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    attempt to study the position of equilibrium. Furthermore‚ after the completion of this experiment‚ the formation of the equilibrium constant of the iron thiocyanate complex could be determined. In order to accomplish these tasks‚ five different solutions were made. Upon completion of the experiment‚ the results of the aforementioned experiments were calculated to an average of the final formation constant of 183. Introduction: The experiment for the Spectrophotometric Determination of Equilibrium

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    INTRODUCTION This experiment outlines the techniques necessary to determine the equilibrium constant for the formation of an iron(III) thiocyanate complex ion (FeSCN2+) from Fe3+ and SCN- . The quantitative preparation of several solutions and subsequent measurement of the solution absorbance using a spectrophotometer are the techniques that will be used in this experiment. The absorbance measurement gives the concentration of FeSCN2+. The concentrations of Fe3+ and SCN- are obtained as the difference

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    the temperature of water increases‚ the particles of solid Potassium chloride‚ KCl‚ which are absorbing energy from its surrounding‚ start moving more easily between the solution and its solid state because. According to the second law of thermodynamics‚ the particles will shift to the more disordered‚ more highly dispersed solution state. I predict that as the temperature of a KCl and water mixture increases‚ then the solubility of the KCl will also increase. Variables Dependant variable

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    of plant cells. Water always moves from an area of high to low water potential.  2. When the two solutions on either sides of the membrane are equal and no net movement is detected‚ the solutions are isotonic. This means that the solutions have the same concentration of solutes. If two solutions differ in the concentration of solutes that each has‚ the one with more solute is hypertonic. The solution that has less solute is hypotonic. 3. This experiment was performed to measure the osmosis of small

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    do cells gain or lose water? Did water move into the cell or out of the cell while it was surrounded by hypotonic solution? The water moved into the cell‚ because there was less water inside the cell than outside (there were fewer water molecules inside). 2. In which direction did the water move though the cell membrane when the cell was surrounded by the hypertonic solution? The water moved out of the cell because there was a higher concentration of water inside the cell than outside (there

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    hot and cool slides? If so‚ explain. - DISPERSION SYSTEMS IN PROTOPLASM 4. DEFINE THE FF: a. Solute: The dissolve matter in a solution; The component of a solution that changes its state b. Solvent: A liquid substance capable of dissolving other substances c. Mixture: a substance consisting of two or more substance mixed together d. Solution: A homogeneous mixture of two or more substances e. Emulsion: a colloid in which both phases are liquids f. Suspension: a mixture in

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    animal and plant cells are placed in a solution‚ the movement of water is effected by the solute concentration of the solution. If animal and plant cells are placed in a more concentrated solution‚ the solution becomes hypertonic to the cells‚ causing water to exit the cells. This changes the appearance of the cells‚ causing the cells to look darker (more concentrated) and shriveled up. Null Hypothesis: When animal and plant cells are placed in a solution‚ the movement of water is not effected by

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    flow through the membrane‚ this allows osmosis to happen to cells in certain solutions. Osmosis can affect the cell in three different types of ways. The cell can become hypertonic‚meaning the concentration

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    OSMOSIS LAB BACKGROUND INFORMATION. Dialysis tubing is being used to model a plasma membrane. Isotonic solutions are solutions that have the same concentration of solutes on both sides of the membrane. Hypertonic solutions are solutions that have more solute to the one with less solute. Hypotonic solution are solutions that have less solute to the one with more solute. RESEARCH QUESTION:which dialysis tubing will gain the distilled water and which one will loss its content

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    of Vanillin. Stock solution of vanillin in water with concentration of 50 ppm was prepared. Four solutions with concentration of 5 ppm‚ 1 ppm‚ 0.5 ppm and 0.1 ppm were made from stock solution. UV-Vis spectra of standard solution was recorded at 229 nm and equal to 0.544 AU. Vanillin was separated on SPE cartridges using a 50% methanol and 50% water as eluting solvent. UV-Vis of blank‚ 1 ppm and 0.1 ppm vanillin sample was obtained at 0.078 AU and 0.014 AU. 5 ppm solution of amlodipine besylate

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