lab project Introduction: In this project we have created a device which takes input of 220 volts of ALTERNATING SOURCE and it gives us out put of 5 volts of DIRECT CURRENT for this purpose we have used various electronic components as mentioned below and made its circuit on PCB we have learned the concept of RECTIFICATION in this project. Components used: Following are the components used in this project: 1. Transformer (step down 220 v). 2. 4 Semiconductor diodes. 3. Capacitor. 4. Regulator
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a chiral molecule‚ meaning that two mirror-image forms (called enantiomers) are possible. In the diagram‚ the wavy line represents a molecular bond that is bent "upward" for so-called (R)-ibuprofen and "downward" for (S)-ibuprofen. In the human body‚ only (S)-ibuprofen is active‚ but an enzyme readily converts (R)-ibuprofen to the active (S)-ibuprofen form. (P.R. Cullis) This is a representation as configurational isomers but only one isomer is effective
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I. SYSTEM FLOWCHART AND ER-DIAGRAM GENERATION TOOL Name of the tool: SMARTDRAW URL: This Software can be downloaded from: http://www.smartdraw.com. This is a paid software‚ but a 30-day free trial for learning can be downloaded. Requirements to use the tool: PC running Windows 95‚ 98 or NT. The latest versions of Internet Explorer or Netscape Navigator‚ and about 20MB of free space. What the tool does: Smartdraw is a perfect suite for drawing all kinds of diagrams and charts: Flowcharts‚ Organizational
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have any possibility of finishing early. Management Finding: Finding 1: Using the estimated times collected by the project team‚ the preliminary information for activities with duration times and predecessors can be seen in the Activity-on-Node (AON) model that
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flowcharts for the assignment above by typing into the textboxes below. Control Flow Diagram—Main Control [pic] Control Flow Diagram—Display Menu | | |[pic] | Control Flow Diagram—Get_Int_Value |
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Name: _______________________ IB DP Biology: Ecology Test – Paper 1 40 Points 45 Minutes 1.Which phylum does the plant below belong to? A.AngiospermophytaB.BryophytaC.ConiferophytaD.Filicinophyta2.What is a community composed of? A.Habitats B.Populations C.Abiotic factors D.Biotic and abiotic factors 3.Which of the following is the best definition of a population? A.A group of individuals that can interbreed and produce fertile offspring B.The number of individuals of the same species
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Lambir Hill National Park Case Study This report is going to show you CDUT Department of Geology have a visit to the University of Malaya‚ Department of Geology. This report contains three parts; Part 1 will assess the important of objectives both for organization and project. Part 2 will evaluate the rationale for project planning and produce Scope‚ Work Breakdown Structure (WBS)‚ Schedule‚ Costing‚ Stakeholder analysis and related communication plan and Risk evaluation. Part 3 will assess why
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radio waves d) long wave length Radio waves 3. In a heat engine the linear motion of the Piston is converted into rotation by the component a) Spart plug b) Carburetor c) Crank Shaft d) Fuel injection pump 4. An Engineer wants to design an engine to convert 800 KJ of heat into 840KJ of useful mechanical work. The correct statement related to the above engine is that it a) Is less efficient b) Is more efficient c) Cannot be designed d) Is 100% efficient 5. An astrophysics observes that Galaxy “A” is more
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jain and Raja Ayyanar. This paper provided a comprehensive analysis of PWM control of dual active bridge. Some of the basics in that are given below :- When both the sides are IGBT’s and there is no lag between the switching off of S1 and switching on of S2 and the same for all other IGBT’s then we get the voltage waveform as one in the above diagram. The power transfer equation is given as We can control the flow of power by simple controlling the phase shift () i.e. by simply
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However in example 6‚ the H2O molecule given in the question is in the liquid state. Thus liquid water has to be converted into steam first. To convert 2 moles of liquid water into 2 moles of steam‚ an additional 82 kJ of energy is required. By using Hess’s Law‚ ΔH + 2(799) + 2(41) + 4(460) = 4(410) + (496) ΔH = -888 kJ mol-1 Alternative: energy absorbed during bond breaking = 4(410) + 2(496) = 2632 kJ energy released during bond forming = 2(799) + 4(460) + 2(41)
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