How does the chemical being burned affect the color of fire? Why do you think each fire burns a different color? The colors of the flames are are due to the different chemicals and substances. The bright yellow-orange of most wood fueled flames is because of the sodium‚ and when it’s heated‚ it emits the glow of the fire. The blue in some wood-fueled flames is because of the carbon and hydrogen emit a blue and purple aura. How are the colors produced by a chemical when it burns related to the atomic
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aldehydes are known as aldoses. Sugars that are ketones are known as ketoses.Glucose and galactose are example of aldoses while fructose is an example of ketoses.There are few test can be done for testing these sugar to show or prove are they reducing sugar or non reducing sugar.Example of the test that can be done is Benedict test. 1 In plant‚glucose is stored as the polysaccharide starch.Example of food that rich in starch is oat‚cereal‚rice and corn.Starch can be divided into
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1. | A master budget is typically prepared for: A. | A period of one year. | B. | Top management only. | C. | Strategic planning purposes only. | D. | Strategic business units only. | E. | Operating activities only. | | | | 2. | A plan of dollar amounts to be spent on long-term projects is called a: A. | Cash budget. | B. | Capital budget. | C. | Rolling budget. | D. | Sales budget. | E. | Rolling financial forecast. | | | | 3. | Budgeting provides
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> # Ho’s Maple Lab Test Solution: Semester 1 2012 (1) # Question 1; > evalf(100*sin(95)‚38); 68.326171473612098369957981656827095404 > # Queston 2; > f:=x->3*sin(1/4*x^4)-sin(3/4*x)^4; (2) > # Find 1st derivative; > D(f); (3) > # Find turning/stationary point in the interval [1‚2]‚ 1st derivative expression = 0‚ 10 significant figures!; > evalf(fsolve(3*cos((1/4)*x^4)*x^3-3*sin((3/4)*x)^3*cos((3/4)*x)= 0‚x=1..2)‚10); 1.562756908 (4) > # Find 2nd derivative at x= 1.562756908; 10 significant
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condition (listed from left to right in the table) ranged from: 19.6-59.2%‚ 11.8-76.0%‚ 25.0-92.3%‚ and 12.5-89.8%‚ respectively. From this‚ we can generally see how the data from each group is spread out across each ligation condition. Table 2. ANOVA test results. The p-value corresponding to the F-statistic is lower than 0.05‚ suggesting that one or more treatments are significantly different. We can see that the treatments that are significantly different are the 1:1 with stuffer and 2:1 without stuffer
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The Urea test was used to test both Unknown Gram-positive and Unknown Gram-negative bacteria. One colony of bacteria was used from the Unknown 13A plate and Unknown 13B plate in order to inoculate the Urea Slant. After the slant was inoculated‚ the cultures were placed in an incubator at 35ºC for Gram-positive bacteria‚ and 37ºC for Gram-negative bacteria for a total of 48 hours. If the Urea test were positive‚ the color of the slant would have changed to a hot pink color‚ which indicated the bacteria’s
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element tensile test is conducted for element size of 5mm at strain rates mentioned in Fig. 7 7. The true stress versus plastic strain results of the simulation in comparison to the load curve is shown in Fig. 7 9. As the damage is coupled to the stress tensor by Eq. 4 1‚ there is a continuous reduction of stress. The plastic strain at failure for different strain rates is shown in Fig. 7 11 which is in accordance to the scaling factor given for different strain rates. One element tensile test is also conducted
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What is urodynamic testing? Urodynamic tests are done to determine how well your lower urinary tract is working. The lower urinary tract includes your bladder and the tube that empties your bladder (urethra). When your kidneys filter your blood‚ urine is stored in your bladder until you feel the urge to pass urine (urinate). Urination requires coordination between the nerves and muscles of your bladder and urethra. When your lower urinary tract is working well‚ you should be able to: Start urinating
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The catalase test is used to differentiate staphylococci (catalase-positive) from streptococci (catalase-negative). The enzyme‚ catalase‚ protects the bacteria from the toxic by-products of oxygen metabolism. This enzyme is produced by bacteria that respires using oxygen. The catalase-positive bacteria include strict aerobes. Catalase-negative bacteria may be anaerobes‚ or they may be facultative anaerobes do not respire using oxygen as a terminal electron acceptor. The test reaction is very fast
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4/27/2014 IRCTC Ltd‚Booked Ticket Printing IRCTCs e-Ticketing Service Electronic Reservation Slip (Personal User) This ticket will only be valid along with an ID proof in original. If found travelling without ID Proof‚will be treated as without ticket and charged as per extant Railway rules. Valid IDs to be presented during train journey by one of the passenger booked on an e-ticket :- Voter Identity Card / Passport / PAN Card / Driving License / Photo ID card issued by Central/State
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