Volume of sphere πr3 Volume of cone πr2h Surface area of sphere = 4πr2 Curved surface area of cone = πrl In any triangle ABC The Quadratic Equation The solutions of ax2+ bx + c = 0 where a ≠ 0‚ are given by x = Sine Rule Cosine Rule a2 = b2+ c2– 2bc cos A Area of triangle = ab sin C Answer
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(D) 1.1‚ 11 The sides AB‚ BC‚ CA of a right angled triangle are 17‚ 15‚ 8 respectively; the value of tan A. sec B is equal to 8 17 15 17 (A) (B) (C) (D) 17 8 17 15 11. 12. tan is not defined when (A) 0o (B) is equal to /4 (C) /6 (D) /2 13. If the diameter of the circle is increased by 200 percent its area is increased by (A) 100% (B) 200% (C) 300% (D) 800% If the area of an equilateral triangle is 64 3 cm2‚ then the side of the triangle is (A) 12 cm (B) 14 cm (C) 16 cm (D) 18 cm In the given
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this answer booklet. 8360/2 Mark Formulae Sheet Volume of sphere = 4 3 r 3 r Surface area of sphere = 4r 2 Volume of cone = 1 2 r h 3 Curved surface area of cone = r l l h r In any triangle ABC C 1 Area of triangle = ab sin C 2 Sine rule a b c = = sin A sin B sin C 2 2 a b A c B 2 Cosine rule a = b + c – 2bc cos A cos A = b2 c2 a2 2bc The Quadratic Equation The solutions of ax 2 + bx + c = 0‚ where
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Geometry Final Exam Review #1 Semester 2 Name:________________________ Hour:_______ GEOMETRY SEMESTER 2 FINAL REVIEW #1 1. The ratio of the side lengths of ΔOMN to ΔHGI is 4:3. Find x and y. 2. Find f. 3. The triangles are similar. Which choice below is NOT a correct statement? (A) B F (B) ΔBAC~ΔFDE BA FE (C) BC FD AC BC (D) DE FE (E) A D 4. Which of the following statements is not true? (A) ΔABC ~ ΔEDC by SAS~ (B) ΔABC ~ ΔEDC by AA~ (C) ΔABC ~ ΔEDC by SSS~ (D) ΔCDE ~ ΔCBA by SAS~
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Answers Chapter 1 c i No x-intercept‚ y = 4 iii y Pre-test 1 a 2x + 1 1 3 c x+ x= x 2 2 f 3x − 7 b 5(x − 1) 1 (x + 4) 3 -5ab -21x -4x + 4 3 ii 0 y=4 d 2x − 3 e a a a a 7x 8y 3x + 3 4m b b b b 6a 7 6 b 7 12 9 a 3 b -2 c 1 10 a y = 2x + 1 b y = -x + 5 c 4 7 d 19 72 Exercise 1A f 21 20 2 3 4 5 4 e 7 c c c c -5x 2 15a 2 -10x + 2x 2 a (0‚ 4) d g c 10 ii
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Research Question: How has the Ancient Greek Philosopher Pythagoras impacted our modern day perception of knowledge‚ being and conduct in Mathematics? Introduction: The Civilization of Ancient Greece has played a vital role in how our modern world functions. Located on the Balkan Peninsula with the Aegean Sea on its East‚ the Mediterranean Sea to its South and the Ionian Sea to its West. The Ancient Greeks have helped us to understand topics ranging from art‚ astronomy‚ mathematics and philosophy
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questions Real-life money questions Generate a sequence from the nth term Substitution Alternate angles Angle sum of a triangle Properties of special triangles Finding angles of regular polygons Area of circle Circumference of circle Area of compound shapes Rotations Reflections Enlargements Translations Find the mid-point of a line Measuring and drawing angles Drawing triangles Plans and elevations Nets Symmetries Questionnaires and data collection Two-way tables Pie charts Scatter graphs Frequency
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z=2(cos(5π/6) + i sin(5π/6)) Apply De Moivre’s Theorem‚ z-10 = (√3 – i)-10 =2-10 (cos(10*5π/6) + i sin(10*5π/6)) = ...... And‚ I think you should be able to get the answer for (√3 – i)-10. 19. Sketch triangle and find other five ratios of θ. sin θ = 3/5 Step 1‚ we sketch a right triangle to specify the angle θ. Step 2‚ since we are given sin θ = 3/5‚ mark the opposite and hypotenuse as the graph below. Step 3‚ find out the missing length by using Pathagorean Theorem. 32 + adjacent2
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Mathematics Quiz 11 (CH11 Applications in Trigonometry) Name:_____________ Class: 5___ Class No: ___ Marks: ____ / ____ Answer all questions Section A (1 mark each) 2011-CE-MATH 2 Q24 1. The figure shows a prism ABCDEF with a right-angled triangle as the cross-section. The angle between BE and the plane ABCD is A. ABE. B. CBE. C. DBE. D. EBF. 2011-CE-MATH 2 Q50 2. In the figure‚ ABCDEFGH is a cuboid. If FHG = x‚ BFG = y and HBG = z‚ then tan z = A. tan x tan y. B. . C. . D
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perimeter of the Classic/Variation Snowflakes to find the total area and perimeter of the final snowflake for each. For both the Classic and Variation Koch Snowflake‚ an equilateral triangle is used to start. We will be using basic arithmetic based on what we know about triangles to find the perimeter and area of the starting triangle. The information gathered here is crucial in our implementation of a sequence for finding the perimeter of the first five/final
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