potential‚ the basis of osmosis. The experiment proved how water molecules in a solution are able to move from an area of low solute concentration‚ high water concentration‚ to an area of high solute concentration‚ low water concentration‚ diffusing “down” the water gradient. The movement of solutes from the area of high concentration to the area of lower concentration that surrounds them will be tested to hopefully demonstrate the accuracy of osmosis‚ as determined by the water potential equation
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Abstract Literature on Van’t Hoff’s law states that water potentials and zero weight change osmolalities will be the same for potato cores placed in varying concentrations of solutes of NaCl‚ glucose‚ and sucrose. This experiment was designed to test these predictions and compare them to data gathered course wide. We found that the mean water potentials were all within 0.26 bars of each other‚ and that the zero weight change osmolalities were all within 0.035 mols of each other. This supported Van’t
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II. Objectives a. To determine the wavelength with maximum absorbance of chromium (VI) specie. b. To calculate the molar absorptivity of the different concentrations of potassium dichromate by applying the Beer’s Law. c. To apply the external calibration method in determing an unknown concentration of potassium dichromate solution. III. Procedure NOTE: Remember to set the OA or 100% T every time the wavelength setting is changed using the blank solution. Also
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medium and the concentration of the mixture. The principle of calorimetry is the discipline or act of calculating changes in limits of chemical reactions‚ physical changes‚ and phase transitions for the intention descending the heat or heat transfer connected to those changes. The purpose of the experiment is to determine the concentration of an unknown using Beer’s Law‚ also to determine the concentration of blue dye #1 using visual colorimetry and the concentration of blue dye #1
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Osmosis in Potato Cells Interpretation My results show what I predicted would happen. My prediction was that as the concentration of sucrose increased the amount of water moving in or out of the potato would change. A low concentration of sucrose solution would make the potato increase in length and mass (become turgid). A high concentration of sucrose solution would make the potato shrink (plasmolysed) We can see this occurred‚ as at 0.1mol of sucrose solution the potato’s size increased by an
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rinse with water‚ then with the solution‚ and then we fill it up and test. We tested for the wavelength standard 5 at which there was maximum absorption. At this wavelength‚ we tested the absorbance of all the standards. Table 1: Volumes and Concentrations of Standards and Analysis Standard in ml | | | 0.002M FeCl3 | 0.2M KSCN | 0.1 M HCl | 0 | 5 | 5 | 1 | 5 | 4 | 2 | 5 | 3 | 3 | 5 | 2 | 4 | 5 | 1 | 5 | 5 | 0 | Analysis in ml | | | 0.002M FeCl3 | 0.2M KSCN |
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increasing concentration of sucrose in solution. The results seen in the water control as well as possibly the 0.2M sucrose occur because the water potential outside of the potatoes would be higher thus encouraging water to move into the potatoes and increase their mass. In other words‚ osmosis (diffusion of water from high to low concentration across a membrane) occurred and moved water from the environment hypotonic to the carrot into the carrot itself in an attempt to equalize concentration between
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An investigation to find the water potential of potato and carrot tubers in a sucrose solution‚ of concentration 0.00 – 0.50Mol‚ over a 24 hour period Interpretation Written Communication C1 From our graph it can be seen that the concentration of sucrose solution is 0.18 M at 0% change in mass for the potato and 0.355 M at 0% change in mass for the carrot. I will use these values to find the solute potential by using the calibration graph. I will work out the water potential by using the
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Convert %T to absorbance and prepare a Beer’s Law plot using this data. Concentration of Various Samples Sample Identification Code Concentration of M (mol/L) %T A = 2 - log(%T) Q5000 4.00 x 10-4 17.9 Q5001 3.20 x 10-4 25.0 Q5002 2.40 x 10-4 35.7 Q5003 1.60 x 10-4 50.2 Q5004 8.000 x 10-5 70.8 Questions from Procedures 3. What is the concentration of M in these samples? Concentration of M Sample Identification Code %T A = 2 - log(%T) A M Q021015-01 43
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LabMr.P/Pd. 63/17/14 Osmosis and Diffusion Lab Osmosis is a process where molecules pass through a semi permeable membrane from a less concentrated solution into a more concentrated one‚ equalizing the concentrations on each side of the membrane. Diffusion is the spreading of something more widely.During the osmosis and diffusion lab I tested what happens to a fresh egg when osmosis and diffusion across membranes. The eggs were placed in vinegar‚ distilled water‚ and then lastly syrup. The
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