Question 1) 1) Discuss puzzles and anomalies 2) Discuss three forms of market efficiency Marketefficiency is a measure of the availability(to all participants ina market) of the information that provides maximum opportunities tobuyers and sellers to effect transactions with minimum transactioncosts. Types of Efficiency: Operational efficiency: It refers to thecost to buyers and sellers of transactions in securities on theexchange. This may be promoted by creating as much competitionbetween
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30 minutes appointments. Some of the patients take more or less than 30 minutes depending upon the type of dental work to be done. The following table shows the various categories of work‚ their probabilities and the time actually needed to complete the work category Time required in mins Probability Filling Crowning Cleaning Extraction Checkup 45 60 15 45 15 0.25 0.15 0.25 0.10 0.25 Simulate the dentist’s clinic for about four hours and determine the average waiting time for
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Homework 4.3 #21 43% of adults in the US receive fewer than 5 phone calls a day. In a random sample of 7 adults‚ what is the probability that the number receiving fewer than five calls a day is (a) exactly 3 (b) at least 3 (c) more than 3? n p 7 0.43 x P(Exactly x) P(At most x) P(At least x) 0 0.0195 0.0195 1.0000 1 0.1032 0.1228 0.9805 2 0.2336 0.3564 0.8772 3 0.2937 0.6502 0.6436 4 0.2216 0.8718 0.3498 5 0.1003 0.9721 0.1282 6 0.0252 0.9973 0.0279 7 0.0027 1.0000 0.0027
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BUS216 Exam #2 Review – Discrete Distributions 1. The number of calls coming into a PBX has a mean of 120 calls per hour. What is the probability of no calls in a one-minute interval? .1353 2. A school is sending 18 children to a camp. If 15% of the children in the school are first graders‚ and the 18 children are selected at random from among all 6 grades at the school‚ find the mean and variance of the number of first graders chosen? The mean is 2.7‚ and the variance is 2.3. n
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(BNN) and Naïve Bayes (NB). Bayes data mining technique are a fundamentally important technique. Bayes theorem finds the event occurring probability given the probability of another already occurred event. Bayes Rule is applied for calculating the posterior from the prior and the likelihood‚ due to the later two is generally easier to be generated from a probability model. Statistics provide a strong fundamental background to quantify and evaluate the results. However‚ algorithms based on statistics
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Waiting Line Models The Structure of a Waiting Line System Queuing Systems Queuing System Input Characteristics Queuing System Operating Characteristics Analytical Formulas Single-Channel Waiting Line Model with Poisson Arrivals and Exponential Service Times Multiple-Channel Waiting Line Model with Poisson Arrivals and Exponential Service Times Economic Analysis of Waiting Lines Slide 1 Structure of a Waiting Line System Queuing theory is the study
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• To represent actual decision-making under conditions of uncertainty for evaluating alternative courses of action based upon facts and assumptions. MONTE CARLO TECHNIQUE STEPS: 1. Setting up a probability distribution for variables to be analyzed. 2. Building a cumulative probability distribution for each random variable. 3. Generate random numbers . 4. Conduct the simulation experiment by means of random sampling 5. Repeat step 4 until the required number of simulation runs has
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year. (a) Find the mean waiting time between accidents. (b) Find the standard deviation of the waiting times between accidents. (c) Find the probability that more than one year elapses between accidents. (d) Find the probability that less than one month elapses between accidents. (e) If no accidents have occurred within the last six months‚ what is the probability that an accident will occur within the next year? Question 4: [20 points] If T is a continuous random
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ticket‚ d2 0 0 Payoff Table a.) A realistic estimate of the chances of winning is 1 in 250‚000. approach to recommend a decision. Use the expected value Answer: Given: Realistic estimate of the probability of winning: 0.000004 (1/250‚000) Realistic estimate of the probability of losing : 0.999996 (1- 0.000004) Thus‚ the expected values for the two decision alternatives are: EV(d1) = 0.000004(300‚000) + 0.999996(-2) = 1.2 + (-1.999992) = -0.799992 EV(d2) = 0.000004(0) + 0.999996(0)
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Page 1 of 3 ASSIGNMENT 2ND SEMESTER : STATISTICAL ANALYSIS (STAT) STUDY UNITS COVERED DUE DATE TOTAL MARKS : CHAPTERS 1 - 8 : 3.00 p.m. 17 AUGUST 2010 : 100 INSTRUCTIONS TO CANDIDATES FOR COMPLETING AND SUBMITTING ASSIGNMENTS The complete ‘Instructions to Students for Completing and Submitting Assignments’ must be collected from any IMM GSM office‚ the relevant Student Support Centre or can be downloaded from the IMM GSM website. It is essential that the complete instructions be studied prior
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