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    Lab Report

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    Potatoes Lab #1 Purpose: To find the molarity/concentration of potato cytoplasm. Materials: As on page 1 in the lab handout. Procedure: As on page 1 in the lab handout. Data and Observations: Test Tube # | Concentration of sucrose solution (mol/L) | Initial Mass (g) | Final Mass | Percentage change in mass | 1 | 1.0 mol/L | 3.00g | 2.25g | -25.0% | 2 | 0.9 mol/L | 2.70g | 2.07g | -23.3% | 3 | 0.8 mol/L | 2.92g | 2.25g | -22.9% | 4 | 0.7 mol/L | 2.60g | 1.94g | -25.4% | 5

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    TABLE OF CONTENTS What is a Mixture? What are the types of Mixtures? Define:-solutions -suspensions -colloids (Draw and compare.) Methods of separation 1. Filtration 2. Distillation (simple and fractional) 3. Paper chromatography 4. Solvent extraction 5. Separating funnel 6. Evaporation 7. Crystallization 8. Sublimation Draw and explain each. What is a mixture??? A mixture is a combination of two or more substances that are not chemically

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    You can separate solutions into two categories‚ colligative properties and non-Colligative properties. Colligative properties are different from non-colligative properties because they focus on the dissolved particles‚ not the solute itself. Non-colligative properties depend on the specification of the dissolved particles and the solvent. Colligative properties are properties that depend on the dissolved solutes in the solution. There are four main colligative properties; vapor pressure‚ freezing

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    concentration of salt (NaCl) affect the mass of a potato soaked in water (H2O) with different concentrations of NaCl over the course of 30 minutes? Hypothesis: It is expected that the solution with the highest concentration of salt will cause more mass loss to the pieces of potato. The pieces that will be placed in the solution with the lowest concentration of salt will have small weight loss. Finally‚ the pieces that will be placed in water (NaCl concentration 0) will gain weight. This is expected because

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    osmosis and diffusion is that they both equalize the concentration of the two solutions into a membrane. Osmosis and diffusion both work together to move water molecules from an area of high concentration to an area of low concentration. The

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    compound. Introduction The solubility product constant‚ Ksp‚ is a particular type of equilibrium constant. The equilibrium is formed when an ionic solid dissolves in water to form a saturated solution. The equilibrium exists between the aqueous ions and the undissolved solid. A saturated solution contains the maximum concentration of ions of the substance that can dissolve at the solution’s temperature. The equilibrium equation showing the ionic solid lead chloride dissolving in water is:

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    the properties unique to solutions depend only on the number of dissolved particles and not their identity. Such properties are called colligative properties. The colligative property that will be examined in this experiment will be the freezing point depression as an example of a colligative property. Every liquid has a freezing point: the temperature at which a liquid undergoes a phase change from liquid to solid. When solutes are added to a liquid‚ forming a solution‚ the solute molecules disrupt

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    being the highest point with a change of mass of 1.75% finishing with the 10% solution on a decline of -12.28%. From observing the scatter plot the data points were not far from the line of best fit‚ indicating the results were hardly affected by random errors. Resulting in fairly precise and reliable results. The hypothesis stated ‘As the concentration of sodium chloride increases the mass of the potato in the solution will decrease.’ This was supported as with the increase of sodium chloride concentration

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    Week 1: Chemical Analysis

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    Write down the ionic chemical equation when the following pairs of solutions are mixed together. (Take note of their solubilities of the products formed) Question 1. riz Remember that all ionic compounds are soluble to an extent; those classied

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    Freezing Point Depression

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    kg 0.29367OsmkgH2O=0.226gM*9.876*10-3kg solvent 0.29367OsmkgH2O=22.88 gM*kgH2O M=22.880.29367 M=77.91gmol Based on the molar mass of calculated‚ the identity of the unknown substance D is Glycine. 2) Finding the concentration of a known solution Table 1.2: Table used for the preparation of the calibration curve used to find the concentration of alcohol in a wine. 0.2mL of each sample were taken and placed in the Osometer. Ethanol sample (g EtOH/100mL) | Osmolality (mOsm/kg H2O) | 5

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