbance and prepare a Beer’s law plot using the data. Step #2: Determine the concentration of M of the samples in table 2: A=ebc A= 2-log(%t) B= 1.0 cm Solve for E E=1875
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flexible‚ and Core A was not flexible and stiff. Core A was the most non-adjustable due to it being hypertonic which means that the total concentration of all the dissolved solute particles is greater than the other solution. Core B was isotonic meaning that it had an equal balance throughout. When two environments are isotonic it means that the total molar concentration of dissolved solutes is the same in both of them (equal). When cells are in an isotonic solution‚ movement of water out of the cell is
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that shows a relationship between concentration and absorbance of a solution. A standard curve was experimentally created in this experiment using 10mL solutions of phenol red with concentrations 10µM‚ 7.5 µM‚ 5.0 µM and 2.5 µM then the absorbance of each sample was measured using a spectrophotometer. This generated curve with resulting average absorbances of 1.273nm‚ 1.0275nm‚ 0.585nm‚ 0.285nm and 0.124nm provided a means to determine the phenol red concentrations of two unknown samples after experimentally
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UNITS OF CONCENTRATION There are a number of different ways of expressing solute concentration that are commonly used. Some of these are listed below. Molarity‚ M = moles solute/liter of solution Normality‚ N = equivalents of solute/liter of solution Weight %‚ Wt % = (mass of solute/mass of solution) x 100% Parts per million‚ ppm = (mass of solute/mass of solution) x 106 Mass per volume‚ mg/L = mass of solute/liter of solution molality‚ m = moles of solute/mass of solvent mole fraction‚ χ = moles
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dilutions on the same chemical in order to change its concentration. The diluted solution from a serial dilution can be used to calculate the concentration of the actual solution. In experimental work‚ often we need to obtain a range of concentrations for a specific compound. Thus‚ instead of preparing one large dilution‚ if we take a concentrated sample of a particular compound and perform a series of dilutions with it‚ we can obtain various concentrations of the same compound. In the context of this experiment
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changes to the phenomenon of osmosis. Method: We soaked several discs of potato cuted using a cork borer with around 1 centimeter of diameter and 2 milimeters of lenght into sucrose solutions with a different range of concentrations from 0 to 1.0M. Then we weighed all the potato cylinders on an electronic balance (see results) and recorded the results. We placed enough pieces of potato to cover the bottom of the petri dish and left them for 60 minutes. After this time we
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TOPIC: Food Tests – Semi Quantitative Test AIM: To determine the concentration of glucose present in an unknown sample‚ using a semi quantitative glucose test APPARATUS AND MATERIALS: 4% stock solution of glucose‚ water‚ 6 test tubes‚ ruler‚ water bath‚ solution of unknown concentration (Sample A)‚ Benedict’s reagent METHOD: 1. Solutions of different concentration were made from the stock solution and placed in test tubes.
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08.2013 TITLE: Transport across membrane OBJECTIVES: To investigate the effect of concentration of blackcurrant squash on osmosis in chipped potatoes. INTRODUCTION: In biology‚ osmosis is defined as the diffusion of solvent molecules (usually water molecules) across a semi-permeable membrane from a region of lower solute concentration to a region of higher solute concentration. Osmosis is of great importance in biological processes where
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purpose of this experiment is what happens when a solid substance‚ a metal carbonate is added slowly to a solution of an acid. We are finding methods of determining acid concentration. For us to balance certain equations‚ we will use a stoichiometry. For this experiment‚ we will need to set up the ratio and finding the concentration of HCI. Procedure: • Grab 4 different beakers. • Add a small amount of sodium carbonate onto a weighted beaker. • For each beaker pour 10 mL‚ 15 mL‚ 20 mL‚ and 30 mL of
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an area of high-level water concentration‚ that is‚ a dilute solution‚ to an area of low-level water concentration‚ that is‚ a strong solution through a semi-permeable membrane. (Passmyexams.co.uk‚ 2015) Actually‚ water moves in a bi-directional manner with the aim of leveling up the concentration. However‚ a high number of water molecules move from the fresh water towards the salty water. The outcome is a net transfer of molecules down the concentration gradient. Finally‚ the water
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